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\(=\frac{6\left(1\cdot5+2\cdot10\cdot2+4\cdot20\cdot4+9\cdot45\cdot9\right)}{3\left(1\cdot5+2\cdot2\cdot10+4\cdot4\cdot20+9\cdot9\cdot45\right)}=\frac{6}{3}=2\)
S=\(\frac{1.5.6+2.10.12+4.20.24+9.45.54}{1.3.5+2.6.10+4.12.20+9.27.45}\)=\(\frac{1.5.6+1.5.6.8+1.5.6.64+1.5.6.729}{1.3.5+1.3.5.8+1.3.5.64+1.3.5.729}\)
S=\(\frac{1.5.6.\left(8+64+729\right)}{1,3,5,\left(8+64+729\right)}\)=\(\frac{30}{15}\)=2
Duyệt mình đi nhé các bạn
chỗ mà 1,3,5 là 1.3.5 đó mình nhấn nhầm mong các bạn thông cảm
\(A=\frac{1.5.6+2^3.1.5.6+4^3.1.5.6+9^3.1.5.6}{1.3.5+2^3.1.3.5+4^3.1.3.5+9^3.1.3.5}=\frac{1.5.6.\left(1+2^3+4^3+9^3\right)}{1.3.5.\left(1+2^3+4^3+9^3\right)}=2\)
\(\frac{1.5.6+2.10.12+4.20.24+9.45.54}{1.3.5+2.6.10+4.12.20+9.27.45}\)=\(\frac{1.5.6+\left(1.5.6\right)2+\left(1.5.6\right)4+\left(1.5.6\right)9}{1.3.5+\left(1.3.5\right)2+\left(1.3.5\right)4+\left(1.3.5\right)9}\)
=\(\frac{\left(1.5.6\right)\left(1+2+4+9\right)}{\left(1.3.5\right)+\left(1+2+4+9\right)}=\frac{1.5.6}{1.3.5}=\frac{6}{3}=2\)
\(\frac{1.5.6+2.10.12+4.20.24+9.45.54}{1.3.5+2.6.10+4.12.20+9.27.45}=\frac{1.5.6+\left(1.5.6\right)2+\left(1.5.6\right)4+\left(1.5.6\right)9}{1.3.5+\left(1.3.5\right)2+\left(1.3.5\right)4+\left(1.3.5\right)9}=\)
\(\frac{\left(1.5.6\right)\left(1+2+4+9\right)}{\left(1.3.5\right)\left(1+2+4+9\right)}=\frac{1.5.6}{1.3.5}=\frac{6}{3}=2\)
\(A=\frac{1\cdot5\cdot6+2\cdot10\cdot12+4\cdot20\cdot24+9\cdot45\cdot54}{1\cdot3\cdot5+2\cdot6\cdot10+4\cdot12\cdot20+9\cdot27\cdot45}\)
\(A=\frac{1\cdot5\cdot6\cdot\left(1+2+4+9\right)}{1\cdot3\cdot5\cdot\left(1+2+4+9\right)}\)
\(A=\frac{1\cdot5\cdot6}{1\cdot3\cdot5}\)
\(A=2\)
Tính bằng cách hợp lý nhất: A=\(\frac{1.5.6+2.10.12+4.20.24+9.45.54}{1.3.5+2.6.10+4.12.20+9.27.45}\)
A = \(\frac{1.5.6+2^3.\left(1.5.6\right)+2^6.\left(1.5.6\right)+9.\left(1.5.6\right)}{1.3.5+2^3.\left(1.3.5\right)+2^6.\left(1.3.5\right)+9.\left(1.3.5\right)}=\frac{1.5.6.\left(1+2^3+2^6+9\right)}{1.3.5.\left(1+2^3+2^6+9\right)}=2\)
\(\text{Giải :}\)
\(\text{A = }\frac{1.5.6+2^3.\left(1.5.6\right)+2^6.\left(1.5.6\right)+9.\left(1.5.6\right)}{1.3.5+2^3.\left(1.3.5\right)+2^6.\left(1.3.5\right)+9.\left(1.3.5\right)}\)
\(\Rightarrow\text{A = }\frac{1.5.6.\left(1+2^3+2^6+9\right)}{1.3.5.\left(1+2^3+2^6+9\right)}=2\)
\(\text{Vậy A = 2}\)
\(\text{~~Học tốt~~}\)
Từ đề bài, ta có:
\(A=\frac{1.5.6\left(2^3+4^3+9^3\right)}{1.3.5\left(2^3+4^3+9^3\right)}=\frac{1.5.6}{1.3.5}=2\)
Thế này thì đúng rồi, sai sao được :)))
Chúc bạn học tốt!
VÌ MỖI TÍCH TƯƠNG ỨNG TRÊN TỬ SỐ THÌ GẤP 2 LẦN TÍCH Ở MẪU :1.5.6=2.(1.3.5) NÊN TA NHÓM 2 RA
ĐỀ: MK HƠI LƯỜI BN VIẾT ĐỀ RA ĐÂY NHA
\(Â\)\(=\)\(\frac{2.\left(1.5.3+2.10.6+4.20.12+9.45.27\right)}{1.3.5+2.6.10+4.12.20+9.27.45}\)
\(Â\)\(=\)\(2\)
A=\(\frac{1.5.6+8\left(1.5.6\right)+64\left(1.5.6\right)+...+729\left(1.5.6\right)}{1.3.5+8\left(1.3.5\right)+64\left(1.3.5\right)+...+729\left(1.3.5\right)}\)
=\(\frac{\left(1.5.6\right)\left(1+8+64+...+729\right)}{\left(1.3.5\right)\left(1+8+64+...+729\right)}\)
=\(\frac{1.5.6}{1.3.5}\)
=2
\(\frac{1.5.6+2.10.12+4.20.24+9.45.54}{1.3.5+2.6.10+4.12.20+9.27.45}\)
= \(\frac{1.5.6.\left(1.1.1+2.2.2+4.4.4+9.9.9\right)}{1.3.5.\left(1.1.1+2.2.2+4.4.4+9.9.9\right)}\)
= \(\frac{1.5.6}{1.3.5}\)
= 2
\(\frac{1.5.6+2.10.12+4.20.24+9.45.54}{1.3.5+2.6.10+4.12.20+9.27.45}\)
\(=\frac{1.3.5.2+2.6.10.2+4.12.20+9.45.27.2}{1.3.5+2.6.10+4.12.20+9.45.27}\)
\(=\frac{\left(1.3.5+2.6.10+4.12.20+9.45.27\right).2}{1.3.5+2.6.10+4.12.20+9.45.27}\)
\(=2\)