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a ) 32.( - 64 ) - 64.68
= - 64 x ( 32 + 68 )
= -64 x 100
= -6400
b ) - 54.76 + 12 (.-76) - 76.(-34)
= 76 x ( - 54 + -34 + 12 )
= 76 x (-76 )
= (-5776)
c ) 19 - 42.(-19) + 38 x 5
= 42 x ( 19 + - 19 ) + 38 x 5
= 42 x 0 + 38 x 5
= 0 + 38 x 5
= 38 x 5
= 190
=)
a) 32 . ( -64 ) - 64 . 68
= ( 32 + 68 ) . ( - 64 )
= 100 . ( - 64 )
= ( - 6400 )
b) ( - 54 ) . 76 + 12 . ( - 76 ) - 76 . ( - 34 )
= 76 x ( -54 + -34 + 12 )
= 76 x ( - 76 )
= ( - 5776 )
c) 19 - 42 . ( -19 ) + 38 . 5
= 42 . ( 19 + -19 ) + 190
= 42 . 0 + 190
= 0 + 190
= 190
a) (-54).76 + 12.(-76) - 76.(-34)
= (-54).76 + (-12).76 - 76.(-34)
= 76. [(-54) + (-12) - (-34)]
= 76. (-32)
= -2432
a) 1135.(-24)+(-24).(-135)
= ( - 24 ) . ( 1135 + -135 )
= -24 . 1000
= -24000
b) - 54.38+12.(-54)-50.(-54)
= - 54 . ( 38 + 12 - 50 )
= -54 . 0
= 0
c) 19-42.(-19)+38.5
= 19 - (- 789 ) + 280
= 808 + 280
= 1088
a)1135.(-24)+(-24).(-135)
=(-24).[1135+(-135)]
=(-24).1000
=-24000
b)-54.38+12.(-54)-50.(-54)
=(-54).(38+12-50)
=(-54).0
=0
c)19-42.(-19)+38.5
=19.[1-(-42]+38.5
=19.43+190
=817+190
=1007
a: \(=-57\cdot75+57\cdot36-75\cdot36+75\cdot57\)
\(=36\left(57-75\right)=-18\cdot36=-648\)
b: \(=19+19\cdot42+19\cdot10\)
\(=19\cdot62=1178\)
a: =-64(32+68)=64x100=-6400
b: =76(-54-12+36)=76x(-30)=-2380
c: =19x50+38x5=950+190=1140
\(C=\dfrac{2}{3\cdot5}+\dfrac{3}{5\cdot8}+\dfrac{11}{8\cdot19}+\dfrac{13}{19\cdot32}+\dfrac{25}{32\cdot57}+\dfrac{30}{57\cdot87}\)\(C=\left(\dfrac{5-3}{3\cdot5}\right)+\left(\dfrac{8-5}{5\cdot8}\right)+\left(\dfrac{19-8}{8\cdot19}\right)+\left(\dfrac{32-19}{19\cdot32}\right)+\left(\dfrac{57-32}{32\cdot57}\right)+\left(\dfrac{87-57}{57\cdot87}\right)\)\(C=\left(\dfrac{1}{3}-\dfrac{1}{5}\right)+\left(\dfrac{1}{5}-\dfrac{1}{8}\right)+\left(\dfrac{1}{8}-\dfrac{1}{19}\right)+\left(\dfrac{1}{19}-\dfrac{1}{32}\right)+\left(\dfrac{1}{32}-\dfrac{1}{57}\right)+\left(\dfrac{1}{57}+\dfrac{1}{87}\right)\)\(C=\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{19}+\dfrac{1}{19}-\dfrac{1}{32}+\dfrac{1}{32}-\dfrac{1}{57}+\dfrac{1}{57}-\dfrac{1}{87}\)\(C=\dfrac{1}{3}-\dfrac{1}{87}=\dfrac{28}{87}\)
B3:
a. =-1250000
b. =-20000
c. =0
d. =-24000
B4:
a. =-4100
b. =-2700
c. =400
d. =1007
\(8.19 – 42.(- 19) + 38.5\)
\(=19.(8+42+10)=1140\)
8.19–42.(−19)+38.58.19–42.(−19)+38.5
=19.(8+42+10)=1140