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![](https://rs.olm.vn/images/avt/0.png?1311)
A=sin^2 70°+sin^2 80°+sin^2 10°+sin^2 20°
\(=\sin^270^o+sin^280^o+sin^210^o+sin^220^o.\)
Nhập zô máy tính như sau:
\(=Sin\left(70\right)^2+Sin\left(80\right)^2+Sin\left(10\right)^2+Sin\left(20\right)^2\)
\(=2\)
Nếu bn ko đc dùng máy tính thì dùng bảng cx đc nha
![](https://rs.olm.vn/images/avt/0.png?1311)
A = ( sin2 10o + sin2 80o) + (sin2 20o + sin2 70o) + ...+ (sin240o + sin2 50o)
A = ( sin2 10o + cos2 10o) + (sin2 20o + cos2 20o) + ...+ (sin240o + cos2 40o)
A = 1 + 1 + 1 + 1 = 4 ( Vì ( sin2 a + cos2 a = 1 với mọi a)
Bài làm
A = ( sin2 10o + sin2 80o) + (sin2 20o + sin2 70o) + ...+ (sin240o + sin2 50o)
A = ( sin2 10o + cos2 10o) + (sin2 20o + cos2 20o) + ...+ (sin240o + cos2 40o)
A = 1 + 1 + 1 + 1 = 4
hok tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\sin^210^o+\sin^220^o+\sin^230^o+\sin^240^o+\sin^250^o+\sin^260^o+\sin^270^o+\sin^280^o\)
\(=\cos^280^o+\cos^270^o+\cos^260^o+\cos^250^o+\sin^250^o+\sin^260^o+\sin^270^o+\sin^280^o\)
\(=\left(\sin^280^o+\cos^280^o\right)+\left(\sin^270^o+\cos^270^o\right)+\left(\sin^260^o+\cos^260^o\right)+\left(\sin^250^o+\cos^250^o\right)\)
\(=1+1+1+1\)
\(=4\)
Vậy ....
![](https://rs.olm.vn/images/avt/0.png?1311)
A=(sin210+sin280)+(sin220+sin70)+(sin230+sin260)+(sin240+sin250)
Lại có: sin80=cos10; sin70=cos20; sin60=cos30; sin50=cos40
=> sin280=cos210; sin270=cos220; sin260=cos230; sin250=cos240
=>A=(sin210+cos210)+(sin220+cos220)+(sin230+cos230)+(sin240+cos240)
=>A=1+1+1+1=4
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=sin^210^o+cos^220^o+sin^280^o+cos^270^o\)
\(A=\left(sin^210^o+sin^280^o\right)+\left(cos^220^o+cos^270^o\right)\)
\(A=0+0\)
\(A=0\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Lời giải:
Ta có: \(\cos a=\sin (90-a)\Rightarrow \cos ^2a=\sin ^2(90-a)\)
Do đó:
\(\cos ^210=\sin ^280\)
\(\cos ^220=\sin ^270\)
\(\cos ^230=\sin ^260\)
\(\cos ^240=\sin ^250\)
\(\Rightarrow \cos ^210+\cos ^220+..+\cos ^280=(\sin ^280+\cos ^280)+(\sin ^270+\cos ^270)+(\sin ^260+\cos ^260)+(\sin ^250+\cos ^250)\)
\(=1+1+1+1=4\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=sin^210+sin^280+sin^220+sin^270+...+sin^240+sin^250\)
\(=sin^210+sin^2\left(90-10\right)+...+sin^240+sin^2\left(90-40\right)\)
\(=sin^210+cos^210+sin^220+cos^220+...+sin^240+cos^240\)
\(=1+1+1+1=4\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=\cos^210^0+\cos^220^0+\sin^220^0+\sin^210^0\\ A=1+1=2\)
=10nha
vì 70-80=âm 10,âm 10+20=10