Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
( 6,7 + 5,66 - 3.7 +4,34 ).( -76,6 .1,2 +7,66 .12 )
= [( 6,7 -3,7 ) + ( 5,66 + 4,34 )].[ -7,66 . 12 + 7,66 . 12 )
= ( 3 + 10 ).[ 12 . ( -7,66 + 7,66 )]
= 13 . 0
= 0
\(\left(6,7-5,66-3,7+4,34\right)\cdot\left(-76,6\cdot1,2+7,66\cdot12\right)\)
\(=\left[\left(6,7-3,7\right)+\left(5,66+4,34\right)\right]\left[-7,66\cdot12+7,66\cdot12\right]=\left(3\cdot10\right)\cdot0=0\)
( 6,7 + 5,66 - 3,7 + 4,34 ).(-76,6 . 1,2 + 7,66 .12 )
=( 6,7 + 5,66 - 3,7 + 4,34 ).(-76,6 . 1,2 + 76,6 .1,2 )
=( 6,7 + 5,66 - 3,7 + 4,34 )..0=0
Vậy ( 6,7 + 5,66 - 3,7 + 4,34 ).(-76,6 . 1,2 + 7,66 .12 )=0
(6,7+5,66-3,7+4,34).(-76,6.1,2+7,66.12)
=(6,7-3,7+5,66+4,34).(-7,66.10.1,2+7,66.12)
=(4+10).(-7,66.12+7,66.12)
=14.0
=0
\(a.6,5+1,2+3,5-5,2+6,5-4,8
\)
\(=\left(6,5+3,5\right)+\left(1,2+6,5\right)-\left(5,2+4,8\right)\)
\(=10+7,7-10\)
\(=\left(10-10\right)+7,7\)
\(=0+7,7=7,7\)
a/ \(6,5+1,2+3,5-5,2+6,5-4,8\)
\(=\left(6,5+3,5+6,5\right)+1,2-\left(5,2+4,8\right)\)
\(=16,5+1,2-10\)
\(=17,7-10=7,7\)
b/ \(\left(-4,3.1,1+1,1.4,5\right):\left(-0,5:0,05+10,01\right)\)
\(=1,1\left(-4,3+4,5\right):\left(-10+10,01\right)\)
\(=1,1.0,2:0,01\)
\(=1,1.20=22\)
c/ \(\left(6,7+5,66-3,7+4,34\right).\left(-76,6.1,2+7,66.12\right)\)
\(=\left[\left(5,66+4,34\right)+\left(6,7-3,7\right)\right]\left[7,66.\left(-10\right).1,2+7,66.12\right]\)
\(=\left(10+3\right).\left[7,66\left(-12\right)+7,66.12\right]\)
\(=13.0=0\)
\(\text{6,5+ 1,2+3,5-5,2+6,5-4,8}=\left(6,5+3,5\right)+\left(-5,2-4,8\right)+\left(1,2+6,5\right)\)
=10-10+7,7=7,7
\(\text{(-4,3.1,1+1,1.4,5): (-0,5:0,05+10,01)}=\dfrac{1,1.\left(-4,3+4,5\right)}{-10+10,01}=\dfrac{0,22}{0,01}=22\)
\(\text{(6,7+5,66-3,7+4,34). (-76,6.1,2+7,66.12)}\)
=(6,7+5,66-3,7+4,34)(-76,6.1,2+76,6.1,2)=0
bài 2)
a)|12,1x+12,1.0,1|=12,1
<=> |12,1(x+0,1)|=12,1
<=>\(\left[\begin{array}{nghiempt}12,1\left(x+0,1\right)=12,1\\12,1\left(x+0,1\right)=-12,1\end{array}\right.\)
<=> \(\left[\begin{array}{nghiempt}x=0,9\\x=-1,1\end{array}\right.\)
b) |0,2x-3,1|+|0,2+3,1|=0
<=>|0,2x-3,1|+3,3=0
ta có |A|>=0
=> pt trên vô nghiệm
bài 1) a) 6,5+1,2+3,5-5,2+6,5-4,8
=(6,5+3,5+6,5)-(5,2-1,2+4,8)
=15,5-8,8=24,6
tt nha bạn
\(c,\left(6,7+5,66-3,7+4,34\right).\left(-76,6.1,2+7,66.12\right)\)
=\(\left(6,7+5,66-3,7+4,34\right).\left(-7,6.12+7,66.12\right)=0\)
a) \(6,5+1,2+3,5-5,2+6,5-4,8\)
\(=6,5+1,2+3,5+6,5-5,2-4,8\)
\(=\left(6,5+3,5+6,5\right)+1,2-\left(5,2+4,8\right)\)
\(=16,5+1,2-10\)
\(=17,7-10\)
\(=7,7.\)
b) \(\left(-4,3.1,1+1,1.4,5\right):\left(-0,5:0,05+10,01\right)\)
\(=\left\{1,1.\left[\left(-4,3\right)+4,5\right]\right\}:\left[\left(-10\right)+10,01\right]\)
\(=\left(1,1.0,2\right):0,01\)
\(=0,22:0,01\)
\(=22.\)
c) \(\left(6,7+5,66-3,7+4,34\right).\left(-76,6.1,2+7,66.12\right)\)
\(=\left[\left(5,66+4,34\right)+\left(6,7-3,7\right)\right].\left[7,66.\left(-10\right).1,2+7,66.12\right]\)
\(=\left[10+3\right].\left[7,66.\left(-12\right)+7,66.12\right]\)
\(=13.\left\{7,66.\left[\left(-12\right)+12\right]\right\}\)
\(=13.0\)
\(=0.\)
Chúc bạn học tốt!
Bài 1:
a: \(=\dfrac{\left(-4.3+1.1\cdot45\right)}{-10+10.01}=\dfrac{49.5-4.3}{0.01}=4520\)
c: \(=\left(3+10\right)\cdot\left[7.66\left(-10\cdot1.2+12\right)\right]\)
=0