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b)(1-3-5+7)+(9-11-13+15)+...+(2009-2011-2013+2015)
=0+0+...+0
=0
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\(\left|-34\right|+(-4)\cdot(-1)^{2008}+(17-19)^2\)
\(=34+4+(-2)^2\)
\(=34+4+4\)
\(=42\)
\((-31)\cdot81-18\cdot31-31\)
\(=31\cdot(-81)-18\cdot31-31\)
\(=31\cdot(-81)-18-1\)
\(=31\cdot(-100)=-3100\)
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( 175 + 52 + 13 ) - [ -15 + 175 - ( -25 )]
= ( 175 + 25 + 13 ) - ( -15 + 175 + 25 )
= 175 + 25 + 13 - 15 - 175 - 25
= -2
( 175 + 52 + 13 ) - [ -15 + 175 - ( -25 )]
= ( 175 + 25 + 13 ) - ( -15 + 175 + 25 )
= 175 + 25 + 13 - 15 - 175 - 25
= -2
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Bỏ dấu ngoặc rồi tính:
a) (123 - 27)+ (27+ 13-123) -= 123 - 27 + 27 + 13 - 123 = 13
b) (175 + 25 + 13)-(-15 + 175 + 25) = 175 + 25 + 13 + 15 - 175 - 25 = 28
c) (2012 - 119 + 29) - (-119 + 29) = 2012 - 119 + 29 + 119 - 29 = 20122
d) -(55 - 80 + 91) - (2012 + 80 - 91) = - 55 + 80 - 91 - 2012 - 80 + 91 = - 2067
e) 123 + [54 + (-123) + 46] = 123 + 54 - 123 + 46 = 100
f) - 64 + [(-110 + 64 + 71] = -64 -110 +64 + 71 = -39
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a) 2 + (-25) + 41+ (-2) + 25 +(-41)
= (-2 + 2) + (-25 + 25) + (-41 +41)
=0 + 0 + 0
=0
b) 10+ ( -17) +5 + (-7)+ 17 + (-15)
= (-15+10+5) + (-17+7) + 7
= 0 + 0 + 7
= 7
c)(-22) + (-14) + 17 + (-24) + 13+ 30
= [(-22) + (-14) + (-24)] + (17 + 13 + 30)
=-60 + 60
=0
a) 2 + (-25) + 41+ (-2) + 25 +(-41)
= (-2 + 2) + (-25 + 25) + (-41 +41)
=0 + 0 + 0
=0
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`Answer:`
a. \(-\frac{17}{30}-\frac{11}{-15}+-\frac{7}{12}\)
\(=-\frac{17}{30}+\frac{11}{15}-\frac{7}{12}\)
\(=-\frac{17}{30}+\frac{22}{30}-\frac{7}{12}\)
\(=\frac{1}{6}-\frac{7}{12}\)
\(=-\frac{5}{12}\)
b. \(-\frac{5}{9}+\frac{5}{9}:\left(\frac{5}{3}-\frac{25}{12}\right)\)
\(=-\frac{5}{9}+\frac{5}{9}:\left(-\frac{5}{12}\right)\)
\(=\frac{5}{9}.\left(-1\right)+\frac{5}{9}.\left(-\frac{12}{5}\right)\)
\(=\frac{5}{9}.\left(-1-\frac{12}{5}\right)\)
\(=\frac{5}{9}.\frac{-17}{5}\)
\(=-\frac{17}{9}\)
c. \(-\frac{7}{25}.\frac{11}{13}+-\frac{7}{25}-\frac{2}{13}-\frac{18}{25}\)
\(=\frac{77}{325}-\left(\frac{7}{25}+\frac{18}{25}\right)-\frac{2}{13}\)
\(=\frac{77}{325}-1-\frac{2}{13}\)
\(=-\frac{452}{325}\)