Question

[96neko]

tình nhanh

\(B=\dfrac{\left(\dfrac{1}{14}-\dfrac{\sqrt{2}}{7}+\dfrac{3\sqrt{2}}{35}\right).\left(-\dfrac{4}{15}\right)}{\left(\dfrac{1}{10}+\dfrac{3\sqrt{2}}{25}-\dfrac{\sqrt{2}}{5}\right).\dfrac{5}{7}}\)

Answer 1

[Nguyễn Lê Phước Thịnh]

\(B=\dfrac{\left(\dfrac{5}{70}-\dfrac{10\sqrt{2}}{70}+\dfrac{6\sqrt{2}}{70}\right)\cdot\dfrac{-4}{15}}{\left(\dfrac{5}{50}+\dfrac{6\sqrt{2}}{50}-\dfrac{10\sqrt{2}}{50}\right)\cdot\dfrac{5}{7}}=\dfrac{\dfrac{5-4\sqrt{2}}{70}\cdot\dfrac{-4}{15}}{\dfrac{5-4\sqrt{2}}{50}\cdot\dfrac{5}{7}}\)

\(=\dfrac{-4\left(5-4\sqrt{2}\right)}{70\cdot15}\cdot\dfrac{50\cdot7}{5\left(5-4\sqrt{2}\right)}=\dfrac{-4}{5}\cdot\dfrac{350}{70\cdot15}=\dfrac{-4}{5}\cdot\dfrac{1}{3}=\dfrac{-4}{15}\)