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\(A=\frac{1}{3}+\frac{1}{6}+...+\frac{1}{28}\)
\(A=\frac{2}{6}+\frac{2}{12}+...+\frac{2}{56}\)
\(A=\frac{2}{2.3}+\frac{2}{3.4}+...+\frac{2}{7.8}\)
\(A=2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{7}-\frac{1}{8}\right)\)
\(A=2\left(\frac{1}{2}-\frac{1}{8}\right)\)
\(A=2\frac{3}{8}=\frac{3}{4}\)
Ủng hộ mk nha !!! ^_^
\(A=\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+\frac{1}{28}\)
\(A=\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+\frac{2}{30}+\frac{2}{42}+\frac{2}{56}\) (Tử số và mẫu số mỗi phân số nhân với 2 thì giá trị ko thay đổi)
\(A=\frac{2}{2.3}+\frac{2}{3.4}+\frac{2}{4.5}+\frac{2}{5.6}+\frac{2}{6.7}+\frac{2}{7.8}\)
\(A:2=\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}\)
\(A:2=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}\)
\(A:2=\frac{1}{2}-\frac{1}{8}=\frac{3}{8}\)
\(A=\frac{3}{8}.2=\frac{3}{4}\)
\(A=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}\)
\(\Rightarrow A=\frac{1}{2}-\frac{1}{8}\)
\(\Rightarrow A=\frac{3}{8}\)
\(A=\left(\frac{1}{2}-\frac{1}{3}\right)+\left(\frac{1}{3}-\frac{1}{4}\right)+...+\left(\frac{1}{7}-\frac{1}{8}\right)\)
\(A=\frac{1}{2}-\frac{1}{8}\)
\(A=\frac{3}{8}\)
A)
0,92 × 324 + 0,92 × 678
= 0,92 × (324+678)
= 0,92 × 1002
= 0,92 × 1000 + 0,92 × 2
= 920 + 1,84
= 921,84
a)
\(A=\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}\)
\(\Rightarrow3A=1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}\)
\(\Rightarrow3A=1+1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+\frac{1}{8}-\frac{1}{16}+\frac{1}{16}-\frac{1}{32}\)
\(\Rightarrow3A=1+1-\frac{1}{32}\)
\(\Rightarrow3A=2-\frac{1}{32}\)
\(\Rightarrow A=\left(2-\frac{1}{32}\right):3=\frac{21}{32}\)
P/s : Đúng nha
a(a+a-1)=a(6+1)
a+a-1=6+1
2a-1=7
2a=7+1
2a=8
a=4
Vậy a=4