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(5 2/5x7 7/12)x(13 8/9:7 5/23)
=(27/5x91/12)x(125/9:166/23)
=819/20x2875/1494
=52325/664
\(\dfrac{12}{7}\times\dfrac{4}{13}+\dfrac{12}{14}\times\dfrac{14}{26}-\dfrac{6}{7}\times\dfrac{2}{13}\)
= \(\dfrac{6}{7}\times\dfrac{4\times2}{13}+\dfrac{6}{7}\times\dfrac{7}{13}-\dfrac{6}{7}\times\dfrac{2}{13}\)
= \(\dfrac{6}{7}\times\left(\dfrac{8}{13}+\dfrac{7}{13}-\dfrac{2}{13}\right)\)
= \(\dfrac{6}{7}\times1\) = \(\dfrac{6}{7}\)
\(\left(\frac{3}{5}+\frac{2}{5}\right)+\left(\frac{6}{11}+\frac{16}{11}\right)+\left(\frac{7}{13}+\frac{19}{13}\right)\)
= 1 + 2 + 2
= 5
\(=\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+\frac{1}{6\cdot7}\)
= \(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}\)
=\(1-\frac{1}{7}\)
=\(\frac{6}{7}\)
Đặt biểu thức trên là A
A=(1-3)+(2-4)+(5-7)+(6-8)+.....+(297-299)+(298-300)+301+302
A=301+302-(3-1)-(4-2)-(7-5)-(8-6)-......-(299-297)-(300-298)
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có 150 số hạng
A=301+302-(2+2+2+2+..........+2)
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50 số hạng
A=301+302-2x150=303
3/2+7/6+13/12+21/20+...+133/132
=1+ 1/2 + 1+ 1/6 + 1+ 1/12 + 1+ 1/20+......+ 1+ 1/132
=(1+ 1 + 1+.....+ 1) + ( 1/2+ 1/6+1/12+ 1/20+....+ 1/132)
= 11+ ( 1/1×2+ 1/2×3+1/3×4+1/4×5+.....+1/11×12)
=11+ ( 1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+......+1/11-1/12)
=11+(1-1/12)
= 11+11/12
=143/12
3/2+7/6+13/12+21/20+...+133/132 =1+ 1/2 + 1+ 1/6 + 1+ 1/12 + 1+ 1/20+......+ 1+ 1/132 =(1+ 1 + 1+.....+ 1) + ( 1/2+ 1/6+1/12+ 1/20+....+ 1/132) = 11+ ( 1/1×2+ 1/2×3+1/3×4+1/4×5+.....+1/11×12) =11+ ( 1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+......+1/11-1/12) =11+(1-1/12) = 11+11/12 =143/12
1+1+2+2+3+3+4+4+5+5+6+6+7+7+8+9+8+9+10+12+13+14+15+16+17+18+19+20+30+1000000=10000274
{(1999x2001-1)/(1998+1999x2000)}x7/5
={[(1999x(2000+1)-1]/(1998+1999x2000)}...
={(1999x2000+1999-1)/(1998+1999x2000)}...
={(1999x2000+1998)/(1998+1999x2000)}x7...
=1x7/5
=7/5
2/ 5 + 7/ 12 + 13 /12 = 2/ 5 + 20/ 12 = 2/ 5 + 5/ 3 = 6/ 15 + 25/ 15 = 31/ 15
\(=\dfrac{2}{5}+\left(\dfrac{7}{12}+\dfrac{13}{12}\right)\)
\(=\dfrac{2}{5}+\dfrac{5}{3}\)
\(=....\)