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bn ghi rõ đâu bài ra chứ mk ko bt câu nào là GTNN câu nào là GTLN đâu
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2^{101}.\left(-0,5\right)^{100}=2^{100}.2-\left(-0.5\right)^{100}\)\(=\left(2+0,5\right)^{100}.2\)\(=\left(2,5\right)^{100}.2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(S=\left(0,25\right)^2+\left(0,5\right)^2+...+\left(2,5\right)^2\)
\(\Rightarrow\frac{n\left(n+1\right)\left(2n+1\right)}{6}=\frac{2,5\left(2,5+1\right)\left(2,5.2+1\right)}{6}\)
\(\Rightarrow S=8,75\)
![](https://rs.olm.vn/images/avt/0.png?1311)
tìm giá trị của biểu thức sau
b)\(\left(0,25\right)^6.\left(-4\right)^6-\dfrac{72^2}{36^2}\)
\(=\left[0.25.\left(-4\right)\right]^4.\left(72:36\right)^2\)
\(=-1.4\)
\(=-4\)
c)\(9.\left(\dfrac{1}{3}\right)^3:\left[\left(-\dfrac{2}{3}+0.5-1\dfrac{1}{2}\right)\right]\)
\(=9.\dfrac{1}{27}:\left[\dfrac{-8}{27}+\dfrac{1}{2}-\dfrac{3}{2}\right]\)
=\(9.\dfrac{1}{27}:\left[\dfrac{-8}{27}+\left(-1\right)\right]\)
\(=9.\dfrac{1}{27}.\dfrac{-27}{35}\)
\(=\dfrac{3.3.1.9.\left(-3\right)}{-3.\left(-9\right).35}=\dfrac{-9}{35}\)
a. \(\left(0,25\right)^6.\left(-4\right)^6-\dfrac{72^2}{36^2}\)
\(=\left[0,24.\left(-4\right)\right]^6-\left(\dfrac{72}{36}\right)^2\)
\(=\left(-1\right)^6-2^2\)
\(=1-4=-3\)
b. \(9.\left(\dfrac{1}{3}\right)^3:\left[\left(\dfrac{-2}{3}\right)^3+0,5-1\dfrac{1}{2}\right]\)
\(=9.\dfrac{1}{27}:\left[\left(\dfrac{-8}{27}\right)+\dfrac{1}{2}-\dfrac{3}{2}\right]\)
\(=9.\dfrac{1}{27}:\dfrac{-35}{27}\)
\(=\dfrac{-9}{35}\)
M = \(-0,5^2-4\left|-0,75\right|\)
\(=-0,25-4\cdot0,75\)
\(=-0,25-3=-3,25\)
~Học tốt~