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\(a.\left(47\times27\right)\times\left(-13\right)+13\left(-53-27\right)\)
\(=1269\times\left(-1\right)\times13+13\left(-80\right)\)
\(=13\left(-1269\right)+13\left(-80\right)\)
\(=13\left[\left(-1269\right)+\left(-80\right)\right]\)
\(=13\left(-1349\right)\)
\(=-17537\)
\(b.-17\left(13+5\right)-13\left(-17-2\right)\)
\(=13\left(-17\right)+5\left(-17\right)-13\left(-17\right)+13.2\)
\(=0-85+26\)
\(=-59\)
a)29.(19-`13)-19.(29-13)
=29.6-19.16
=174-304
=-130
b) 27.75+25.75-150
=(27+25).75-150
=52.75-150
=3900-150
=3750
b,27.75+25.75-150=27.75+25.75-2.75=75.(27+25-2)=75.50=3750
a) ( -3 ) + ( 8 ) + ( -13 ) + 18 + ... + ( -53 ) + 58
= [ ( -3 ) + 8 ] + [ ( -13 ) + 18 ] + ... + [ ( -53 ) + 58 ] có 6 cặp
= 5 + 5 + ... + 5
= 5 x 6
= 30
b) ( -40 ) + ( -39 ) + ... + 33 + 34 + 35
= [ ( -35 ) + 35 ] + [ ( -34 ) + 34 ] + ... + [ ( -1 ) + 1 ] + 0 + ( -40 ) + ( -39 ) + ... + ( -36 )
= 0 + 0 + ... + 0 + 0 + ( -190 )
= -190
a)=85.27-85.56+85.56-85.37
=85.27-85.37-85.56+85.56
=85(27-37)+0
=85.(-10)=-850
b) Bạn làm tương tự nhé
( 43 − 13 ) . ( − 3 ) + 27. ( − 14 − 16 ) = 30. ( − 3 ) + 27. ( − 30 ) = ( − 30 ) .3 + 27. ( − 30 ) = ( − 30 ) . ( 3 + 27 ) = ( − 30 ) .30 = − 90
a. \(M=\left(\frac{12}{13}+\frac{21}{65}\right):\frac{81}{13}\)
\(M=\left(\frac{120}{130}+\frac{42}{130}\right).\frac{13}{81}\)
\(M=\frac{81}{65}.\frac{13}{81}\)
\(M=\frac{1}{5}\)
M=(12.107/13.107 + 21.10101/65.10101):27.3/13=(12/13 + 21/65):27.3/13
=[(12.5+21)/65]:27.3/13
=81/13.5 : 27.3/13 =81/(5.27.3)=1/5
Đs: M=1/5
(47.27).(-13)+13.(-53-27)
=1269.(-13)+13.(-80)
=1269.13.(-1)+13.(-80)
=(1269-80).13.(-1)
=1189.13.(-1)
=15487.(-1)
=-15487
\(\left(47\cdot27\right)\cdot\left(-13\right)+13\cdot\left(-53\cdot27\right)\)
\(=\left(-47\cdot27\right)\cdot13+13\cdot\left(-53\cdot27\right)\)
\(=13\left[\left(-47\cdot27\right)+\left(-53\cdot27\right)\right]\)
\(=13\left\{27\cdot\left[\left(-47\right)+\left(-53\right)\right]\right\}\)
\(=13\cdot\left\{27\cdot\left(-100\right)\right\}\)
\(=13\cdot\left(-2700\right)\)
\(=-35100\)