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\(#N\)
\(-\dfrac{11}{7}+\dfrac{13}{-2}+-\dfrac{6}{17}=-\dfrac{113}{14}+-\dfrac{6}{17}=-\dfrac{2005}{238}\)
\(\dfrac{13}{-8}+-\dfrac{7}{20}+\dfrac{3}{-8}=\left(-\dfrac{13}{8}+-\dfrac{3}{8}\right)+-\dfrac{7}{20}=-2+-\dfrac{7}{20}=-\dfrac{47}{20}\)
\(-\dfrac{4}{7}+\dfrac{11}{5}+\dfrac{1}{5}+-\dfrac{7}{3}=-\dfrac{4}{7}+\left(\dfrac{11}{5}+\dfrac{1}{5}\right)+-\dfrac{7}{3}=-\dfrac{4}{7}+\dfrac{12}{5}+-\dfrac{7}{3}=-\dfrac{53}{105}\)
a)=3/4+6/13+7/13+8/45+0,25
=(6/13+7/13)+(3/4+0,25)+8/45
=1+1+8/45
=98/45
a)=3/4+6/13+7/13+8/45+1/4
=(3/4+1/4)+(6/13+7/13)+8/45
=1+1+8/45=2+8/45=90/45+8/45=98/45
1: 0,35*12,4=0,35*2,4+0,35*10=3,5+0,84=4,34
2: =0,1-2,34=-2,24
3: =5-2,9=2,1
4: \(=2,5\left(10,124-0,124\right)=10\cdot2,5=25\)
5: =-3/7+1/13
=-39/91+7/91
=-32/91
6: =-1/3+1/3=0
\(0,5.\left[\frac{4}{3}.\left(-20\right)\right].0,75.\frac{8}{-35}\)
\(\frac{5}{10}.\left[\frac{4}{3}.\left(-20\right)\right].\frac{75}{100}.\frac{8}{-35}\)
\(=\frac{2}{5}.\left[\frac{4}{3}.\left(-20\right)\right].\frac{3}{4}.\frac{8}{-35}\)
\(=\left(\frac{4}{3}.\frac{3}{4}\right).\left[\frac{2}{5}.\frac{\left(-35\right)}{8}\right].\left(-20\right)\)
\(=1.\left(\frac{2}{1}.\frac{1}{4}\right).\left(-20\right)\)
\(=1.\frac{1}{2}.\left(-20\right)=-\frac{20}{2}=\frac{10}{1}=10\)
Mk ko chắc, bn tham khảo nha
B=1/4.8/3.(-20).3/-8.-1/5
=[1/4.-1/5.(-20)].[8/3.3/-8]
= 1 . (-1)
= -1
\(B=\left(0,25.\left(-20\right)\right).\left(\frac{8}{3}.\frac{3}{-8}\right).\frac{-7}{35}\)
\(B=-5\cdot\left(-1\right).\frac{-7}{35}\)
\(B=-1\)