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a, 4 . 24 . 5 2 - 3 3 . 18 + 3 3 . 12
= 100.24–27.30
= 2400 – 810
= 1590
b, 2 3 . 7 . 5 3 - 5 2 . 65 + 5 2 . 35
= 7.1000 – 25.100
= 7000 – 2500
= 4500
c, 2 2 . 74 . 5 2 + 5 2 . 26 . 4 - 7000
= 100.74 + 100.26 – 70.100
= 100.(74+26–70)
= 100.30
= 3000
d, 55 . 2 2 . 5 + 4 . 89 . 5 2 - 3 2 . 10 3
= 25.4.11 + 4.25.89 – 90.100
= 100.11 + 100.89 – 100.90
= 100.(11+89–90)
= 100.10
= 1000
e, [(315+372).3+(372+315).7]:(26.13+74.13+74)
= [687.3+687.7]:(13.(26+74)+74)
= (687.10):(13.100+74)
= 6870:1374
= 5
b) 3 3 . 18 - 3 3 . 12 = 27.18 -27.12 = 27.(18 – 12) = 27.6 = 162
33.18 - 33.12 = 27.18 - 27.12 = 27.(18 - 12)
= 27.6 = 162
hoặc
33.18 - 33.12 = 27.18 - 27.12 = 486 - 324 = 162
a,15+23+(-25)+(-23)=[ (-23)+23] +[(-25)+15] = 0+(-10)= -10
b,-23.63+23.21-58.23=23.(-63)+23.21-58.23=23.(-63+21-58)=23.(-100)=-2300
a)
15 + 23 + ( -25 ) + ( -23 )
= [ 15 + ( -25 ) ] + [ 23 + ( -23 ) ]
= -10 + 0
= -10.
b)
-23.63 + 23.21 - 58.23
= -23 . ( 63 - 21 + 58 )
= -23 . 100
= -2300.
Giải;
1) \(347.222-222.\left(216+184\right):8\)
\(=347.222-222.400:8\)
\(=347.222-222.50\)
\(=222.\left(347-50\right)\)
\(=222.297\)
\(=65934\)
2) \(132-\left[116-\left(132-128\right).22\right]\)
\(=132-\left[116-4.22\right]\)
\(=132-\left[116-88\right]\)
\(=132-28\)
\(=104\)
3) \(16:\left\{400:\left[200-\left(37+46.3\right)\right]\right\}\)
\(=16:\left\{400:\left[200-\left(37+138\right)\right]\right\}\)
\(=16:\left\{400:\left[200-175\right]\right\}\)
\(=16:\left\{400:25\right\}\)
\(=16:16\)
\(=1\)
4) \(\left\{184:\left[96-124:31\right]-2\right\}.3651\)
\(=\left\{184:\left[96-4\right]-2\right\}.3651\)
\(=\left\{184:92-2\right\}.3651\)
\(=\left\{2-2\right\}.3651\)
\(=0.3651\)
\(=0\)
5) \(46-\left[\left(16+71.4\right):15\right]-2\)
\(=46-\left[\left(16+284\right):15\right]-2\)
\(=46-\left[300:15\right]-2\)
\(=46-20-2\)
\(=24\)
6) \(3^3.18+72.4^2-41.18\)
\(=18.\left(27-41\right)+72.16\)
\(=18.-14+1152\)
\(=-252+1152\)
\(=900\)
Giải: (tiếp)
7) \(\left(56.46-25.23\right):23\)
\(=\left(2576-575\right):23\)
\(=2001:23\)
\(=87\)
8) \(\left(28.54+56.36\right):21:2\)
\(=\left(1512+2016\right):21:2\)
\(=3528:21:2\)
\(=84\)
9) \(\left(76.34-19.64\right):\left(38.9\right)\)
\(=\left(2584-1216\right):342\)
\(=1368:342\)
\(=4\)
10) \(\left(2+4+6+...+100\right).\left(36.333-108.111\right)\)
\(=\left(2+4+6+...+100\right).\left(11988-11988\right)\)
\(=\left(2+4+6+...+100\right).0\)
\(=0\)
11) \(\left(5.4^{11}-3.16^5\right):4^{10}\)
\(=5.4^{11}:4^{10}-3.16^5:4^{10}\)
\(=5.4-3.1\)
\(=20-3\)
\(=17\)
12) \(7256.4375-725:3650+4375.7255\)
\(=4375.\left(7256+7255\right)-\dfrac{29}{146}\)
\(=4375.14511-\dfrac{29}{146}\)
\(=63485624,8\)
Câu 12 ko chắc!
a) 29.(85-47)+85.(47-29)= 29.85-29.47+85.47-85.29
=(29.85-85.29) -29.47+85.47
=0-29.47+85.47
= -29.47+85.47
= (-29+85).47
=56.47
= 2632
b)47.(23+50)-23.(47+50)= 47.23+47.50-23.47+23.50
=(47.23-23.47)+47.50+23.50
=0+47.50+23.50
=47.50+23.50
=(47+23).50
=70.50
=3500
tích ^.^ ~
a) 29.(85-47)+85(47-29)
=29.38+85.18
=1102+1520
=2622
b)47.(23+50)-23.(47+50)
=47.73-23.97
=3431-2231
=1200
k mình nha...^_^...kb nữa... thanks
a, Ta có :
A = 1 + 2 + 2 2 + 2 3 + 2 4 + . . . + 2 99 + 2 100
2A = 2 + 2 2 + 2 3 + 2 4 + . . . + 2 99 + 2 100 + 2 101
A = 2A – A = ( 2 + 2 2 + 2 3 + 2 4 + . . . + 2 99 + 2 100 + 2 101 ) –( 1 + 2 + 2 2 + 2 3 + 2 4 + . . . + 2 99 + 2 100 )
= 2 + 2 2 + 2 3 + 2 4 + . . . + 2 99 + 2 100 + 2 101 – 1 - 2 - 2 2 - 2 3 - 2 4 - . . . - 2 99 - 2 100
= 2 101 - 1
Vậy A = 2 101 - 1
b, Ta có.
B = 5 + 5 3 + 5 5 + . . . + 5 97 + 5 99
5 2 B = 5 2 ( 5 + 5 3 + 5 5 + . . . + 5 97 + 5 99 )
25B = 5 3 + 5 5 + . . . + 5 97 + 5 99 + 5 101
25B – B = ( 5 3 + 5 5 + . . . + 5 97 + 5 99 + 5 101 ) – ( 5 + 5 3 + 5 5 + . . . + 5 97 + 5 99 )
24B = 5 3 + 5 5 + . . . + 5 97 + 5 99 + 5 101 – 5 - 5 3 - 5 5 - . . . - 5 97 - 5 99
24B = 5 101 - 5
B = 5 101 - 5 24 = 5 5 100 - 1 24
Vậy B = 5 5 100 - 1 24