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1) \(35.18-5.7.28\)
\(=35.18-35.28\)
\(=35.\left(18-28\right)\)
\(=35.\left(-10\right)\)
\(=-350\)
2) \(45-5.\left(12+9\right)\)
\(=45-60-45\)
\(=\left(45-45\right)-60\)
\(=0-60\)
\(=-60\)
3) \(24.\left(16-5\right)-16.\left(24-5\right)\)
\(=\left(384-120\right)-\left(384-120\right)\)
\(=264-264\)
\(=0\)
4) \(13.\left(23+22\right)-3.\left(17+28\right)\)
\(=13.45-3.45\)
\(=\left(13-3\right).45\)
\(=10.45\)
\(=450\)
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1/ 35 . 18 - 5 . 7 . 28
= 35 . 18 - 35 . 28
= 35 . (18 - 28)
= 35 . (-10)
= -350
2/ 45 - 5 . (12 + 9)
= 5 . 9 - 5 . 12 + 5 . 9
= 5 . (9 - 12 + 9)
= 5 . 6
= 30
3/ 24 . (16 - 5) - 16 . (24 - 5)
= 24 . 16 - 24 . 5 - 16 . 24 - 16 . 5
= (24 . 16 - 16 . 24) - (24 . 5 - 16 . 5)
= 0 - [5 . (24 - 16)]
= 0 - [5 . 8]
= 0 - 40
= -40
4/ 13 . (23 + 22) - 3 . (17 + 28)
= 13 . 45 - 3 . 45
= 45 . (13 - 3)
= 45 . 10
= 450
a: =-21/36-3/36=-24/36=-2/3
b: =43/12*1/2+5/24=43/24+5/24=2
c: =8/9+1/9=1
e: =1-1/4+1/4-1/7+...+1/97-1/100
=1-1/100=99/100
35.18-5.7.28=35.18-35.28=35(18-28)=-350
45-5.12-5.9=45-60-45=-60
=24.16-24.5-16.24-16.5=5(-24-16)=5.-40=-200
35 . 18 - 5 . 7 . 28 = 35 . 18 - 35 . 28
= 35 . (18 - 28)
= 35 . (-10)
= -350
45 - 5 . (12 + 9) = 45 - 5 . 9 + 5 . 12
= 45 - 45 + 60
= 60
24 . (16 - 5) - 16 . (24 - 5) = 24 . 16 - 24 . 5 - 16 . 24 + 16 . 5
= (24 . 16 - 16 . 24) + (16 . 5 - 24 . 5)
=0 + 5 . (16 - 24)
= 5. (-8)
= -40
a)=3/4+6/13+7/13+8/45+0,25
=(6/13+7/13)+(3/4+0,25)+8/45
=1+1+8/45
=98/45
a)=3/4+6/13+7/13+8/45+1/4
=(3/4+1/4)+(6/13+7/13)+8/45
=1+1+8/45=2+8/45=90/45+8/45=98/45
a: =3/8-1/4
=3/8-2/8
=1/8
b: =-5/9+3/5-1/9+2/5
=-2/3+1
=1/3
c: =21/7*5/25=3/5
d: =3/4+11/10:(2/5-3/2)-1/9
=-13/36
\(\left(1-\dfrac{5}{17}\right)\left(\dfrac{3}{8}-\dfrac{5^2}{24}\right)\)
\(=\dfrac{17-5}{17}\cdot\dfrac{9-25}{24}\)
\(=\dfrac{12}{17}\cdot\dfrac{-16}{24}=\dfrac{-16}{17}\cdot\dfrac{12}{24}=\dfrac{-16}{17}\cdot\dfrac{1}{2}=-\dfrac{8}{17}\)
Lời giải:
a. $=-(37+63)+[25+(-25)]+(-9)=-100+0+(-9)=-(100+9)=-109$
b. $=[1+(-3)]+[5+(-7)]+....+[21+(-23)]$
$=\underbrace{(-2)+(-2)+....+(-2)}_{6}=(-2).6=-12$
c. $=-(280+20)+[-(79+21)]=-300+(-100)=-(300+100)=-400$
d. $=[-(27+43)]+[-(208+102)]=-70+(-310)=-(70+310)=-380$
e. $=(38+120)-(12+46)=158-58=100$
f. $=9+15+11+24=(9+11)+(15+24)=20+39=59$
1) 125.(-24) + 24.225.
\(=24\left(-125+225\right)=24.100=2400.\)
2) 512.(2 – 128) – 128. (-512).
\(=512\left(2-128+128\right)=512.2=1024.\)
\(=\dfrac{3^{28}\cdot2^{21}\cdot5^{10}}{2^9\cdot3^3\cdot2^2\cdot3\cdot5^{12}}=\dfrac{3^{28}}{3^4}\cdot\dfrac{2^{21}}{2^{11}}\cdot\dfrac{1}{5^2}=\dfrac{3^{24}\cdot2^{10}}{5^2}\)