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1) \(35.18-5.7.28=35.18-35.28=35\left(18-28\right)=-350\)
2) \(45-5\left(12+9\right)=45-60-45=-60\)
3) \(24\left(16-5\right)-16\left(24-5\right)=24.16-24.5-16.24+16.5=5\left(16-24\right)=5.8=40\)
4) \(29\left(19-13\right)-19\left(29-13\right)=29.19-29.13-19.29+19.13=13\left(19-29\right)=-130\)
5) \(31.\left(-18\right)+31.\left(-81\right)-31=-31.\left(18+81+1\right)=-3100\)
6) \(\left(-12\right).47+\left(-12\right).52+\left(-12\right)=\left(-12\right)\left(47+52+1\right)=-1200\)
7) \(13\left(23+22\right)-3\left(17+28\right)=13.45-3.45=45.\left(13-3\right)=450\)
8) \(-48+48.\left(-78\right)+48.\left(-21\right)=-48\left(1+78+21\right)=-4800\)
\(1.\dfrac{-7}{18}+\dfrac{-5}{12}-\dfrac{-13}{18}\text{=}\left(\dfrac{-7}{18}-\dfrac{-13}{18}\right)+\dfrac{-5}{12}\text{=}\dfrac{1}{3}+\dfrac{-5}{12}\text{=}\dfrac{-1}{12}\)
\(2.\dfrac{-13}{17}+\dfrac{-13}{21}+\dfrac{-4}{17}\text{=}\left(\dfrac{-13}{17}+\dfrac{-4}{17}\right)+\dfrac{-13}{21}\text{=}-1+\dfrac{-13}{21}\text{=}\dfrac{-34}{21}\)
\(3.\dfrac{-13}{10}-\dfrac{-4}{13}+\dfrac{-11}{10}\text{=}\dfrac{-12}{5}-\dfrac{-4}{13}\text{=}\dfrac{-136}{65}\)
\(4.\dfrac{13}{17}\times\left(\dfrac{-4}{5}+\dfrac{-3}{4}\right)\text{=}\dfrac{13}{17}\times\dfrac{-31}{20}\text{=}\dfrac{-403}{340}\)
\(5.\left(\dfrac{-5}{12}\times\dfrac{-9}{20}\right)\times\dfrac{-7}{17}\text{=}\dfrac{3}{16}\times\dfrac{-7}{17}\text{=}\dfrac{-21}{272}\)
\(6.\dfrac{11}{23}\times\left(\dfrac{5}{9}+\dfrac{17}{9}-\dfrac{13}{9}\right)\text{=}\dfrac{11}{23}\times1\text{=}\dfrac{11}{23}\)
1) 35.18 - 5.7.28
= 35.18 - 35.28
= 35.(18 - 28)
= 35.(-10)
= -350
2) 45 - 5.(12 + 9)
= 45 - 5.12 - 5.9
= 45 - 60 - 45
= (45 - 45) - 60
= 0 - 60
= -60
3) 24.(16 - 5) - 16.(24 - 5)
= 24.16 - 24.5 - 16.24 + 16.5
= (24.16 - 16.24) - (24.5 + 16.5)
= 0 - (24.5 + 16.5)
= -24.5 + 16.5
= 5.(-24 + 16)
= 5.(-8)
= -40
4) 29.(19 - 13) - 19.(29 - 13)
= 29.19 - 29.13 - 19.29 + 19.13
= (29.19 - 19.29) + (19.13 - 29.13)
= 0 + (19.13 - 29.13)
= 19.13 - 29.13
= 13.(19 - 29)
= 13.(-10)
= -130
5) 31.(-18) + 31.(-81) - 31
= 31.(-18 - 81 - 1)
= 31.(-100)
= -3100
6) (-12).47 + (-12).52 + (-12)
= (-12).(47 + 52 + 1)
= (-12).100
= -1200
7) 13.(23 + 22) - 3.(17 + 28)
= 13.45 - 3.45
= 45.(13 - 3)
= 45.10
= 450
8) -48 + 48.(-78) + 48.(-21)
= 48.(-1) + 48.(-78) + 48.(-21)
= 48.(-1 - 78 - 21)
= 48.(-100)
= -4800
Cố gắng lên nhé em Hoàng Mai Hoa
1)35.18-5.7.28
= 35 . 18 - 35 . 28
= 35 . ( 18 - 28 )
= 35 . ( - 10 )
= - 350
35.18-5.7.28
=35.18-35.28
=35.(18-28)
=35.(-10) =-350
Bài 1:
\(A=\dfrac{-1}{3}+1+\dfrac{1}{3}=1\)
\(B=\dfrac{2}{15}+\dfrac{5}{9}-\dfrac{6}{9}=\dfrac{2}{15}-\dfrac{1}{9}=\dfrac{18-15}{135}=\dfrac{3}{135}=\dfrac{1}{45}\)
\(C=\dfrac{-1}{5}+\dfrac{1}{4}-\dfrac{3}{4}=\dfrac{-1}{5}-\dfrac{1}{2}=\dfrac{-7}{10}\)
Bài 2:
a: \(=\dfrac{1}{5}+\dfrac{1}{2}+\dfrac{2}{5}-\dfrac{3}{5}+\dfrac{2}{21}-\dfrac{10}{21}+\dfrac{3}{20}\)
\(=\left(\dfrac{1}{5}+\dfrac{2}{5}-\dfrac{3}{5}\right)+\left(\dfrac{2}{21}-\dfrac{10}{21}\right)+\left(\dfrac{1}{2}+\dfrac{3}{20}\right)\)
\(=\dfrac{-8}{21}+\dfrac{13}{20}=\dfrac{113}{420}\)
b: \(B=\dfrac{21}{23}-\dfrac{21}{23}+\dfrac{125}{93}-\dfrac{125}{143}=\dfrac{6250}{13299}\)
Bài 3:
\(\dfrac{7}{3}-\dfrac{1}{2}-\left(-\dfrac{3}{70}\right)=\dfrac{7}{3}-\dfrac{1}{2}+\dfrac{3}{70}=\dfrac{490}{210}-\dfrac{105}{210}+\dfrac{9}{210}=\dfrac{394}{210}=\dfrac{197}{105}\)
\(\dfrac{5}{12}-\dfrac{3}{-16}+\dfrac{3}{4}=\dfrac{5}{12}+\dfrac{3}{16}+\dfrac{3}{4}=\dfrac{20}{48}+\dfrac{9}{48}+\dfrac{36}{48}=\dfrac{65}{48}\)
Bài 4:
\(\dfrac{3}{4}-x=1\)
\(\Rightarrow-x=1-\dfrac{3}{4}\)
\(\Rightarrow x=-\dfrac{1}{4}\)
Vậy: \(x=-\dfrac{1}{4}\)
\(x+4=\dfrac{1}{5}\)
\(\Rightarrow x=\dfrac{1}{5}-4\)
\(\Rightarrow x=-\dfrac{19}{5}\)
Vậy: \(x=-\dfrac{19}{5}\)
\(x-\dfrac{1}{5}=2\)
\(\Rightarrow x=2+\dfrac{1}{5}\)
\(\Rightarrow x=\dfrac{11}{5}\)
Vậy: \(x=\dfrac{11}{5}\)
\(x+\dfrac{5}{3}=\dfrac{1}{81}\)
\(\Rightarrow x=\dfrac{1}{81}-\dfrac{5}{3}\)
\(\Rightarrow x=-\dfrac{134}{81}\)
Vậy: \(x=-\dfrac{134}{81}\)
45 - 5 . (12 + 9)
= 45 - 5 . 21
= 45 - 105
= -60
-48 + 48 . (-78) + 48 . (-21)
= -48 + (-48) . 78 + (-48) . 21
= -48 . (78 + 21 + 1)
= -48 . 100
= -4800
\(\left(\frac{-5}{12}.\frac{4}{21}+\frac{5}{12}.\frac{-17}{21}\right).\left(\frac{-2}{4}\right)\)
\(=\left(\frac{-5}{12}\left(\frac{4}{21}+\frac{17}{21}\right)\right).\left(\frac{-2}{4}\right)\)
\(=\left(\frac{-5}{12}.1\right).\left(\frac{-2}{4}\right)\)
\(=\frac{-5}{12}.\frac{-2}{4}=\frac{5}{24}\)
\(\left(\frac{-5}{12}.\frac{4}{21}+\frac{5}{12}.\frac{-17}{21}\right).\left(-2,4\right)\)
\(=\left[\frac{\left(-5\right)}{12}+\frac{5}{12}\right].\left[\frac{\left(-17\right)}{21}+\frac{4}{21}\right].\left(\frac{-24}{10}\right)\)
\(=0.\frac{\left(-13\right)}{21}.\frac{\left(-12\right)}{5}\)
\(=0\)