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a) \(\dfrac{3}{7}\)
b)\(\dfrac{9}{4}\)
c)\(\dfrac{1}{3}\)
d)\(\dfrac{41}{32}\)
e)\(\dfrac{73}{60}\)
\(2-\dfrac{3}{4}x\dfrac{8}{5}+\dfrac{1}{2}\)
\(=2-\dfrac{24}{20}+\dfrac{1}{2}\)
\(=2-\dfrac{24+10}{20}\)
\(=\dfrac{2}{1}-\dfrac{34}{20}=\dfrac{40-34}{20}=\dfrac{6}{20}=\dfrac{3}{10}\)
\(2-\dfrac{3}{4}\times\dfrac{8}{5}+\dfrac{1}{2}=\dfrac{2\times20}{1\times20}-\dfrac{24}{20}+\dfrac{1\times10}{2\times10}\\ =\dfrac{40-24+10}{20}=\dfrac{26}{20}=\dfrac{13}{10}\)
4/5 + 3/10 - 1/5 x 6 : 4/7
=11/10 - 1/5 x 6 : 4/7
= 9/10 x 6 : 4/7
= 27/5 : 4/7
= 189/20
chúc hok tốt
\(\frac{4}{5}.\frac{3}{7}+\frac{4}{5}.\frac{6}{7}-\frac{4}{5}.\frac{4}{14}\)
\(=\frac{4}{5}.\left(\frac{3}{7}+\frac{6}{7}-\frac{4}{14}\right)\)
\(=\frac{4}{5}.1\)
\(=\frac{4}{5}\)
Đây là bài toán vui mỗi tuần nên anh sẽ không đưa ra lời giải nhé, em chịu khó suy nghĩ tiếp hoặc không nghĩ ra thì đợi kết quả vào thứ 6 nhé
Lời giải:
$2-\frac{5}{9}+\frac{1}{3}=\frac{18}{9}-\frac{5}{9}+\frac{3}{9}=\frac{18-5+3}{9}=\frac{16}{9}$
$1+(\frac{3}{4}-\frac{1}{2})=1+(\frac{3}{4}-\frac{2}{4})=1+\frac{1}{4}=\frac{5}{4}$
$3-(\frac{3}{4}+\frac{3}{8})=3-(\frac{6}{8}+\frac{3}{8})=3-\frac{9}{8}=\frac{15}{8}$
$\frac{14}{5}-(\frac{6}{9}+\frac{1}{3})=\frac{14}{5}-(\frac{2}{3}+\frac{1}{3})$
$=\frac{14}{5}-1=\frac{9}{5}$
\(2-\dfrac{5}{9}+\dfrac{1}{3}=2-\dfrac{5}{9}+\dfrac{3}{9}=\dfrac{2}{1}-\dfrac{5}{9}+\dfrac{3}{9}=\dfrac{18}{9}-\dfrac{5}{9}+\dfrac{3}{9}=\dfrac{18-5+3}{9}=\dfrac{16}{9}\)
\(1+\left(\dfrac{3}{4}-\dfrac{1}{2}\right)=1+\left(\dfrac{3}{4}-\dfrac{2}{4}\right)=1+\dfrac{1}{4}=\dfrac{5}{4}\)
\(3-\left(\dfrac{3}{4}+\dfrac{3}{8}\right)=3-\left(\dfrac{6}{8}+\dfrac{3}{8}\right)=3-\dfrac{9}{8}=\dfrac{3}{1}-\dfrac{9}{8}=\dfrac{24}{8}-\dfrac{9}{8}=\dfrac{15}{8}\)
\(\dfrac{14}{5}-\left(\dfrac{6}{9}+\dfrac{1}{3}\right)=\dfrac{14}{5}-\left(\dfrac{6}{9}+\dfrac{3}{9}\right)=\dfrac{14}{5}-1=\dfrac{14}{5}-\dfrac{5}{5}=\dfrac{9}{5}\)