Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{-11}{23}.\frac{6}{7}+\frac{8}{7}.\frac{-11}{23}-\frac{1}{23}\)=\(\frac{-11}{23}.\left(\frac{6}{7}+\frac{8}{7}\right)-\frac{1}{23}\)=\(\frac{-11}{23}.2-\frac{1}{23}\)=\(\frac{-22}{23}-\frac{1}{23}=\frac{-21}{23}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
suy ra A=1/23+1/7-1/1009.23.7.1009 phần 1/23+1/7-1/1009+1/7.1/3/1/1009 .23.7.1009+1/30.1009-160
suy ra A=7.1009+23.1009-23.7/7.1009+23.1009-23.7+1+1/7.1009+23.1009-23.7+1=7/1009+23.1009-23.7+1/7.1009+23.1009-23.7+1=1
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{7}{-25}\) \(+\) \(\frac{-18}{25}\) \(+\) \(\frac{4}{23}\) \(+\) \(\frac{5}{7}\) \(+\) \(\frac{19}{23}\) \(+\) \(\frac{2}{14}\)
\(=\)\(\frac{6}{7}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=\frac{7}{12}+\frac{5}{12}:6-\frac{1}{36}\)
\(=\frac{7}{12}+\frac{5}{72}-\frac{11}{36}\)
\(=\frac{42}{72}+\frac{5}{72}-\frac{22}{72}\)
\(=\frac{25}{72}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\frac{31}{23}-\left(\frac{7}{23}+\frac{8}{23}\right)\)
\(=\frac{31}{23}-\frac{15}{23}\)
\(=\frac{16}{23}\)
b) \(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)
\(=\frac{1}{3}+\frac{12}{67}+\frac{13}{41}-\frac{79}{67}+\frac{28}{41}\)
\(=\frac{1}{3}+\left(\frac{12}{67}-\frac{79}{67}\right)+\left(\frac{13}{41}+\frac{28}{41}\right)\)
\(=\frac{1}{3}+\frac{-67}{67}+\frac{41}{41}\)
\(=\frac{1}{3}-1+1\)
\(=\frac{1}{3}\)
c) \(\frac{38}{45}-\left(\frac{8}{45}-\frac{17}{52}-\frac{3}{11}\right)\)
\(=\frac{38}{45}-\frac{8}{45}+\frac{17}{52}+\frac{3}{11}\)
\(=\frac{30}{45}+\frac{17}{52}+\frac{3}{11}\)
\(=\frac{2}{3}+\frac{17}{52}+\frac{3}{11}\)
\(=\frac{104+51}{156}+\frac{3}{11}\)
\(=\frac{155}{156}+\frac{3}{11}\)
\(=\frac{156}{156}-\frac{1}{156}+\frac{3}{11}\)
\(=1-\frac{1}{156}+\frac{3}{11}\)
\(=1-\left(\frac{11-468}{1716}\right)\)
\(=1-\frac{-457}{1716}\)
\(=1+\frac{457}{1716}\)
\(=\frac{2173}{1716}\)
a)31/23-(7/32+8/23)=31/23-7/32-8/23=(31/23-8/23)-7/32=1-7/32=25/32
\(\frac{4354}{23}+\frac{2453425}{23}=\frac{4354+2453425}{23}=\frac{2457779}{23}\)
\(\frac{43352}{12}+\frac{23412134}{23}=\frac{997096}{276}+\frac{280945608}{276}=\frac{281942704}{276}\)
\(\frac{4354+2453425}{23}=\frac{2457779}{23}\)