Question

[Ngoc Vy Lieu Truong]

tính: các bn hãy giúp mình nhé

Answer 1

[Edogawa Conan]

\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}=\frac{\left(2^2\right)^6.\left(3^2\right)^5+\left(2.3\right)^9.2^3.3.5}{\left(2^3\right)^4.3^{12}-\left(2.3\right)^{11}}=\frac{3^{10}.2^{12}+2^{12}.3^{10}.5}{2^{12}.3^{12}-2^{11}.3^{11}}\)

\(=\frac{2^{12}.3^{10}.\left(1+5\right)}{3^{11}.2^{11}\left(2.3-1\right)}=\frac{2.6}{3.5}=\frac{4}{5}\)

Answer 2

[Nguyễn Tiến Huy]

\(=\frac{2^{12}.3^{10}+2^9.3^9.3.2^3.5}{2^{12}.3^{12}-2^{11}.3^{11}}\)

\(=\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{2^{11}.3^{11}.\left(2.3-1\right)}\)

\(=\frac{2^{12}.3^{10}.\left(1+5\right)}{2^{11}.3^{11}.5}\)

\(=\frac{2.3.6}{5}\)

\(=\frac{36}{5}\)