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a) 0,25 x 611,7 x 40
=0,25 x 40 x 611,7
=10 x 611,7
=6117
b) 17,6 x 3,21 + 3,21 x 42,4 +3,21 x 40
= 3,21 x ( 17,6+42,4+40)
=3,21 x (60+40)
=3,21 x 100
=321
a, 0,25*611,7* 40
=(0,25* 40)* 611,7
=10*611,7
=6117
b, 17,6*3,21+3,21*42,4+3,21*40
=3,21* ( 17,6+42,4+40)
= 3,21*100
=321
x : 0,25 + x : 0,5 + x + x :0,01 = 3,21
x * 4 + x * 2 + x * 1 + x * 100 = 3,21
x * ( 4 + 2 + 1 + 100 ) = 3,21
x * 107 = 3,21
x = 3,21 : 107
x = 0,03
5,65.13,8+35,7.3,21+5,65.21,9+35,7.1,14
=5,65.(13,8+21,9)+35,7.(3,21+1,14)
=5,65.35,7+35,7.4,35
=35,7.(5,65+4,35)
=35,7.10
=357
Lời giải:
$(2,41+3,12)\times 2,2=5,53\times 2,2=12,166$
$(5,6-3,21)\times 2,3=2,39\times 2,3=5,497$
$3,276:1,4+7,66=2,34+7,66=10$
$28,886:1,3+77,78=22,22+77,78=100$
a) 0,25x3/4-0,25x0,25+0,25x1/2
=0,25x(3/4-0,25+1/2)
=0,25x1
=0,25
b) 5,68x8+56,8x0,1+56,8:10
=5,68x8+5,68+5,68
=5,68x(8+1+1)
=5,68x10
=56,8
2 - [x : 4/7 - \(2\frac{3}{4}\)] * 9,8 = 0
=> 2 - [x : 4/7 - 11/4] = 0
=> x : 4/7 -11/4 = 2
=> x : 4/7 = 2 + 11/4
=> x : 4/7 = 19/4
=> x = 19/4 * 4/7
=> x = 19/7
Vậy x = 19/7
\(3\frac{1}{4}\cdot\left(8\frac{1}{2}-x\div\frac{1}{3}\right)=3,21\)
\(\Rightarrow\frac{13}{4}\cdot\left(\frac{17}{2}-x\div\frac{1}{3}\right)=3,21\)
\(\Rightarrow3,25\cdot\left(8,5-x\div\frac{1}{3}\right)=3,21\)
\(\Rightarrow8,5-x\div\frac{1}{3}=3,21\div3,25\)
\(\Rightarrow8,5-x\div\frac{1}{3}=\frac{321}{325}\)
\(\Rightarrow x\div\frac{1}{3}=8,5\div\frac{321}{325}\)
\(\Rightarrow x\div\frac{1}{3}=\frac{5525}{642}\)
\(\Rightarrow x=\frac{5525}{642}\cdot\frac{1}{3}=2,868639668\)
Chắc đề sai bn à
a/\(0,25\times611,7\times4\)
\(=\left(0,25\times4\right)\times611,7\)
\(=1\times611,7\)
\(=611,7\)
b/\(17,6\times3,21+3,21\times42,4+3,21\times40\)
\(=3,21\times\left(17,6+42,4+40\right)\)
\(=3,21\times100\)
\(=321\)
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