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mình lam một phần thôi
\(\frac{42134\times846267-423133}{846267\times423133+423134}=\frac{\left(42133+1\right)\times846267-42133}{846267\times423133+423134}\)
\(=\frac{42133\times846267+846267-42133}{846267\times42133+42134}=\frac{846267\times42133+42134}{846267\times42133+42134}=1\)
a) A = 1 + ( - 2 ) + 3 + ... + ( - 98 ) + 99
A = 1 + [ ( - 2 ) + 3 ] + ... + [ ( - 98 ) + 99 ]
A = 1 + 1 + ... + 1
A = 1 . 50
A = 50
miucool:
A = 1 + (-2) + 3 + ... + (-98) + 99
A = 1 + [(-2) + 3)] + ... + [(-98) + 99)]
A = 1 + 1 + ... + 1
Có 50 cặp số:
A = 1 . 50
A = 50
Vậy A =50
(^_^)
a)(1/4+3/4)-(5/13+8/13)+2/11=1-1+2/11=2/11
b)(21/31+10/31)-16/7+(44/53+9/53)=1+1-16/7=14/7-16/7=-2/7
b.\(\frac{1374.57+1374.34}{26.13+74.13+74}=\frac{1374.91}{1374}=91\)
a, 1990 . 1990 - 1982 . 1998
= ( 1982 + 8 ) . 1990 - 1982 . ( 1990 + 8 )
= 1982 .1990 + 8 .1990 - ( 1982 . 1990 + 8 . 1982 )
= 1982 . 1990 + 8 .1990 - 1982 . 1990 - 8 . 1982
= ( 1982 .1990 - 1982 . 1990 ) + ( 8 . 1990 - 8 . 1982 )
= 8 . ( 1990 - 1982 )
= 8 . 8
= 64
Mình sửa đề bài chút xíu nha 1992 thành 1982
\(11-\left(15-49\right)=-x+\left(9-25\right)\)
\(11-15+49=-x+9-25\)
\(x=9-25-11+15-49\)
\(x=-61\)
Vậy \(x=-61\)
\(x-+\left(-479-479\right)=-\left(26-74\right)\)
\(x+479+479=-26+74\)
\(x=74-26-479-479\)
\(x=-910\)
Vậy \(x=-910\)
sua lai
A) \(\left(44.52.60\right):\left(11.13.15\right)\)
\(=\left(4.11.4.13.4.15\right):\left(11.13.15\right)\)
\(=4^3\left(11.13.15\right):\left(11.13.15\right)\)
\(=64\)
B) \(123.456456-456.123123\)
\(=123.456.1001-456.123.1001\)
\(=56088.1001-56088.1001\)
\(=1001.\left(56088-56088\right)\)
\(=1001.0\)
\(=0\)
C) \(\left(98.7676-9898.76\right):\left(2001.2002....2020\right)\)
\(=\left(98.76.101-98.101.76\right):\left(2001.2002....2020\right)\)
\(=0:\left(2001.2002....2020\right)\)
\(=0\)
Ta có : \(\left(\frac{2}{11.13}+\frac{2}{13.15}+...+\frac{2}{19.21}\right)642-\left[0,04:\left(x+1,05\right)\right]:0,12=19\)
=> \(\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{19}-\frac{1}{21}\right)642-0,04:\left(x+1,05\right):0,12=19\)
=>
(nãy bấm nhầm) tiếp nà :
=> \(\left(\frac{1}{11}-\frac{1}{21}\right)462-0,04:\left(x+1,05\right):0,12=19\)
=> \(\frac{10}{231}.462-0,04:\left(x+1,05\right):0,12=19\)
=> \(20-0,04:\left(x+1,05\right):0,12=19\)
=> 0,04 : (x + 1,05) : 0,12 = 1
=> 0,04 : (x + 1,05) = 0,12
=> \(x+1,05=\frac{1}{3}\)
=> \(x=\frac{1}{3}-1,05=...\)