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a) Cách 1 : (3/4 + 1/2) x 5/7
= 5/4 x 5/7
= 25/28
Cách 2 : (3/4 + 1/2) x 5/7
= 3/4 x 5/7 + 1/2 x 5/7
= 15/28 + 5/14
= 25/28
b) Cách 1 : 5/7 x 13/21 + 2/7 x 13/21
= 65/147 + 26/147
= 13/21
Cách 2 : 5/7 x 13/21 + 2/7 x 13/21
= (5/7 + 2/7) x 13/21
= 1 x 13/21
= 13/21
câu c tự làm
a) Cách 1
\(\frac{3}{4}\)x \(\frac{1}{2}\)x \(2\)
= \(\frac{3}{8}\)x \(2\)
= \(\frac{3}{4}\)
Cách 2
\(\frac{3}{4}\)x \(\frac{1}{2}\)x \(2\)
= \(\frac{3}{4}\)x \(\left(\frac{1}{2}x2\right)\)
= \(\frac{3}{4}\)x 1
= \(\frac{3}{4}\)
5/7+2/3-4/7+4/3
=(5/7+4/7)-(2/3+4/3)
=9/7+6/3
=27/21+42/21
=69/21
a) C1 : 2/5 x 3/7 + 2/7 x 4/7
= 2/5 x (3/7 + 4/7)
= 2/5 x 1
= 2/5
C2 : 2/5 x 3/7 + 2/5 x 4/7
= 6/35 + 8/35
= 2/5
b) (2/3 - 4/7) x 5/5
= 2/21 x 5/5
= 2/21
C2 : (2/3 - 4/7) x 5/5
= 2/3 x 1 - 4/7 x 1
= 2/3 - 4/7
= 2/21
c) 3/4 x 2/5 - 3/4 x 2/7
= 3/4 x (2/5 - 2/7)
= 3/4 x 4/35
= 3/35
C2 : 3/4 x 2/5 - 3/4 x 2/7
= 3/10 - 3/14
= 3/35
a,
Cách 1
\(\frac{2}{5}\times\frac{3}{7}+\frac{2}{5}\times\frac{4}{7}\)
\(=\frac{6}{35}+\frac{8}{35}\)
\(=\frac{2}{5}\)
Cách 2 :
\(\frac{2}{5}\times\frac{3}{7}+\frac{2}{5}\times\frac{4}{7}\)
\(=\frac{2}{5}\times\left(\frac{3}{7}+\frac{4}{7}\right)\)
\(=\frac{2}{5}\times1\)
\(=\frac{2}{5}\)
b,
Cách 1 :
\(\left(\frac{2}{3}-\frac{4}{7}\right)\times\frac{5}{5}\)
\(=\frac{2}{21}\times1\)
\(=\frac{2}{21}\)
Cách 2 :
\(\left(\frac{2}{3}-\frac{4}{7}\right)\times\frac{5}{5}\)
\(=\frac{2}{3}\times\frac{5}{5}-\frac{4}{7}\times\frac{5}{5}\)
\(=\frac{2}{3}-\frac{4}{7}\)
\(=\frac{2}{21}\)
c,
Cách 1 :
\(\frac{3}{4}\times\frac{2}{5}-\frac{3}{4}\times\frac{2}{7}\)
\(=\frac{3}{10}-\frac{3}{14}\)
\(=\frac{3}{35}\)
Cách 2 :
\(\frac{3}{4}\times\frac{2}{5}-\frac{3}{4}\times\frac{2}{7}\)
\(=\frac{3}{4}\times\left(\frac{2}{5}-\frac{2}{7}\right)\)
\(=\frac{3}{4}\times\frac{4}{35}\)
\(=\frac{3}{35}\)
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a,3/5+4/7+2/5+1/7+2/7
= (4/7+1/7+2/7)+(3/5+4/5)
=7/7+5/5
=1+1
=2
b, 1/3+1/6+4/3+2/6+2/3+5/6
=(1/3+4/3+2/3)+(1/6+5/6+2/6)
=7/3+8/6
=7/3+4/3
=11/3
\(\frac{3}{4}\cdot\frac{2}{5}-\frac{3}{4}\cdot\frac{2}{7}\\ =\frac{6}{20}-\frac{6}{28}\\ =\frac{3}{35}\)
\(\frac{3}{4}\cdot\frac{2}{5}-\frac{3}{4}\cdot\frac{2}{7}\\ =\frac{3}{4}\cdot\left(\frac{2}{5}-\frac{2}{7}\right)\\ =\frac{3}{4}\cdot\frac{4}{35}=\frac{3}{35}\)