K
Khách

Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.

21 tháng 8 2021

A=\(\dfrac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=\dfrac{11.3^{29}-3^{29}.3}{2^2.3^{28}}=\dfrac{3^{29}.\left(11-3\right)}{2^2.3^{28}}=\dfrac{3^{29}.2^3}{2^2.3^{28}}=3.2=6\)

29 tháng 10 2017

a) \(A=\dfrac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)

\(A=\dfrac{11.3^{29}-3^{30}}{2^2.3^{28}}\)

\(A=\dfrac{11.3^{29}-3^{29}.3}{2^2.3^{28}}\)

\(A=\dfrac{3^{29}.\left(11-3\right)}{2^2.3^{28}}\)

\(A=\dfrac{3^{29}.8}{2^2.3^{28}}\)

\(A=\dfrac{3.8}{4}=6\)

vậy \(A=6\)

b) \(B=\dfrac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)

\(B=\dfrac{3^2.\left(2^2\right)^2.\left(2^{16}\right)^2}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)

\(B=\dfrac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)

\(B=\dfrac{3^2.2^{36}}{11.2^{35}-2^{35}.2}\)

\(B=\dfrac{3^2.2^{36}}{2^{35}.\left(11-2\right)}\)

\(B=\dfrac{3^2.2^{36}}{2^{35}.9}\)

\(B=\dfrac{3^2.2}{9}\)

\(B=\dfrac{9.2}{9}\)

\(B=2\)

vậy \(B=2\)

20 tháng 7 2017

A=11.322.37-915/(2.314)2

A=11.329-915/22.328

A=11.329-(32)15/4.328

A=11.329-330/4.328

A=11.329-329.3/4.328

A=329.(11-3)/328.4

A=329.8/328.4

A=3.8/4

A=24/4

A=6

ai tích mình mình tích lại cho

31 tháng 5 2015

\(A=\frac{11\cdot3^{22}\cdot3^7-9^{15}}{\left(2\cdot3^{14}\right)^2}=6\)

\(B=\frac{\left(3\cdot4\cdot2^{16}\right)^2}{11\cdot2^{13}\cdot4^{11}-16^9}=2\)

\(C=\frac{4^5\cdot9^{4-2\cdot6^9}}{2^{10}\cdot3^8+6^8\cdot20}=0\)

 

15 tháng 8 2016

A=\(\frac{11\cdot3^{22}\cdot3^7-9^{15}}{\left(2\cdot3^{14}\right)^2}=6\)

16 tháng 7 2017

\(=\frac{11.3^{29}-3^{30}}{2^2.3^{28}}=\frac{3^{29}\left(11-3\right)}{2^2.3^{28}}=\frac{3^{29}.2^3}{2^2.3^{28}}=3.2=6.\)

16 tháng 7 2017

\(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=\frac{11.3^{22}.3^7-\left(3^2\right)^{15}}{2^2.\left(3^{14}\right)^2}=\frac{11.3^{29}-3^{30}}{2^2.3^{28}}\)

\(=\frac{3^{29}\left(11-3\right)}{2^2.3^{28}}=\frac{3.8}{4}=\frac{24}{4}=6\)

Đáp số: \(6\)

17 tháng 10 2021

\(=\dfrac{11\cdot3^{21}-3^{30}}{2^2\cdot3^{28}}=\dfrac{3^{21}\left(11-3^7\right)}{2^2\cdot3^{28}}=\dfrac{-2176}{2^2\cdot3^7}=\dfrac{-2176}{8748}=\dfrac{-544}{2187}\)

8 tháng 4 2017

a)

=

b) =

9 tháng 4 2017

a, \(\left(\dfrac{-2}{3}+\dfrac{3}{7}\right)-\dfrac{5}{21}:\dfrac{4}{5}+\left(\dfrac{-1}{3}+\dfrac{4}{7}\right):\dfrac{4}{5}\\ = -\dfrac{5}{21}:\dfrac{4}{5}+ \left(-\dfrac{5}{21}\right):\dfrac{4}{5}\\ =\left[-\dfrac{5}{21}+\left(-\dfrac{5}{21}\right)\right]:\dfrac{4}{5}\\ -\dfrac{10}{21}:\dfrac{4}{5}\\ =-\dfrac{25}{42}\)

b,

\(\dfrac{5}{9}:\left(\dfrac{1}{11}-\dfrac{5}{22}\right)+\dfrac{5}{9}:\left(\dfrac{1}{15}-\dfrac{2}{3}\right)\\ =\dfrac{5}{9}:\dfrac{-3}{22}+\dfrac{5}{9}:-\dfrac{3}{5}\\ =\dfrac{5}{9}:\left(\dfrac{-3}{22}+-\dfrac{3}{5}\right)\\ =\dfrac{5}{9}:-\dfrac{81}{110}\\ =-\dfrac{550}{729}\)

24 tháng 7 2017

\(A=\dfrac{2^{12}.3^5-\left(2^2\right)^6.\left(3^2\right)^2}{\left(2^2\right)^6.3+\left(2^3\right)^4.3^5}-\dfrac{5^{10}+7^3-\left(5^2\right)^5.\left(7^2\right)^2}{(5^3).7^3+5^9.\left(7^2\right)^3}\)

\(A=\dfrac{2^4.1-2.3^3}{1.1+1.1}-\dfrac{5+1-5.1}{1.1+1.7}\)

\(A=\dfrac{2^4-54}{2}-\dfrac{1.1}{2\cdot7}\)

\(A=(2^3-54)-\dfrac{1}{14}\)

\(A=\left(-46\right)-\dfrac{1}{14}\)

Câu 2: 

\(B=\dfrac{5^{21}\cdot\left(2\cdot5-9\right)}{5^{20}}\cdot\dfrac{7^{15}\left(7+3\right)}{15\cdot7^{15}-95\cdot7^{14}}\)

\(=\dfrac{5\cdot1}{1}\cdot\dfrac{7^{15}\cdot10}{7^{14}\cdot\left(15\cdot7-95\right)}\)

\(=5\cdot\dfrac{7\cdot10}{105-95}=5\cdot7=35\)

13 tháng 9 2017

a/ \(\dfrac{\left(1+2+.....+100\right)\left(\dfrac{1}{3}-\dfrac{1}{5}-\dfrac{1}{7}-\dfrac{1}{9}\right)\left(6,3.12-21.36\right)}{\dfrac{1}{2}+\dfrac{1}{3}+.......+\dfrac{1}{100}}\)

\(=\dfrac{\left(1+2+3+.....+100\right)\left(\dfrac{1}{3}-\dfrac{1}{5}-\dfrac{1}{7}-\dfrac{1}{9}\right).0}{\dfrac{1}{2}+\dfrac{1}{3}+.......+\dfrac{1}{100}}\)

\(=\dfrac{0}{\dfrac{1}{2}+\dfrac{1}{3}+.....+\dfrac{1}{100}}\)

\(=0\)

13 tháng 9 2017

bn có chép sai đề bài ko vậy