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Bài 2:
a: \(\Leftrightarrow x=\dfrac{29}{60}\cdot\dfrac{-7}{5}=\dfrac{-203}{300}\)
b: \(\Leftrightarrow x\cdot\dfrac{2}{5}=\dfrac{29}{60}-\dfrac{3}{4}=\dfrac{29-45}{60}=\dfrac{-16}{60}=\dfrac{-8}{30}\)
\(\Leftrightarrow x=\dfrac{-8}{30}:\dfrac{2}{5}=\dfrac{-8\cdot5}{30\cdot2}=\dfrac{-40}{60}=-\dfrac{2}{3}\)
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\(\frac{8^2.4^3}{16^3}=\frac{\left(2^3\right)^2.\left(2^2\right)^3}{\left(2^4\right)^3}=\frac{2^6.2^6}{2^{12}}=1\)
\(\frac{25^2.125}{5^3.5^4}=\frac{\left(5^2\right)^2.5^3}{5^4.5^3}=\frac{5^4.5^3}{5^4.5^3}=1\)
\(\frac{8^2.4^3}{16^3}=\frac{\left(2^3\right)^2.\left(2^2\right)^3}{\left(2^4\right)^3}=\frac{2^6.2^6}{2^{12}}=1\)
\(\frac{25^2.125}{5^3.5^4}=\frac{\left(5^2\right)^2.5^3}{5^3.5^4}=\frac{5^4.5^3}{5^3.5^4}=1\)
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a, (1/5)5x(3)5
=1/3125.243
=243/3125
b, (0,125)^3.512
=1/512.512
=1
c,(0,25)^4.1024
=1/256.1024
=4
2,hầu như chịu hết
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#)Giải :
\(\frac{2^{15}.9^2}{6^5.8^3}=\frac{2^{14}.2.\left(3^2\right)^2}{\left(2.3\right)^5.\left(2^3\right)^3}=\frac{2^{14}.2.3^4}{2^5.3^5.2^9}=\frac{2^{14}.2.3^4}{2^{14}.3^5}=\frac{2.3^4}{3^5}=\frac{2.3^4}{3.3^4}=\frac{2}{3}\)
\(\frac{2^{15}.9^2}{6^5.8^3}=\frac{2^{15}.3^4}{2^5.3^5.2^6}=\frac{2^{15}.3^4}{2^{11}.3^5}=\frac{2^4}{3}=\frac{16}{3}\)
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Năm nay mình mới lên lp 4 nên không biết làm bài này.
Xin bạn thông cảm.
Giải:
\(\dfrac{\left(-5\right)^{60}.3^5}{15^5.5^{61}}\)
\(=\dfrac{5^{60}.3^5}{\left(3.5\right)^5.5^{61}}\)
\(=\dfrac{5^{60}.3^5}{3^5.5^5.5^{61}}\)
\(=\dfrac{5^{60}.3^5}{3^5.5^{66}}\)
\(=\dfrac{1}{5^6}=\dfrac{1}{15625}\)