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\(a,\left(0,125\right)^3.8^3\)
\(=\left(0,125.8\right)^3\)
\(=1^3\)
\(=1\)
\(b,\left(-39\right)^4:13^4\)
\(=\left(-39:13\right)^4\)
\(=-3^4\)
\(=81\)
\(=\frac{\left(-11\right).3.13}{39.4.55}=\frac{\left(-1\right).1.1}{1.4.5}=-\frac{1}{20}\)
\(\left(-\frac{11}{39}\right).\frac{3}{4}.\frac{13}{55}\)
\(=\left(-\frac{11}{52}\right).\frac{13}{55}\)
\(=-\frac{1}{20}.\)
Chúc bạn học tốt!
\(=5+\dfrac{17}{39}+4+\dfrac{2}{85}-3-\dfrac{2}{45}-13-\dfrac{19}{85}+\dfrac{11}{45}-\dfrac{4}{39}\)
\(=\left(-4\right)+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}=-4+\dfrac{1}{3}=-\dfrac{11}{3}\)
\(\left(\frac{-4}{13}+\frac{4}{13}+\frac{-12}{13}\right)\times\left(\frac{5}{17}+\frac{4}{17}\right)\)
\(=\)\(\frac{-12}{13}\times\left(\frac{5}{17}+\frac{4}{17}\right)\)
\(=\)\(\frac{-12}{13}\times\frac{9}{17}=\frac{-106}{221}\)
\(\frac{\frac{3}{4}+\frac{3}{5}+\frac{3}{7}+\frac{3}{11}}{\frac{-13}{4}-\frac{13}{5}-\frac{13}{7}-\frac{13}{11}}\)
\(=\frac{3\left(\frac{1}{4}+\frac{1}{5}+\frac{1}{7}+\frac{1}{11}\right)}{-13\left(\frac{1}{4}+\frac{1}{5}+\frac{1}{7}+\frac{1}{11}\right)}\)
\(=\frac{-3}{13}.\)
