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\(\left(125^3.7^5-175^5:5\right):2016^{2017}\)
= \(\left[\left(5^3\right)^3.7^5-\left(5^2.7\right)^5:5\right]:2016^{2017}\)
= \(\left[5^{3.3}.7^5-5^{2.5}.7^5:5\right]:2016^{2017}\)
= \(\left[5^9.7^5-5^{10}.7^5:5\right]:2016^{2017}\)
= \(\left[5^9.7^5-5^9.7^5\right]:2016^{2017}\)
= \(0:2016^{2017}\)
= \(0\)
\(\dfrac{125^3\cdot7^5-175^5:5}{2016^{2017}}\)
\(=\dfrac{5^9\cdot7^5-5^{10}\cdot7^5:5}{2016^{2017}}\)
\(=\dfrac{5^9\cdot7^5-5^9\cdot7^5}{2016^{2017}}\)
=0
a) \(9^3\cdot3^2\)
\(=\left(3^2\right)^3\cdot3^2\)
\(=3^6\cdot3^2\)
\(=3^8\)
b) \(x^7\cdot x:x^4\)
\(=x^8:x^4\)
\(=x^4\)
c) \(7\cdot3^9+3^{10}+51\cdot3^8\)
\(=3^8\cdot\left(7\cdot3+3^2+51\right)\)
\(=3^8\cdot81\)
\(=3^8\cdot3^4\)
\(=3^{12}\)
d) \(5^{15}\cdot125^3\cdot625\)
\(=5^{15}\cdot5^9\cdot5^4\)
\(=5^{28}\)
`5^12 .25^4 .125^3 .625^2=5^12 . (5^2)^4 . (5^3)^3 . (5^4)^2 =5^12 .5^8 .5^9 .5^8=5^37`
Ta có \(125^3.7^5-175^5:5=0\)
\(=>0:2016^{2017}=0\)
= 0 nha