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câu a phải là như z ms làm được bn ơi
A = 31.3+33.5+...+319.2031.3+13.5+...+319.20
\(B=\frac{3}{2}\left(\frac{2}{1.2.3}+\frac{2}{2.3.4}+...+\frac{2}{49.50.51}\right)\)
\(=\frac{3}{2}\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+...+\frac{1}{49.50}-\frac{1}{50.51}\right)\)
\(=\frac{3}{2}\left(\frac{1}{2}-\frac{1}{2550}\right)\)
\(=\frac{3}{2}\cdot\frac{637}{1275}\)
\(=\frac{637}{850}\)
A = 1.2 + 2.3 + ... + 99.100
3A = 1.2.3 + 2.3.(4-1) + ... + 99.100.(101-98)
3A = 1.2.3 + 2.3.4 - 1.2.3 + ... + 99.100.101 - 98.99.100
3A = 99.100.101
3A = 999900
A = 333300
C = 1.2.3 + 2.3.4 + ... + 49.50.51
4C = 1.2.3.4 + 2.3.4.(4-1) + ... + 49.50.51.(52-48)
4c = 1.2.3.4 + 2.3.4.5 - 1.2.3.4 + ... + 49.50.51.52 - 48.49.50.51
4C = 49.50.51.52
4C = 6497400
C = 1624350
`D=1.2.3+2.3.4+3.4.5+....+49.50.51`
`=>4D=1.2.3.4+2.3.4.4+3.4.5.4+.....+49.50.51`
`=>4D=1.2.3.4+2.3.4.(5-1)+3.4.5.(6-2)+.....+49.50.51.(52-48)`
`=>4D=1.2.3.4+2.3.4.5-1.2.3.4+3.4.5.6-2.3.4.5+.....+49.50.51.52-48.49.50.51`
`=>4D=49.50.51.52=49.50.51.13.4`
`=>D=13.49.50.51`
Giải:
\(D=1.2.3+2.3.4+3.4.5+...+49.50.51\)
\(4D=1.2.3.4+2.3.4.\left(5-1\right)+3.4.5.\left(6-2\right)+...+49.50.51.\left(52-48\right)\)
\(4D=1.2.3.3.4+2.3.4.5-2.3.4.1+3.4.5.6-3.4.5.2+...+49.50.51.52-49.50.51.48\)
\(4D=49.50.51.52\)
\(4D=6497400\)
\(D=6497400:4\)
\(D=1624350\)
\(\frac{1}{1.2.3}+\frac{1}{2.3.4}+...+\frac{1}{49.50.51}\)
= \(\frac{2}{1.2.3}+\frac{2}{2.3.4}+...+\frac{2}{49.50.51}\)
= \(\frac{2-1}{1.2.3}+\frac{4-2}{2.3.4}+...+\frac{51-49}{49.50.51}\)
= \(\frac{1}{1.3}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+...+\frac{1}{49.50}-\frac{1}{50.51}\)
= \(\frac{1}{3}-\frac{1}{50.51}\)
= \(\frac{1}{3}-\frac{1}{2550}\)
= \(\frac{283}{850}\)