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a) \(\left[\left(10-2.30.5\right)+2.6\right]:2+\left(4.5\right)^2\)
\(=\left[\left(10-300\right)+2.6\right]:2+20^2\)
\(=\left(-290+2.6\right):2+400\)
\(=\left(-290+12\right):2+400\)
\(=-278:2+400\)
\(=-139+400\)
\(=-\left(139-400\right)\)
\(=-\left(-261\right)\)
\(=261\)
b) \(536.27-9\left(825+219\right):18+15^3:15^2.4^2.3\)
\(=536.27-9.1044:18+15^3:15^2.4^2.3\)
\(=14472-9396:18+15^3:15^2.4^2.3\)
\(=14472-522+15^3:15^2.4^2.3\)
\(=13920+15^{3-2}.4^2.3\)
\(=13920+15.4^2.3\)
\(=13920+15.16.3\)
\(=13920+240.3\)
\(=13920+720\)
\(=14640\)
A)3.5n.52+4.5n:53=19.9765625
5n(3.52+4:53)=185546875
5n.\(\frac{12}{5}\)=185546875
a: \(\Leftrightarrow3\cdot5^n\cdot25+4\cdot5^n\cdot\dfrac{1}{125}=19\cdot5^{10}\)
\(\Leftrightarrow5^n\cdot\left(75+\dfrac{4}{125}\right)=19\cdot5^{10}\)
\(\Leftrightarrow5^n\simeq2472903,228\)(vô lý)
b: \(\Leftrightarrow6^x\cdot11\cdot\dfrac{1}{6}+2\cdot6^x\cdot6=11\cdot6^{11}+2\cdot6^{11}\cdot36\)
\(\Leftrightarrow6^x\left(\dfrac{11}{6}+12\right)=6^{11}\cdot83\)
\(\Leftrightarrow6^x=6^{12}\)
hay x=12
b)11.6x-1+2.6x+1=11.611+2.613
11.6x-1+2.6x+1 = 11. 612-1+ 2. 612+1
=> x= 12
c) 24-x / 165 = 326
24-x / 220= 230
24-x = 250
=> 4-x = 50
x= -46
c) \(\frac{2^{4-x}}{\left(2^4\right)^5}=\left(2^5\right)^6\)
\(2^{4-x}:2^{20}=\left(2^5\right)^6\)
\(2^{4-x}=2^{30}.2^{20}\)
\(2^{4-x}=2^{50}\)
=> \(4-x=50\)
=> \(x=4-50=-46\)
vậy x = -46
mk ko nhớ công thức đâu bn ơi,nhưng mk bt cahcs làm.nếu bn cần thì mk có thể làm giúp bn
b) \(11\cdot6^{x-1}+2\cdot6^{x+1}=11\cdot6^{11}+2\cdot6^{13}\)
\(\Leftrightarrow11\cdot6^{x-1}+2\cdot6^{x+1}=11\cdot6^{12-1}+2\cdot6^{12+1}\)
\(\Leftrightarrow x=12\)