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a) \(x\left(2x-1\right)\left(x+5\right)-\left(2x^2+1\right)\left(x+4,5\right)=3,5\)
\(\Leftrightarrow2x^3-x^2+10x^2-5x-2x^3-x-9x^2-4,5=3,5\)
\(\Leftrightarrow-6x=8\Leftrightarrow x=-\frac{4}{3}\)
b) \(\left(2x-5\right)^2+\left(y-3\right)^2=0\)
\(\Leftrightarrow\hept{\begin{cases}2x-5=0\\y-3=0\end{cases}\Rightarrow\hept{\begin{cases}x=\frac{5}{2}\\y=3\end{cases}}}\)
a) x\left(2x-1\right)\left(x+5\right)-\left(2x^2+1\right)\left(x+4,5\right)=3,5x(2x−1)(x+5)−(2x2+1)(x+4,5)=3,5
\Leftrightarrow2x^3-x^2+10x^2-5x-2x^3-x-9x^2-4,5=3,5⇔2x3−x2+10x2−5x−2x3−x−9x2−4,5=3,5
\Leftrightarrow-6x=8\Leftrightarrow x=-\frac{4}{3}⇔−6x=8⇔x=−34
b) \left(2x-5\right)^2+\left(y-3\right)^2=0(2x−5)2+(y−3)2=0
\(\Leftrightarrow\hept{\begin{cases}2x-5=0\\y-3=0\end{cases}\Rightarrow\hept{\begin{cases}x=\frac{5}{2}\\y=3\end{cases}}}\)
b)3x2 - 3x(x - 2)=36 c) (3x2 - x + 1)(x - 1)+ x2(4 - 3x) = 5/2
3x2 - 3x2 + 6x= 36 3x3 - 3x2 - x2 + x + x - 1 + 4x2 - 3x3= 5/2
6x=36 =>x=36 : 6= 6 (3x3 - 3x3) + (-3x2 - x2 + 4x2) + (x + x) - 1= 5/2
2x - 1= 5/2 =>2x= 5/2 + 1= 7/2
x= 7/2 : 2 =7/4
a) 3x + 2( 5 - x) = 0
3x + 10 - 2x = 0
x + 10 = 0
x = -10.
b) x(2x - 1)(x + 5) - ( 2x2 + 1)(x + 4,5) = 3,5
* x(2x2 +10x-x-5) - (2x3 + 9x2 + x + 4,5)=3,5.
2x3 + 10x2 - x2 -5x- 2x3 - 9x2 -x -4,5=3,5
-6x - 4,5 =3,5
-6x = 8
x = -8/6.
a, \(x\left(x^2+x+1\right)-x^2\left(x+1\right)=2x+5\)
\(\Rightarrow x^3+x^2+x-x^3-x^2-2x=5\)
\(\Rightarrow-x=5\Rightarrow x=-5\)
b, \(\left(x-3\right)\left(x-2\right)-\left(x+1\right)\left(x-5\right)=0\)
\(\Rightarrow x^2-2x-3x+6-\left(x^2-5x+x-5\right)=0\)
\(\Rightarrow x^2-5x+6-x^2+4x+5=0\)
\(\Rightarrow-x=-5-6\Rightarrow x=11\)
c, \(x\left(2x-1\right)\left(x+5\right)-\left(2x^2+1\right)\left(x+4,5\right)=3,5\)
\(\Rightarrow x\left(2x^2+10x-x-5\right)-\left(2x^3+9x^2+x+4,5\right)=3,5\)
\(\Rightarrow2x^3+9x^2-5x-2x^3-9x^2-x-4,5=3,5\)
\(\Rightarrow-6x=3,5+4,5\Rightarrow-6x=8\Rightarrow x=-\dfrac{4}{3}\)
Chúc bạn học tốt!!!
Bạn ơi ở câu a bạn làm sai rùi
\(\left(-x^2\right).\left(-1\right)=+x^2\)chứ sao lại \(-x^2\)
\(a,3x+2\left(5-x\right)=0\)
\(\Rightarrow3x+10-2x=0\)
\(\Rightarrow x+10=0\)
\(\Rightarrow x=-10\)
\(b,x\left(2x-1\right)\left(x+5\right)-\left(2x^2+1\right)\left(x+4,5\right)=3,5\)
\(\Rightarrow\left(2x^2-x\right)\left(x+5\right)-\left(2x^2+1\right)\left(x+4,5\right)=3,5\)
\(\Rightarrow2x^3+9x^2-5x-2x^3-9x^2-4,5=3,5\)
\(\Rightarrow-5x-4,5=3,5\)
\(\Rightarrow-5x=8\)
\(\Rightarrow x=-\dfrac{8}{5}\)
\(c,3x^2-3x\left(x-2\right)=36\)
\(\Rightarrow3x^2-3x^2+6x=36\)
\(\Rightarrow6x=36\)
\(\Rightarrow x=6\)
\(d,\left(3x^2-x+1\right)\left(x-1\right)=x^2\left(4-3x\right)=\dfrac{5}{2}\)
\(\Rightarrow3x^3-3x^2-x^2+x+x-1+4x^2-3x^3=\dfrac{5}{2}\)
\(\Rightarrow2x-1=\dfrac{5}{2}\)
\(\Rightarrow2x=\dfrac{7}{2}\)
\(\Rightarrow x=\dfrac{7}{4}\)