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4|x| + |x| -13 = 2+2|x|
5|x| -13 =2+2|x|
5|x|-2|x| = 2+ 13
3|x| =15
|x| =15:3
|x| = 5
x=-5 hoac x =5
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a) 10 + 2x = 16.4 : 4
=> 10 + 2x = 16
2x = 16 - 10
2x = 6
x = 6:2 = 3
b) 231 - ( x - 6 ) = 1339 : 13
=> 231 - ( x - 6 ) = 103
( x - 6 ) = 231 - 103
x - 6 = 128
x = 128 + 6
x = 134
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\(\left|x-4\right|+\left|x-6\right|=\left|x-4\right|+\left|6-x\right|\ge\left|x-4+6-x\right|=2\)
Dấu "=" xảy ra <=> \(\left(x-4\right)\left(6-x\right)\ge0\)
<=> \(4\le x\le6\)
Vậy....
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Cho mk hỏi nha đề bài là
Tìm số nguyên x, biết :
a/13 bé hơn 4/5 bé hơn a+2/13
nhưng x đâu lại có a
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13 - ( 2 x X - 1) = 4 4 x X - 12 = 40
( 2 x X - 1) = 13 - 4 4 x X = 40 + 12
( 2x X -1) = 9 4 x X = 52
2 x X = 9 + 1 X = 52 : 4
2 x X = 10 X = 13
X = 10 : 2
X = 5
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x^2+4=13
x^2=13-4
x^2=9
x^2=3^2
=> x=3
x^2=13-4
x^2= 9
x=3
Chúc bạn học tốt nhé