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\(\frac{x}{142}+457=625\)
\(\frac{x}{142}=168\)
\(\Rightarrow x=168.142\)
\(\Rightarrow x=23856\)
vậy \(x=23856\)
\(x-16,7+8,6=16,9\)
\(x=16,9-8,6+16,7\)
\(x=25\)
vậy \(x=25\)
\(\left(x-1\frac{3}{4}\right)x:2\frac{1}{4}=\frac{5}{3}\)
\(\left(x-\frac{7}{4}\right)x:\frac{9}{4}=\frac{5}{3}\)
\(x^2-\frac{7}{4}x=\frac{5}{3}.\frac{9}{4}\)
\(x^2-\frac{7}{4}x=\frac{15}{4}\)
\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=1\)
\(x\cdot4+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=1\)
\(x\cdot4+\left(\frac{8}{16}+\frac{4}{16}+\frac{2}{16}+\frac{1}{16}\right)=1\)
\(x\cdot4+\frac{13}{16}=1\)
\(x\cdot4=1-\frac{13}{16}\)
\(x\cdot4=\frac{3}{16}\)
\(x=\frac{3}{16}:4\)
\(x=\frac{3}{64}\)
\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=1\)
\(=\left(x+x+x+x\right)+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=1\)
\(=4x+\frac{15}{16}=1\)
\(\Rightarrow4x=1-\frac{15}{16}=\frac{1}{16}\)
\(\Rightarrow x=\frac{1}{16}:4=\frac{1}{64}\)
\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+...+\left(x+\frac{1}{512}\right)=1\)
\(9x+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{512}\right)=1\)
\(9x+\left[\left(1-\frac{1}{2}\right)+\left(\frac{1}{2}-\frac{1}{4}\right)+\left(\frac{1}{4}-\frac{1}{8}\right)+....+\left(\frac{1}{256}-\frac{1}{512}\right)\right]=1\)
\(9x+\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+...+\frac{1}{512}\right)=1\)
\(9x+\left(1-\frac{1}{512}\right)=1\)
\(9x+\frac{511}{512}=1\)
\(9x=1-\frac{511}{512}\)
\(9x=\frac{1}{512}\)
\(\Rightarrow x=\frac{1}{512}\div9=\frac{1}{4608}\)
X x 2 , 5 + X x 4\(\frac{1}{2}\)+ X x 4 = 24 , 5
X x 2 , 5 + X x 4 , 5 + X x 4 = 24 , 5
X x ( 2 , 5 + 4 , 5 + 4 ) = 24 , 5
X x ( 7 + 4 ) = 24 , 5
X x 11 = 24 , 5
X = 24 , 5 : 11
X = 49/22
Vậy X = 49/22
Tham khảo nha !!!
=Xx2,5+Xx4,5+Xx4=24,5
=Xx(2,5+4,5+4)=24,5
=Xx11=24,5
X=24,5:11
X=49/22.