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a, 2x - 20 = 35 : 32
=> 2x - 1 = 33
=> 2x - 1 = 27
=> 2x = 28
=> x = 14
b, 525.5x + 1 = 525
=> 525+x+1 = 525
=> 25 + x + 1 = 25
=> 26 + x = 25
=> x = -1
a. 2x - 20 = 35 : 32
2x - 1 = 33
2x = 27 + 1
2x = 28
x = 28 : 2
x = 14.
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a) 2x.23 + 2x = 36
=> 2x. (8 + 1) = 36
=> 2x.9 = 36 => 2x = 4 = 22 => x = 2
b) 3x + 3x.32 + 3x.33 = 35.37
=> 3x. (1 + 32 + 33) = 37
=> 3x. 37 = 35.37 => 3x = 35 => x = 5
c) => 52x+ x+2 = 1252.25
=> 53x+2 = (53)2.52 = 58
=> 3x+2 = 8 => 3x = 6 => x = 2
Vậy..
Tìm x , biết:
a, ( 2x + 1)2 = 93
b, ( 2x + 1)3 = 1252
c, 252< 5x+3 < 254
d, x15= x
e, ( x - 5)4 = ( x-5)6
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A) \(\left(2x+1\right)^2=9^3\)
\(\Rightarrow\left(2x+1\right)^2=9^2\times9\)
\(\Rightarrow2x+1=81\)
\(\Rightarrow2x=81-1\)
\(\Rightarrow2x=80\)
\(\Leftrightarrow x=40\)
B) \(\left(2x+1\right)^3=125^2\)
\(\Rightarrow\left(2x+1\right)^3=5^3\)
\(\Rightarrow2x+1=5\)
\(\Rightarrow2x=5-1\)
\(\Leftrightarrow x=2\)
C) \(25^2< 5^{x+3}< 25^4\)
\(\Leftrightarrow5^4< 5^{x+3}< 5^6\)
\(\Leftrightarrow4< x+3< 6\)
\(\Rightarrow x+3=5\)
\(\Rightarrow x=2\)
D) \(x^{15}=x\)
Nếu \(x>1\)thì \(x^{15}>x\)
Vậy \(x=1\)
E) \(\left(x-5\right)^4=\left(x-5\right)^6\)
\(\Rightarrow\left(x-5\right)^4-\left(x-5\right)^6=0\)
\(\Rightarrow\left(x-5\right)\times\left(1^4-1^6\right)=0\)
\(\Rightarrow x-5=0\)
\(\Leftrightarrow x=5\)
KÍCH MK NHA BẠN
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Ta có : 53.5x-2= 252
=> 5x+1=(52)2=54
=> x+1 = 4
=> x=4-1=3
vậy .....
A) 720 : (41 - x) = 23. 5
= 720 : (41 - x) = 40
=> 41-x=720 : 40 = 18
=> x = 41-18=23
vậy x =23
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a)=>48+288:(x-3)^2=50
=>288:(x-3)^2=2
=>(x-3)^2=144
=>x-3=12=>x=15
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a) 154-(x-4)=2*25
154-x+4=50
x+4=104
x=100
b)2346:(25+x)=23
25+x=102
x=77
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a) 2(x-1)^2=800 5^x+1.5^5=5^9
(x-1)^2=800:2 5^x.5.5^5=5^9
(x-1)^2=400 5^x.5^6=5^9
(x-1)^2=20^2 5^x=5^9:5^6
(x-1)=20 5^x=5^3
x=20+1 => x=3
x=21
c) 25^2 : 5(x-1)=25 d)4^x . 7 +8^2=176
625:5(x-1)=25 4^x . 7+64=176
5(x-1)=625:25 4^x . 7=176:64
5(x-1)=25 4^x . 7=112
x-1=25:5 4^x =112:7
x-1=5 4^x=16
x=5+1 mà 16=4^2
x=6 =>4^x=4^2
=>x=2
bài e) mình ko biết !! ^.^
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a) 135 - 5(x + 4) = 35
<=> 135 - 5x - 20 = 35
<=> 115 - 5x = 35
<=> 5x = 115 - 35
<=> 5x = 80
<=> x = 16
b) 25 + 3 (x - 8) = 106
=> 3 ( x - 8) = 106 - 25
=> 3 ( x - 8) = 81
=> ( x - 8) = 81: 3
=> x - 8 = 27
=> x = 27 + 8
=> x = .......
Ta có : 53 . 5x - 2 = 252
=> 53 . 5x - 2 = (52)2
=> 53 . 5x - 2 = 54
=> 5x - 2 = 51
=> x - 2 = 1
=> x = 3
Vậy x = 3
53 . 5x - 2 = 252
=> 5x - 2 + 3 = ( 52 )2
=> 5x + 1 = 54
=> x + 1 = 4
=> x = 3