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\(3^2.3^x.81-27^4=0\)
\(3^2.3^x.3^4-\left(3^3\right)^4=0\)
\(3^6.3^x-3^{12}=0\)
\(3^6.3^x-3^{12}=0\)
\(3^6.3^x=0+3^{12}\)
\(3^6.3^x=3^{12}\)
\(3^{6+x}=3^{12}\)
\(\Rightarrow6+x=12\)
\(x=12-6\)
\(\Rightarrow x=6\)
Bài 1:
2\(x\) = 4
2\(^x\) = 22
\(x=2\)
Vậy \(x=2\)
Bài 2:
2\(^x\) = 8
2\(^x\) = 23
\(x=3\)
Vậy \(x=3\)
=9x2^25-2^2x2^26/2^24x5^2-2^27x3
=9x2^25-2^28/2^24x5^2-2^27x3
=2^25x(9-2^3)/2^24x(5^2-2^3x3)
=2^25/2^24
=2^1=2
a) 25+x=0
x=0-25
x=-25
b)\(2^x:2^{19}=2^{25}\)
\(2^x=2^{25}.2^{19}\)
\(2^x=2^{44}\)
=>x=44
c)\(5^x.5^{18}=5^{54}\)
\(5^x=5^{54}:5^{18}\)
\(5^x=5^{36}\)
=>x=36
a) x=50-37
x= 13
b) 2.x=11+3
2.x=14
x=14:2=7
c) 2+x=6.5
2.x=30
x=30:2=15
e) \(^{^{^{ }}x^9}\)=25
\(\Rightarrow\)x=5
\(\left(x+1\right)^3=27\)
\(\left(x+1\right)^3=3^3\)
\(\Rightarrow x+1=3\)
\(x=2\)
\(\left(x+1\right)^3=27\)
\(< =>\left(x+1\right)^3=3.3.3=3^3\)
\(< =>x+1=3< =>x=3-1=2\)
\(\left(2x+3\right)^3=9.81\)
\(< =>\left(2x+3\right)^3=9.9.9\)
\(< =>\left(2x+3\right)^3=9^3\)
\(< =>2x+3=9< =>2x=6\)
\(< =>x=\frac{6}{2}=3\)
3x+25=26.22+2.50130 mũ 81
=>3x+25=26.4+2.50130m
=>3x+25=26.4+2.1
=>3x+25=104+2
=>3x+25=106
=>3x=81
Mà 3x=81=34
=>x=4