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a. |x-1/5|=|-5/2|-|1/4-2/3|
=> |x-1/5|=5/2-5/12
=> |x-1/5|=25/12
+) x-1/5=25/12
=> x=137/60
+) x-1/5=-25/12
=> x=-113/60
Vậy x \(\in\){-113/60 ; 137/60}
b. (x-0,5).(x2-1,96)=0
+) x-0,5=0
=> x=0,5
+) x2-1,96=0
=> x2=1,96
=> x2=(7/5)2=(-7/5)2
=> x \(\in\left\{-\frac{7}{5};\frac{7}{5}\right\}\)
Vậy \(x\in\left\{-\frac{7}{5};0,5;\frac{7}{5}\right\}\).
c. 5/6 : x = 20 : 3
=> 5/6 : x = 20/3
=> x = 5/6 : 20/3
=> x=1/8
Vậy x=1/8.
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\(\left(\frac{1}{4}x-1,5\right)+\left(\frac{5}{6}-3\right)-\left(\frac{5}{8}x-0,5\right)=45\)
\(\frac{1}{4}x-1,5-\frac{13}{6}-\frac{5}{8}x+0,5=45\)
\(-\frac{3}{8}x-\frac{19}{6}=45\)
\(-\frac{3}{8}x=\frac{289}{6}\)
\(\Rightarrow x=-\frac{1156}{9}\)
cảm ơn bạn anh nha mà cho em hỏi tại sao x lại ghép đc với nhau z?
a) \(\left|x-1\right|=5\)
\(\Rightarrow\orbr{\begin{cases}x-1=5\\x-1=-5\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=6\\x=-4\end{cases}}\)
b) \(\left|x-0,5\right|=2,4\)
\(\Rightarrow\orbr{\begin{cases}x-0,5=2,4\\x-0,5=-2,4\end{cases}}\Rightarrow\orbr{\begin{cases}x=2,9\\x=-1,9\end{cases}}\)
c) \(2\left|3x-1\right|-1=6\)
\(\Leftrightarrow2\left|3x-1\right|=7\)
\(\Leftrightarrow\left|3x-1\right|=3,5\)
\(\Rightarrow\orbr{\begin{cases}3x-1=3,5\\3x-1=-3,5\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}3x=4,5\\2x=-2,5\end{cases}\Rightarrow\orbr{\begin{cases}x=1,5\\-1,25\end{cases}}}\)
\(a.=\left(\frac{83}{5}-\frac{68}{5}\right).-\frac{1}{3}+\frac{3}{4}\)
\(=\frac{15}{5}.-\frac{1}{3}+\frac{3}{4}\)
\(=3.-\frac{1}{3}+\frac{3}{4}\)
\(=-1+\frac{3}{4}\)
\(=-\frac{1}{4}\)
a) \(\frac{3}{4}+\frac{1}{4}.x=\frac{1}{2}+\frac{1}{2}x\)
\(\Rightarrow3.\frac{1}{4}+\frac{1}{4}.x=\frac{1}{2}.\left(x+1\right)\)
\(\Rightarrow\frac{1}{4}.\left(x+3\right)=\frac{1}{2}.\left(x+1\right)\)
\(\Rightarrow\frac{x+1}{x+3}=\frac{1}{4}:\frac{1}{2}=\frac{1}{2}\)\(\Rightarrow\left(x+1\right).2=x+3\Rightarrow2x+2=x+3\)
\(\Rightarrow2x-x=3-2\Rightarrow x=1\)
vay x=1
a)
\(\begin{array}{l}\frac{2}{9}:x + \frac{5}{6} = 0,5\\\frac{2}{9}:x = \frac{1}{2} - \frac{5}{6}\\\frac{2}{9}:x = \frac{3}{6} - \frac{5}{6}\\\frac{2}{9}:x = \frac{{ - 2}}{6}\\x = \frac{2}{9}:\frac{{ - 2}}{6}\\x = \frac{2}{9}.\frac{{ - 6}}{2}\\x = \frac{{ - 2}}{3}\end{array}\)
Vậy \(x = \frac{{ - 2}}{3}\).
b)
\(\begin{array}{l}\frac{3}{4} - \left( {x - \frac{2}{3}} \right) = 1\frac{1}{3}\\x - \frac{2}{3} = \frac{3}{4} - 1\frac{1}{3}\\x - \frac{2}{3} = \frac{3}{4} - \frac{4}{3}\\x - \frac{2}{3} = \frac{9}{{12}} - \frac{{16}}{{12}}\\x - \frac{2}{3} = \frac{{ - 7}}{{12}}\\x = \frac{{ - 7}}{{12}} + \frac{2}{3}\\x = \frac{{ - 7}}{{12}} + \frac{8}{{12}}\\x = \frac{1}{12}\end{array}\)
Vậy\(x = \frac{1}{12}\).
c)
\(\begin{array}{l}1\frac{1}{4}:\left( {x - \frac{2}{3}} \right) = 0,75\\\frac{5}{4}:\left( {x - \frac{2}{3}} \right) = \frac{3}{4}\\x - \frac{2}{3} = \frac{5}{4}:\frac{3}{4}\\x - \frac{2}{3} = \frac{5}{4}.\frac{4}{3}\\x - \frac{2}{3} = \frac{5}{3}\\x = \frac{5}{3} + \frac{2}{3}\\x = \frac{7}{3}\end{array}\)
Vậy \(x = \frac{7}{3}\).
d)
\(\begin{array}{l}\left( { - \frac{5}{6}x + \frac{5}{4}} \right):\frac{3}{2} = \frac{4}{3}\\ - \frac{5}{6}x + \frac{5}{4} = \frac{4}{3}.\frac{3}{2}\\ - \frac{5}{6}x + \frac{5}{4} = 2\\ - \frac{5}{6}x = 2 - \frac{5}{4}\\ - \frac{5}{6}x = \frac{8}{4} - \frac{5}{4}\\ - \frac{5}{6}x = \frac{3}{4}\\x = \frac{3}{4}:\left( { - \frac{5}{6}} \right)\\x = \frac{3}{4}.\frac{{ - 6}}{5}\\x = \frac{{ - 9}}{{10}}\end{array}\)
Vậy \(x = \frac{{ - 9}}{{10}}\).
a) |x-1|=5
1) x-1 = 5
x= 6
2) x-1 = -5
x= -4
Vậy x= 5 hoặc x= -4
b) tương tự câu a
c) ) 2|3x-1|-1=6
2|3x-1| = 7
|3x-1| = 7/2
1) 3x - 1 = 7/2
3x = 9/2
x= 9/2.1/3
x= 3/2
2) 3x - 1 = -7/2
3x = -5/2
x= -5/2 . 1/3
x= -5/6
Vậy x = 3/2 hoặc x= -5/6
a)vì |x-1|=5 nên x-1=5 hoặc x-1=-5
Th1:x-1=5 suy ra x=5+1=6
Th2:x-1=-5 suy ra x=-5+1=-4
Vậy x=6 hoặc x=-4
Phần b+c tương tự
1)\(x+0,5+x+1,5+x+2,5=33\)
\(\Leftrightarrow3x=33-0,5-1,5-2,5=28,5\)
\(\Leftrightarrow x=9,5\)
2)\(\left(x+0,9\right)\left(1-0,4\right)=2412\)
\(\Leftrightarrow\left(x+0,9\right)\cdot0,6=2412\)
\(\Leftrightarrow x+0,9=4020\)
\(\Leftrightarrow x=1019,1\)
1/3 - 5/6 ( x + 1 ) = 0,5
1/3 - 5/6 ( x + 1 ) = 1/2
5/6 ( x + 1 ) = 1/3 - 1/2
5/6 ( x + 1 ) = -1/6
x + 1 = -1/6 : 5/6
x +1 = -1/5
x = -1/5 - 1
x = -6/5
\(\frac{1}{3}-\frac{5}{6}.\left(x+1\right)=0.5\)
\(\frac{5}{6}.\left(x+1\right)=\frac{1}{3}-0.5\)
\(\frac{5}{6}.\left(x+1\right)=\frac{-1}{6}\)
\(x+1=\frac{-1}{6}:\frac{5}{6}\)
\(x+1=\frac{-1}{5}\)
\(x=\frac{-1}{5}-1\)
\(x=\frac{-6}{5}\)
Vậy \(x=\frac{-6}{5}\)
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