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Tìm x :
\(5x+x=39-3^{11}:3^9\)
\(6x=39-3^2\)
\(6x=39-9\)
\(6x=30\)
\(x=30:6\)
\(x=5\)
Thực hiện phép tính :
\(225:3^2+4^3.125-125:5^2\)
\(=225:9+64.125-125:25\)
\(=25+8000-5\)
\(=8020\)
a, 6x=39-3^2 b,225:9+64.125-125:25
6x=39-9 =25+64.125-125:25
6x=30 =25+8000-125:25
x=30:6 =25+8000-5
x=5 =8020
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\(\frac{\left(3-x\right)^{10x}}{\left(3-x\right)^{20}}=1\Leftrightarrow\left(3-x\right)^{10x-20}=\left(3-x\right)^{10\left(x-2\right)}=1\\ \)
\(\orbr{\begin{cases}x-2=0=>x=2\\3-x=+-1\orbr{\begin{cases}x=2\\x=4\end{cases}}\end{cases}}\)\(\orbr{\begin{cases}x-2=0\Rightarrow x=2\\3-x=!1!\end{cases}}\)\(\orbr{\begin{cases}x=2\\x=4\end{cases}}\)
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Bài 1 :
a) 5x = 125
=> 5x = 53
=> x = 3
b) 34 . 3x = 37
=> 4 + x = 7
=> x = 7 - 4
=> x = 2
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\(\left(3x-15\right)^7=0\Rightarrow3x-15=0\)
\(\Rightarrow3x=15\)
\(\Rightarrow x=5\)
\(4^2.x-6=1\Rightarrow16.x=7\)
\(\Rightarrow x=\frac{7}{16}\)
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\(2^x=32=>x=5\)
\(2^{x+1}=32=>x+1=5=>x=4\)
\(x^3=125=>x=5\)
\(\left(x+1\right)^3=125=>x+1=5=>x=4\)
3. x3 = 125 => x = 5
4. (x + 1)3 = 125
(x + 1)3 = 53
=> x + 1 = 5
=> x = 4
t i c k nhé!! 45457474678789886973463125135153152454654657657868768
\(X=\sqrt[3]{125}\)---> X=5
11x3-125=103
<=>11x3-10x3=125
<=>x3=125
<=>x=5