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a)-Ix-3I+16=4
-Ix-3I=4-16
-Ix-3I=-12
-IxI=-12+3
-IxI=-9
x=-9
b)3-(17-x)=289-(36+289)
3-(17-x)=289-325
3-(17-x)=-36
(17-x)=3-(-36)
(17-x)=39
x=17-39
x=-22
c)25-(x+5)=415-(15-415)
25-(x+5)=415-(-400)
25-(x+5)=815
(x+5)=25-815
(x+5)=-790
x=(-790)-5
x=-795
d)34+(21-x)=(3747-30)-3746
34+(21-x)=3717-3746
34+(21-x)=-29
31+x=21-(-29)
31+x=50
x=50-31
x=19
3-(17-x)=289-(36+289)
<=> 3-17+x=289-36-289
<=> -14+x=-36 => x=-22
25-(x+5)=-45-(15-45)
<=> 25-x-5=-45-15+45
<=> 20-x=-15=> x=35
34-(21-x)=(3747-30)-3747
<=> 334-21+x=3747-30-3747
<=> 313+x=-30=> x=-343
3 - ( 17 - x ) = 289 - ( 36 + 289 )
3 - 17 + x = 289 - 36 - 289
- 14 + x = - 36
x = ( - 36 ) - ( - 14 )
x= - 22
25 - ( x + 5 ) = - 45 - ( 15 - 45)
25 - x - 5 = - 45 - 15 + 45
20 - x = - 15
x = 20 - ( - 15 )
x = 35
34 - ( 21 - x ) = ( 3747 - 30 ) - 3747
34 - 21 + x = 3747 - 30 - 3747
13 + x = - 30
x = ( - 30 ) - 13
x = - 46
34+(21-x)=(3747-30)-3746
34+(21-x)=3717-3746
34+(21-x)=-29
21-x=-29-34
21-x=-63
x=21-(-63)
x=21+63
x=84
(x+153)-(48-193)=1-2-3-4
(x+153)-(48-193)=-8
(x+153)-(-145)=-8
(x+153)+145=-8
x+153=-8-145
x+153=-153
x=-153-153
x=0
35-(x+5)=315-(2x+135)
213-(x+84)= -161
x+84=213-(-161)
x+84=213+161
x+84=374
x=374-84
x=290
1,
a) |x| + |y + 1| =0
Ta có: |x| \(\ge\) 0 (Với x \(\in\) Z)
|y + 1| \(\ge\) 0 (Với y\(\in\) Z)
\(\Rightarrow\) |x| + |y + 1| \(\ge\) 0
Dấu "=" xảy ra (=):
\(\left\{\begin{matrix}\left|x\right|=0\\\left|y+1\right|=0\end{matrix}\right.\Rightarrow\left\{\begin{matrix}x=0\\y+1=0\end{matrix}\right.\Rightarrow}\left\{\begin{matrix}x=0\\y=0-1\end{matrix}\right.\Rightarrow}\left\{\begin{matrix}x=0\\y=-1\end{matrix}\right.\)
Vậy x = 0; y = -1
b) (2 - x)4 = 81
\(\Rightarrow\) (2 - x)4 = 34 = (-3)4
\(\Rightarrow\) \(\left[\begin{matrix}2-x=3\\2-x=-3\end{matrix}\right.\Rightarrow\left[\begin{matrix}x=2-3\\x=2-\left(-3\right)\end{matrix}\right.\Rightarrow\left[\begin{matrix}x=-1\\x=5\end{matrix}\right.\)
Vậy: x \(\in\) {-1; 5}
c) |x - 1| + (-3) = 17
\(\Rightarrow\) |x - 1| = 17 - (-3)
\(\Rightarrow\) |x - 1| = 20
\(\Rightarrow\left[\begin{matrix}x-1=-20\\x-1=20\end{matrix}\right.\Rightarrow\left[\begin{matrix}x=-20+1\\x=20+1\end{matrix}\right.\Rightarrow\left[\begin{matrix}x=-19\\x=21\end{matrix}\right.\)
Vậy: x \(\in\) {-19; 21}
d) 3 - (17 - x) = 289 - (36 + 289)
\(\Rightarrow\) 3 - (17 - x) = 289 - 36 - 289
\(\Rightarrow\) 3 - (17 - x) = 0 - 36
a) 34+21-x=3747-30-3747
=>55-x=-30
=>-x=-85
=>x=85
b)17-{-x-[-x-(-x)]}=-16
=>17-{-x-[-x+x]}=-16
=>17-{-x-0}=-16
=>17+x=-16
=>x=-33