Question

[Vu Hai Anh]

Tìm x :

\(\left(\frac{2}{3}\right)^{x+2}=\left(\frac{4}{9}\right)^4\)

Làm đi mình tick

Answer 1

[Nguyễn Tấn Phát]

\(\left(\frac{2}{3}\right)^{x+2}=\left(\frac{4}{9}\right)^4\)

\(\left(\frac{2}{3}\right)^{x+2}=\left[\left(\frac{2}{3}\right)^2\right]^4\)

\(\left(\frac{2}{3}\right)^{x+2}=\left(\frac{2}{3}\right)^8\)

\(\Rightarrow x+2=8\)

Vậy \(x=6\)

Answer 2

[T.Ps]

#)Giải :

Ta có : \(\left(\frac{4}{9}\right)^4=\left[\left(\frac{2}{3}\right)^2\right]^4=\left(\frac{2}{3}^8\right)\)

\(\left(\frac{2}{3}\right)^{x+2}=\left(\frac{2}{3}\right)^8\)

\(\Leftrightarrow x+2=8\)

\(\Leftrightarrow x=6\)