Question

[bé bảo]

tìm x \(\in\)N

1, \(x^2.x^3=3^7:3^2\)

2, \(x-18:3=12\)

3,\(\left(x-18\right):2=12\)

4,\(x^2=16\)

5,\(\left(2x+2^4\right).5^3\)

6,\(\left(3x-48\right).6=3^3.2^2+2^2.3^2=12^2\)

7,\(1170:\left(x-13\right)=339-3.10^2\)

8,\(\left(x-1\right).11=33\)

9,\(3.\left(x-9\right)+15=12+243:3^2\)

10,\(30:\left(x-7\right)=15^9:15^8\)

Answer 1

[Vĩnh Thụy]

1, x^2 . x^3 = 3^7 : 3^2

       x^5     = 3^5

=> x = 3

2, x - 18 : 3 = 12

    x - 6       = 12

    x            = 12 + 6

    x            = 18

3, (x - 18) : 2 = 12

     x - 18       = 12 . 2

     x - 18       = 24

     x             = 24 + 18

     x             = 42

4, x^2 = 16

    x^2 = 4^2

=> x = 4

Answer 2

[do thu ha]

x=4 nha bn

k k nha

mk k lại cho!