\(\dfrac{20}{x-3}\) = \(\dfrac{18}{x+2}\)

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28 tháng 6 2017

bài 3:

a, đặt \(\dfrac{x}{12}=\dfrac{y}{9}=\dfrac{z}{5}=k\)

=>x=12k,y=9k,z=5k

ta có: ayz=20=> 12k.9k.5k=20

=> (12.9.5)k^3=20

=>540.k^3=20

=>k^3=20/540=1/27

=>k=1/3

=>x=12.1/3=4

y=9.1/3=3

z=5.1/3=5/3

vậy x=4,y=3,z=5/3

b,ta có: \(\dfrac{x}{5}=\dfrac{y}{7}=\dfrac{z}{3}=\dfrac{x^2}{25}=\dfrac{y^2}{49}=\dfrac{z^2}{9}\)

A/D tính chất dãy tỉ số bằng nhau ta có:

\(\dfrac{x}{5}=\dfrac{y}{7}=\dfrac{z}{3}=\dfrac{x^2}{25}=\dfrac{y^2}{49}=\dfrac{z^2}{9}=\dfrac{x^2+y^2-z^2}{25+49-9}=\dfrac{585}{65}=9\)

=>x=5.9=45

y=7.9=63

z=3*9=27

vậy x=45,y=63,z=27

28 tháng 6 2017

Theo mình thì bạn nên đăng từng câu hỏi chứ đăng 1 lượt thế này có 1 số bạn thấy dài quá ko mún làm và mình cũng ở trong số đó.vui

11 tháng 7 2017

giúp zới

khocroi

15 tháng 4 2018

c)

\(\left|\dfrac{2}{3}x-\dfrac{1}{2}\right|-1=\dfrac{5}{6}\)

\(\Leftrightarrow\left|\dfrac{4x-3}{6}\right|=1+\dfrac{5}{6}=\dfrac{11}{6}\)

\(\Leftrightarrow\left|4x-3\right|=11\Leftrightarrow\left[{}\begin{matrix}4x-3=11=>x=\dfrac{11+3}{4}=\dfrac{7}{2}\\4x-3=-11=>x=\dfrac{-8}{2}=-4\end{matrix}\right.\)

a: \(\dfrac{x+2}{27}=\dfrac{x}{-9}\)

=>x+2=-3x

=>4x=-2

hay x=-1/2

b: \(\dfrac{-7}{x}=\dfrac{21}{34-x}\)

=>-7(34-x)=21x

=>34-x=-3x

=>2x=-34

hay x=-17

c: \(\dfrac{-8}{15}< \dfrac{x}{40}< \dfrac{-7}{15}\)

\(\Leftrightarrow-64< 3x< -56\)

hay \(x\in\left\{-21;-20;-19\right\}\)

d: \(\dfrac{-1}{2}< \dfrac{x}{18}< \dfrac{-1}{3}\)

=>-9<x<-6

hay \(x\in\left\{-8;-7\right\}\)

8 tháng 8 2018

1) \(x:\dfrac{2}{3}=150\)

\(\Leftrightarrow x=150.\dfrac{2}{3}\)

\(\Leftrightarrow x=100\).

2) \(\dfrac{35}{9}:x=\dfrac{35}{6}\)

\(\Leftrightarrow x=\dfrac{35}{9}:\dfrac{35}{6}\)

\(\Leftrightarrow x=\dfrac{2}{3}\).

3) \(\dfrac{49}{7}:x=\dfrac{49}{5}\)

\(\Leftrightarrow x=\dfrac{49}{7}:\dfrac{49}{5}\)

\(\Leftrightarrow x=\dfrac{5}{7}\).

4) \(1-\left\{5\dfrac{4}{9}+x-7\dfrac{7}{18}\right\}:15\dfrac{3}{5}=0\)

\(\Leftrightarrow1-\left\{\dfrac{49}{9}+x-\dfrac{133}{18}\right\}:\dfrac{78}{5}=0\)

\(\Leftrightarrow\left\{\dfrac{-35}{18}+x\right\}:\dfrac{78}{5}=1-0\)

\(\Rightarrow\dfrac{-35}{18}+x=1.\dfrac{78}{5}\)

\(\Leftrightarrow\dfrac{-35}{18}+x=\dfrac{78}{5}\)

\(\Rightarrow x=\dfrac{1579}{90}\).

8 tháng 8 2018

Gọi a,b,c.. cho dễ nhé.Thớt vui tính quá, dấu phẩy cũng không viết hộ con dân =)))

a, \(x:\dfrac{2}{3}=150\)

\(\Leftrightarrow x=150.\dfrac{2}{3}\)

\(\Leftrightarrow x=100\)

Vậy...

b, \(\dfrac{35}{9}:x=\dfrac{35}{6}\)

\(\Leftrightarrow x=\dfrac{35}{9}:\dfrac{35}{6}\)

\(\Leftrightarrow x=\dfrac{2}{3}\)

Vậy...

c, \(\dfrac{49}{7}:x=\dfrac{49}{5}\)

\(\Leftrightarrow x=\dfrac{49}{7}:\dfrac{49}{5}\)

\(\Leftrightarrow x=\dfrac{5}{7}\) Vậy...

d, \(1-\left\{5\dfrac{4}{9}+x-7\dfrac{7}{18}\right\}:15\dfrac{3}{4}=0\)

\(\Leftrightarrow1-\left\{\dfrac{49}{9}+x-\dfrac{133}{18}\right\}:\dfrac{63}{4}=0\)

\(\Leftrightarrow1-\left\{x-\dfrac{35}{18}\right\}:\dfrac{63}{4}=0\)

\(\Leftrightarrow1-\left(\dfrac{\left(18x-35\right).4}{18.63}\right)=0\)

\(\Leftrightarrow1-\left(\dfrac{72x-140}{1134}\right)=0\)

\(\Leftrightarrow1-\dfrac{72x-140}{1134}=0\)

\(\Leftrightarrow\dfrac{1134-72x+140}{1134}=0\)

\(\Leftrightarrow1274-72x=0\)

\(\Leftrightarrow72x=1274\)

\(\Leftrightarrow x=\dfrac{637}{36}\)

Vậy...

26 tháng 6 2017

Bài 2: a) \(\dfrac{x-3}{x+5}=\dfrac{5}{7}\)

\(\Leftrightarrow\left(x-3\right).7=\left(x+5\right).5\)

\(\Leftrightarrow7x-21=5x+25\)

\(\Leftrightarrow7x-5x=21+25\)

\(\Leftrightarrow2x=46\)

\(\Rightarrow x=46:2=23\)

b) \(\dfrac{7}{x-1}=\dfrac{x+1}{9}\)

\(\Leftrightarrow\left(x+1\right)\left(x-1\right)=63\)

\(\Leftrightarrow x^2-1=63\)

\(\Leftrightarrow x^2=64\)

\(\Rightarrow x^2=\left(\pm8\right)^2\)

\(\Rightarrow x=8\) hoặc \(x=-8\)

26 tháng 6 2017

2)a) \(\dfrac{x-3}{x+5}=\dfrac{5}{7}\)

\(\Leftrightarrow7\left(x-3\right)=5\left(x+5\right)\)

\(7x-21=5x+25\)

\(7x-5x+25=21\)

\(2x+25=21\)

\(2x=-4\Rightarrow x=-2\)

b) \(\dfrac{7}{x-1}=\dfrac{x+1}{9}\)

\(7.9=\left(x+1\right)\left(x-1\right)\)

\(63=x\left(x-1\right)+1\left(x-1\right)\)

\(63=x^2-x+x-1\)

\(x^2=63+1=64\)

\(x=\left\{\pm8\right\}\)

c) \(\dfrac{x+4}{20}=\dfrac{2}{x+4}\)

\(\Leftrightarrow\left(x+4\right)\left(x+4\right)=2.20=40\)

\(x\left(x+4\right)+4\left(x+4\right)=40\)

\(x^2+4x+4x+16=40\)

\(x^2+8x=40-16=24\)

\(x\left(x+8\right)=24\)

\(x\in\left\{\varnothing\right\}\)

d) \(\dfrac{x-1}{x+2}=\dfrac{x-2}{x+3}\)

\(\Leftrightarrow\left(x+2\right)\left(x-2\right)=\left(x-1\right)\left(x+3\right)\)

\(x\left(x-2\right)+2\left(x-2\right)=x\left(x+3\right)-1\left(x+3\right)\)

\(x^2-2x+2x-4=x^2+3x-x-3\)

\(\)\(x^2-4=x^2+2x-3\)

\(\Leftrightarrow x^2-x^2-2x+3=4\)

\(-2x+3=4\)

\(-2x=1\)

\(x=-\dfrac{1}{2}\)

26 tháng 3 2017

a)\(\dfrac{3}{10}\)-x=\(\dfrac{25}{30}\)-\(\dfrac{4}{30}\)

\(\dfrac{3}{10}-x=\dfrac{7}{10}\)

x = \(\dfrac{3}{10}-\dfrac{7}{10}\)

x=\(\dfrac{-4}{10}\)

b)\(\dfrac{-5}{8}+x=\dfrac{4}{9}-\dfrac{63}{9}\)

\(\dfrac{-5}{9}+x=\dfrac{-59}{9}\)

\(x=\dfrac{-59}{9}-\dfrac{-5}{9}\)

\(x=\dfrac{-64}{9}\)

26 tháng 3 2017

c)=>2.18=(x-3).(x-3)

=>36=(x-3)\(^2\)

=>6\(^2\)=(x-3)\(^2\)

6= x-3

x=6+3=9

29 tháng 3 2017

Giải:

a) \(\dfrac{4}{9}-\dfrac{7}{8}.x=-\dfrac{2}{3}\)

\(\dfrac{7}{8}x=\dfrac{4}{9}-\dfrac{-2}{3}\)

\(x=\dfrac{10}{9}:\dfrac{7}{8}\)

\(x=\dfrac{80}{63}\)

b) \(\dfrac{1}{6}+\dfrac{-5}{7}:x=\dfrac{-7}{8}\)

\(-\dfrac{5}{7}:x=\dfrac{-7}{8}-\dfrac{1}{6}\)

\(\dfrac{-5}{7}:x=\dfrac{-5}{9}\)

\(x=\dfrac{-5}{7}:\dfrac{-5}{9}\)

\(x=\dfrac{9}{7}\)

29 tháng 3 2017

\(\dfrac{4}{9}-\dfrac{7}{8}.x=\dfrac{-2}{3}\)

\(\dfrac{7}{8}.x=\dfrac{4}{9}-\left(-\dfrac{2}{3}\right)\)

\(\dfrac{7}{8}.x=\dfrac{10}{9}\)

\(x=\dfrac{10}{9}:\dfrac{7}{8}\)

\(x=\dfrac{80}{63}\)
Vậy:\(x=\dfrac{80}{63}\)

\(\dfrac{1}{6}+\dfrac{-5}{7}:x=\dfrac{-7}{18}\)

\(\dfrac{-5}{7}:x=\dfrac{-7}{18}-\dfrac{1}{6}\)

\(\dfrac{-5}{7}:x=\dfrac{-5}{9}\)

x=\(\dfrac{-5}{7}:\dfrac{-5}{9}\)

x= \(\dfrac{9}{7}\)

Vậy x=\(\dfrac{9}{7}\)

11 tháng 7 2017

\(a.-8:\left(4\dfrac{1}{5}x+\dfrac{3}{10}\right)=4\dfrac{4}{9}\)

\(4\dfrac{1}{5}x+\dfrac{3}{10}=\left(-8\right):4\dfrac{4}{9}\)

\(4\dfrac{1}{5}x+\dfrac{3}{10}=\dfrac{-9}{5}\)

\(4\dfrac{1}{5}x=\dfrac{-9}{5}-\dfrac{3}{10}\)

\(4\dfrac{1}{5}x=\dfrac{-21}{10}\)

\(x=\dfrac{-21}{10}:\dfrac{21}{5}\)

\(x=\dfrac{-1}{2}\)

Vay \(x=\dfrac{-1}{2}\).

\(b.4\dfrac{2}{3}-\left(\dfrac{3}{5}:x\right)=-20\%\)

\(\dfrac{14}{3}-\left(\dfrac{3}{5}:x\right)=\dfrac{-1}{5}\)

\(\dfrac{3}{5}:x=\dfrac{14}{3}-\dfrac{-1}{5}\)

\(\dfrac{3}{5}:x=\dfrac{73}{15}\)

\(x=\dfrac{3}{5}:\dfrac{73}{15}\)

\(x=\dfrac{9}{73}\)

Vay \(x=\dfrac{9}{73}\).

Câu c; d; e tương tự nhé.

a: \(=\dfrac{-28}{36}+\dfrac{15}{36}-\dfrac{26}{36}=\dfrac{-39}{36}=\dfrac{-13}{12}\)

b: \(=\dfrac{11}{9}\left(\dfrac{15}{4}-\dfrac{7}{4}-\dfrac{5}{4}\right)=\dfrac{11}{9}\cdot\dfrac{3}{4}=\dfrac{11}{12}\)

c: \(=15+\dfrac{9}{7}+6+\dfrac{2}{3}-5-\dfrac{5}{9}\)

\(=16+\dfrac{88}{63}=\dfrac{1096}{63}\)

d: \(=\dfrac{5}{6}-\dfrac{1}{3}+\dfrac{2}{18}\)

\(=\dfrac{15-6+2}{18}=\dfrac{11}{18}\)