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3/5 - 1/3 x (2,48 + 0,52) x y : 60 : 5 = 1/5
1/3 x (2,48+0,52) x y : 60 : 5 = 2/5
1/3 x 3 x y : 60 : 5 = 2/5
y: 60 : 5 =2/5
y: 60 =2/5 x 5
y : 60 =2
y = 2 x 60
y =120
Ta có: \(\dfrac{3}{5}-\dfrac{1}{3}\left(2.48+0.52\right)\cdot y:60:5=\dfrac{1}{5}\)
\(\Leftrightarrow\dfrac{3}{5}-\dfrac{1}{3}\cdot3\cdot y\cdot\dfrac{1}{60}\cdot\dfrac{1}{5}=\dfrac{1}{5}\)
\(\Leftrightarrow y\cdot\dfrac{1}{300}=\dfrac{2}{5}\)
hay y=120
\(\left(x+\dfrac{1}{3}\right)\times\dfrac{9}{14}\times\dfrac{7}{3}-\dfrac{1}{3}=1:\dfrac{9}{5}\\ \Rightarrow\left(x+\dfrac{1}{3}\right)\times\dfrac{3}{2}-\dfrac{1}{3}=\dfrac{5}{9}\\ \Rightarrow\left(x+\dfrac{1}{3}\right)\times\dfrac{3}{2}=\dfrac{5}{9}+\dfrac{1}{3}\\ \Rightarrow\left(x+\dfrac{1}{3}\right)\times\dfrac{3}{2}=\dfrac{8}{9}\\ \Rightarrow x+\dfrac{1}{3}=\dfrac{8}{9}:\dfrac{3}{2}\\ \Rightarrow x+\dfrac{1}{3}=\dfrac{16}{27}\\ \Rightarrow x=\dfrac{16}{27}-\dfrac{1}{3}\\ \Rightarrow x=\dfrac{7}{27}\)
\(8,75\times x+1,25\times x=20\)
\(\left(8,75+1,25\right)\times x=20\)
\(10\times x=20\)
\(x=20:10\)
\(x=2\)
Vậy \(x=2\)
Cjhucs bạn học tốt !!!
8,75x X + 1,25 x X = 20
X x ( 8,75 + 1,25 ) = 20
X x 10 = 20
X = 20 : 10
X = 2 Vậy X= 2
\(1\)\(\frac{1}{3}x1\)\(\frac{1}{4}x1\)\(\frac{1}{5}x...x1\)\(\frac{1}{8}\)
\(=\frac{4}{3}x\)\(\frac{5}{4}x\)\(\frac{6}{5}\)\(x...x\)\(\frac{9}{8}\)
Tự tính nốt
\(1\frac{1}{3}\times1\frac{1}{4}\times1\frac{1}{5}\times1\frac{1}{6}\times1\frac{1}{7}\times1\frac{1}{8}.\)
= \(\frac{4}{3}\times\frac{5}{4}\times\frac{6}{5}\times\frac{7}{6}\times\frac{8}{7}\times\frac{9}{8}\times\frac{10}{9}\)
= \(\frac{4\times5\times6\times7\times8\times9\times10}{3\times4\times5\times6\times7\times8\times9}\)
= \(\frac{10}{3}\)
x:(1.24+3.56)-0.249=1.451
x:4,8-0,249 =1,451
x:4,8 =1,451 +0,249
x:4,8 =1,7
x =1,7 x 4,8
x =8,16
x : ( 1.24 + 3.56) - 0.249 = 1.451
x : ( 1.24 + 3.56) = 1.451 + 0.249
x : ( 1.24 + 3.56) = 1.7
x : 4.8 = 1.7
x = 1.7 x 4.8
x = 8.16
k mình nhé !!!
\(x+x+x\times1+x\times6=120\\ x\times\left(1+1+1+6\right)=120\\ x\times9=120\\ x=\dfrac{120}{9}\\ x=\dfrac{40}{3}\)
\(x+x+x\text{×}1+x\text{×}6=120\)
\(x\text{×}\left(1+1+1\right)+x\text{×}6=120\)
\(x\text{×}3+x\text{×}6=120\)
\(x\text{×}\left(3+6\right)=120\)
\(x\text{×}9=120\)
\(x=\dfrac{120}{9}\)