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\(\frac{4}{7}x-\frac{2}{3}=\frac{1}{5}\)
\(\frac{4}{7}x=\frac{13}{15}\)
\(x=\frac{91}{60}\)
\(\frac{4}{5}+\frac{5}{7}:x=\frac{1}{6}\)
\(\frac{5}{7}:x=-\frac{19}{30}\)
\(x=-\frac{150}{133}\)
=.= hk tốt!!
a)\(10\left(x-7\right)-8\left(x+5\right)=6\cdot\left(-5\right)+24\)
\(10x-10\cdot7-8x-8\cdot5=\left(-30\right)+24\)
\(10x-70-8x-40=-6\)
\(10x-8x=\left(-6\right)+70+40\)
\(2x=104\)
\(x=104\div2\)
\(x=52\)
b)\(2\left(4x-8\right)-7\left(3+x\right)=6\)
\(2\cdot4x-2\cdot8-7\cdot3-7x=6\)
\(8x-16-21-7x=6\)
\(8x-7x=6+16+21\)
\(x=43\)
1. \(\frac{x-5}{y-4}\) = \(\frac{5}{4}\)
=> ( x - 5 )4 = ( y - 4 )5
4x - 20 = 5y - 20
4x = 5y - 20 + 20
4x = 5y (1)
Theo bài ra , ta có x - y = 6 nên x = y + 6 (2)
Thay (2) vào (1) , có 4x = 5y <=> 4( y + 6 ) = 5y <=> 4y + 24 = 5y
=> 24 = 5y - 4y => 5y - 4y = 24 => y = 24
Thay y = 24 vào (2) ta đc : x = 24 + 6 = 30
Vậy \(\frac{x}{y}\) = \(\frac{30}{24}\) = \(\frac{5}{4}\)
câu a : \(\frac{1}{7}=\frac{8}{-x}\Rightarrow\frac{8}{56}=\frac{8}{-x}\)
\(\Rightarrow-x=56\)
\(\Rightarrow x=-56\)
câu b
\(\left(x-2\frac{1}{4}\right):\left(-\frac{5}{6}\right)=3\)
\(\Rightarrow x-2\frac{1}{4}=3.\left(-\frac{5}{6}\right)\)
\(\Rightarrow x-2\frac{1}{4}=\frac{-15}{6}\)
đến đây thực hiện tìm x dễ rồi
\(\frac{4}{7}\times x=\frac{1}{5}+\frac{2}{3}\)
\(\frac{4}{7}x=\frac{13}{15}\)
\(\Rightarrow x=\frac{91}{60}\)
các bài còn lại tương tự nha
mấy cái này dễ mà toán tìm x này là cơ bản!!
67865785685685785785774677567568568
\(\left|x+5\right|=5\)
<=> \(\hept{\begin{cases}x+5=5\\x+5=-5\end{cases}}\)
<=> \(\hept{\begin{cases}x=0\\x=-10\end{cases}}\)
\(\left|x+1\right|+7=10\)
<=> \(\left|x+1\right|=3\)
<=> \(\hept{\begin{cases}x+1=3\\x+1=-3\end{cases}}\)
<=> \(\hept{\begin{cases}x=2\\x=-4\end{cases}}\)
\(\left|x-3\right|-6=5\)
<=> \(\left|x-3\right|=11\)
<=> \(\hept{\begin{cases}x-3=11\\x-3=-11\end{cases}}\)
<=> \(\hept{\begin{cases}x=14\\x=-8\end{cases}}\)
\(\left|x+2\right|-6\left(x-4\right)=20-6x\)
<=> \(\left|x+2\right|-6x+24=20-6x\)
<=> \(\left|x+2\right|=-4\)
<=> \(\hept{\begin{cases}x+2=-4\\x+2=4\end{cases}}\)
<=> \(\hept{\begin{cases}x=-2\\x=2\end{cases}}\)
a) \(|x+5|=5\)
\(\Rightarrow\orbr{\begin{cases}x+5=5\\x+5=-5\end{cases}}\Rightarrow\orbr{\begin{cases}x=0\\x=-10\end{cases}}\)
Vậy x = 0 hoặc x = -10
b) \(|x+1|+7=10\)
\(\Rightarrow|x+1|=10-7\)
\(\Rightarrow|x+1|=3\)
\(\Rightarrow\orbr{\begin{cases}x+1=3\\x+1=-3\end{cases}}\Rightarrow\orbr{\begin{cases}x=2\\x=-4\end{cases}}\)
Vậy x = 2 hoặc x = -4
c) \(|x-3|-6=5\)
\(\Rightarrow|x-3|=5+6\)
\(\Rightarrow|x-3|=11\)
\(\Rightarrow\orbr{\begin{cases}x-3=11\\x-3=-11\end{cases}}\Rightarrow\orbr{\begin{cases}x=14\\x=-8\end{cases}}\)
Vậy x = 14 hoặc x = -8
d) \(|x+2|-6\left(x-4\right)=20-6x\)
\(\Rightarrow|x+2|-6x+24=20-6x\)
\(\Rightarrow|x+2|=20-6x-24+6x\)
\(\Rightarrow|x+2|=\left(20-24\right)+\left(-6x+6x\right)\)
\(\Rightarrow|x+2|=-4\)
Vì \(|x|\ge0\)mà \(|x+2|=-4\)
\(\Rightarrow\)Không có giá trị x thỏa mãn
_Chúc bạn học tốt_
a/ \(\frac{6}{7}x=\frac{18}{23}\)
\(x=\frac{18}{23}:\frac{6}{7}=\frac{21}{23}\)
b/ \(2\frac{1}{2}x=\frac{5}{6}\)
\(=>\frac{5}{2}x=\frac{5}{6}\)
\(x=\frac{5}{6}:\frac{5}{2}=\frac{1}{3}\)
c/\(x:2\frac{3}{4}=9\frac{5}{8}\)
\(x:\frac{11}{4}=\frac{77}{8}\)
\(x=\frac{77}{8}\cdot\frac{11}{4}=\frac{847}{32}\)
d/\(7\frac{1}{7}\cdot\frac{1}{7}\cdot x=22\frac{1}{8}\)
\(\frac{50}{49}x=\frac{177}{8}\)
\(x=\frac{177}{8}:\frac{50}{49}=\frac{8673}{400}\)
\(a,\frac{6}{7}.x=\frac{18}{23}\) \(\Rightarrow x=\frac{18}{23}:\frac{6}{7}=\frac{18}{23}.\frac{7}{6}=\frac{21}{23}\)
\(b,2\frac{1}{2}.x=\frac{5}{6}\Rightarrow\frac{5}{2}.x=\frac{5}{6}\Rightarrow x=\frac{5}{6}:\frac{5}{2}=\frac{5}{6}.\frac{2}{5}=\frac{1}{3}\)
\(c,x:2\frac{3}{4}=9\frac{5}{8}\Rightarrow x:\frac{11}{4}=\frac{77}{8}\Rightarrow x=\frac{77}{8}.\frac{11}{4}=\frac{847}{32}\)
\(d,7\frac{1}{7}.\frac{1}{7}.x=22\frac{1}{8}\Rightarrow\frac{50}{49}.x=\frac{177}{8}\Rightarrow x=\frac{177}{8}:\frac{50}{49}=\frac{177}{8}.\frac{49}{50}=\frac{8673}{400}\)
1. Ta có: \(\frac{3+x}{5+y}=\frac{3}{5}\Leftrightarrow\hept{\begin{cases}3+x=3k\\5+y=5k\end{cases}}\Leftrightarrow\hept{\begin{cases}x=3\left(k-1\right)\\y=5\left(k-1\right)\end{cases}}\)
\(\Rightarrow x+y=3\left(k-1\right)+5\left(k-1\right)=\left(3+5\right)\left(k-1\right)\)
\(\Rightarrow8\left(k-1\right)=16\)
\(\Leftrightarrow k-1=16\div8\)
\(\Leftrightarrow k-1=2\)
\(\Leftrightarrow k=2+1\)
\(\Leftrightarrow k=3\)
\(\Rightarrow\hept{\begin{cases}x=3.3-3=6\\y=5.3-5=10\end{cases}}\)
Vậy x = 6 và y = 10
Với \(\frac{3+x}{5+y}=\frac{3}{5}\Leftrightarrow x=3a;y=5a\left(1\right)\)
Ta có :
\(x+y=3a+5a\)
hay \(16=3a+5a\)
\(\Leftrightarrow16=8a\)
\(\Leftrightarrow a=2\left(2\right)\)
Thay ( 2 ) vào ( 1 ) . Ta có :
\(x=3.2;y=5.2\)
\(\Leftrightarrow x=6;y=10\)
Vậy x = 6; y=10
1) \(\frac{1}{7}=\frac{8}{-x}\Rightarrow-x=7\cdot8\)
\(-x=56\)
\(x=-56\)
5) \(\left(x-2\frac{1}{4}\right):\left(-\frac{5}{6}\right)=3\)
\(x-\frac{9}{4}=3\cdot\left(-\frac{5}{6}\right)\)
\(x-\frac{9}{4}=-\frac{5}{2}\)
\(x=-\frac{5}{2}+\frac{9}{4}\)
\(x=-\frac{1}{4}\)
6) \(-8\left(4\frac{1}{5}\cdot x+\frac{3}{10}\right)=4\frac{4}{9}\)
\(-8\left(\frac{21}{5}x+\frac{3}{10}\right)=\frac{40}{9}\)
\(\frac{21}{5}x+\frac{3}{10}=\frac{40}{9}:\left(-8\right)\)
\(\frac{21}{5}x+\frac{3}{10}=-\frac{5}{9}\)
\(\frac{21}{5}x=-\frac{5}{9}-\frac{3}{10}\)
\(\frac{21}{5}x=-\frac{77}{90}\)
\(x=-\frac{77}{90}:\frac{21}{5}\)
\(x=-\frac{11}{54}\)
x : (-7) . 4 = -5 . (-6)
x : -28 = 30
x = 30. ( -28)
x = -840
Vậy x=-840
_HT_
\(x:\left(-7\right)4=\left(-5\right)\left(-6\right)\)
\(x:\left(-7\right)=24:4\)
\(x:\left(-7\right)=6\)
\(x=6\left(-7\right)\)
\(x=\left(-42\right)\)
@Nghệ Mạt
#cua