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\(x^2-3x+2.\left(x-3\right)=0\)
\(x.\left(x-3\right)+2.\left(x-3\right)=0\)
\(\left(x-3\right).\left(x+2\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x=3\\x=-2\end{cases}}\)
\(x.\left(x-3\right)-3x+9=0\)
\(x.\left(x-3\right)-3.\left(x-3\right)=0\)
\(\left(x-3\right)^2=0=>x=3\)
a,\(x^2-3x+2\left(x-3\right)=0.\)
\(\Leftrightarrow x^2-3x+2x-6=0\)
\(\Leftrightarrow x^2+x-6=0\)
\(\Leftrightarrow\left(x^2-2x\right)+\left(3x-6\right)=0\)
\(\Leftrightarrow x\left(x-2\right)+3\left(x-2\right)=0\)
\(\Leftrightarrow\left(x-2\right)\left(x+3\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-2=0\\x+3=0\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=2\\x=-3\end{cases}}\)
\(\left(x-3\right).\left(x^2+3x+9\right)-x.\left(x+2\right).\left(x-2\right)=1\)
\(\Leftrightarrow x^3-3^3-x.\left(x^2-2^2\right)=1\)
\(\Leftrightarrow x^3-27-x^3+4x=1\)
\(\Leftrightarrow-27+4x=1\)
\(\Leftrightarrow4x=28\)
\(\Leftrightarrow x=28:4\)
\(\Leftrightarrow x=7\)
\(\left(x-3\right)\left(x^2+3x+9\right)-x\left(x+2\right)\left(x-2\right)=1\)
\(\Leftrightarrow x^3-27-x\left(x^2-4\right)=1\)
\(\Leftrightarrow x^3-27-x^3+4x=1\)
\(\Leftrightarrow4x=28\)
\(\Leftrightarrow x=7\)
\(\text{a , (x-3).(x^2+3x+9)+x(x+2).(2-x)=1 }\)
=(x3-33)+x(4-x2)=1
=x3-27+4x-x3=1
4x-27=1
4x=28
x=7
\(\text{b, (x+1)^3-(x-1)^3-6.(x-1)^2=-10}\)
=-0,5
a) \(\Rightarrow5x^2-15x=5x^2-x-10x+2-5\)
\(\Rightarrow5x^2-15x-5x^2+x+10x=2-5\)
\(\Rightarrow-4x=-3\)
\(\Rightarrow x=\frac{3}{4}\)
Vậy \(x=\frac{3}{4}\)
b) \(\Rightarrow x^2-4x-5x+20-x^2+2x-x+2=7\)
\(\Rightarrow x^2-4x-5x-x^2+2x-x=7-20-2\)
\(\Rightarrow-8x=-15\)
\(\Rightarrow x=\frac{15}{8}\)
Vậy \(x=\frac{15}{8}\)
c) \(\Rightarrow3x^2-6x-4x+8=3x^2-27x-3\)
\(\Rightarrow3x^2-6x-4x-3x^2+27x=-3-8\)
\(\Rightarrow17x=-11\)
\(\Rightarrow x=\frac{-11}{17}\)
Vậy \(x=\frac{-11}{17}\)
Chúc bạn học tốt.
(x - 3)(x2 + 3x + 9) + x(x + 2)(2 - x) = 1
<=> x3 - 33 + x.(22 - x2) = 1
<=> x3 - 27 + 4x - x3 = 1
<=> 4x - 27 = 1
<=> 4x = 28
<=> x = 7
Vậy x = 7.
\(=>x^3-3^3-x\left(x^2-4\right)=1\)
\(=>x^3-27-x^3+4x=1\)
\(=>4x-27=1\)
\(=>4x=28=>x=7\)
\(\left(x-3\right)\left(x^2+3x+9\right)-x.\left(x+2\right).\left(x-2\right)=1\)
\(x^3-3^3-x.\left(x^2-2^2\right)=1\)
\(x^3-27-x^3+4x=1\)
\(-27+4x=1\)
\(4x=28\)
\(x=7\)