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Áp dụng t/c dãy tỉ số bằng nhau, ta có:
\(\frac{2x+2}{5x-3}=\frac{2x+12}{5x+18}=\frac{\left(2x+12\right)-\left(2x+2\right)}{\left(5x+18\right)-\left(5x-3\right)}=\frac{10}{21}\)
Có: \(\frac{2x+2}{5x-3}=\frac{10}{21}\)
<=> 21(2x+2) = 10(5x-3)
<=> 42x+42 = 50x-30
<=> 8x = 72
<=> x = 9
\(\frac{2x+2}{5x-3}=\frac{2x+12}{5x+18}\)
\(\Rightarrow\left(2x+2\right)\left(5x+18\right)=\left(5x-3\right)\left(2x+12\right)\)
\(\Rightarrow2x\left(5x+18\right)+2\left(5x+18\right)=5x\left(2x+12\right)-3\left(2x+12\right)\)
\(\Rightarrow10x^2+36x+10x+36=10x^2+60x-6x-36\)
\(\Rightarrow46x+36=54x-36\)
\(\Rightarrow36+36=54x-46x\)
\(\Rightarrow72=8x\)
\(\Rightarrow x=9\)
tck cho to nha
2x(5x+18)+2(5x+18)=5x(2x+12)+3(3x-1)
10x^2+2x+10x+2=10x+-5x+9x-3
=> 10x^2+2x+10x-10x^2+5x-9x=-3-2
-2X=-5
x=5/2
x=5/2
a) Ta có: \(\frac{3x+2}{5x+7}=\frac{3x-1}{5x+1}\)
\(\Leftrightarrow\left(3x+2\right)\left(5x+1\right)=\left(5x+7\right)\left(3x-1\right)\)
\(\Leftrightarrow3x\left(5x+1\right)+2\left(5x+1\right)=5x\left(3x-1\right)+7\left(3x-1\right)\)
\(\Leftrightarrow15x^2+3x+10x+2=15x^2-5x+21x-7\)
\(\Leftrightarrow15x^2-15x^2+3x+10x+5x-21x=-7-2\)
\(\Leftrightarrow-3x=-9\)
\(\Leftrightarrow x=3\)
Vậy x = 3
b) Ta có: \(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}\Leftrightarrow\left(x+1\right)\left(x+3\right)=\left(2x+1\right)\left(0,5x+2\right)\)
\(\Leftrightarrow x\left(x+3\right)+\left(x+3\right)=2x\left(0,5x+2\right)+\left(0,5x+2\right)\)
\(\Leftrightarrow x^2+3x+x+3=x^2+4x+0,5x+2\)
\(\Leftrightarrow x^2-x^2+3x+x-4x-0,5x=2-3\)
\(\Leftrightarrow-0,5x=-1\Leftrightarrow x=2\)
Vậy x = 2
\(\frac{2x+2}{5x-3}=\frac{2x+12}{5x+18}\)
\(\Rightarrow\left(2x+2\right)\left(5x+18\right)=\left(2x+12\right)\left(5x-3\right)\)
\(\Rightarrow\left(2x+2\right)5x+\left(2x+2\right)18=\left(2x+12\right)5x-\left(2x+12\right)3\)
\(\Rightarrow10x^2+10x+36x+36=10x^2+60x-6x-36\)
\(\Rightarrow46x+36=54x-36\)
\(\Rightarrow54x-46x=36+36\)
\(\Rightarrow8x=72\)
\(\Rightarrow x=9\)
Vậy \(x=9\)
=> ( 2x+2).(5+18)= (2x+12). (5x-3)
=> (2x+2) . 23 = 2x. 5x - 2x.3 + 12.5x - 12.3
=> 2x. 23+ 2.23 = 10.x.x - 6x+ 60x - 36
=> 46x + 46 = 10x.x + 54 x -36
=> 46 + 36 = 10xx + 54x -46x
=> 82 = 10xx +8x
mỏi tay rùi tự lam nốt đi
\(4\left(18-5x\right)-12\left(3.7\right)=15\left(2x-16\right)-6\left(2+14\right)\)
\(\Leftrightarrow72-20x-252=30x-240-96\)
\(\Leftrightarrow-20x-180=30x-336\)
\(\Leftrightarrow-50x=-156\)
\(\Leftrightarrow x=3,12\)
#H
\(\frac{2x+2}{5x-3}=\frac{2x+12}{5x+18}\)
=> ( 2x + 2 ) ( 5x + 18 ) = ( 2x + 12 ) ( 5x - 3 )
=> 2x ( 5x + 18 ) + 2 ( 5x + 18 ) = 2x ( 5x - 3 ) + 12 ( 5x - 3 )
=> 10 x 2 + 36x + 10x + 36 = 10 x 2 - 6x + 60 x - 36
=> 36x + 10x + 6x - 60x = - 36 - 36
=> - 8 x = - 72
=> x = 9