Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a. \(\frac{1}{5}=0,2\)
\(\Rightarrow|x|=-0,2\)
b.\(\frac{x+9}{15}=\frac{3}{5}\)
\(\frac{9}{15}=\frac{3}{5}\Rightarrow\frac{x+9}{15}=\frac{9}{5}\)
\(\Rightarrow x=0\)
c. \(|x|=0,75=\frac{3}{4}\)
\(|x|=\frac{3}{4}\)
\(|x|=-0,75\)
d.\(\frac{x}{169}=\frac{10^4}{x}\)
\(\frac{x}{169}=\frac{10000}{x}\)
\(\Rightarrow x=-1300\)
0.5x - 2/3x = 7/12
<=> 1/2x - 2/3x = 7/12
<=> (1/2 - 2/3).x = 7/12
<=> -1/6.x = 7/12
<=> x = 7/12 : -1/6
<=> x = -7/2
Vậy x = -7/2
1/3 . x - 0,5 . x = 0,75
=> ( 1/3 - 0,5)x = 0,75
=> ( 1/3 -1/2)x =0,75
=> (-1/6)x = 0,75
=> x = 0,75 : (-1/6)
=> x = -9/2
Vậy x = -9/2
a) \(\frac{4}{3}x-1=\frac{x}{5}\)
=> \(\frac{4}{3}x-\frac{1}{5}x=1\)
=> \(\frac{17}{15}x=1\)
=> \(x=1:\frac{17}{15}=\frac{15}{17}\)
b) \(x+50\%=\frac{4\left(x+1\right)}{3}-\frac{1}{3}\)
=> \(x+\frac{1}{2}=\frac{4x+4-1}{3}\)
=> \(\frac{2x+1}{2}=\frac{4x+3}{3}\)
=> \(\left(2x+1\right).3=2.\left(4x+3\right)\)
=> \(6x+3=8x+6\)
=> \(6x-8x=6-3\)
=> \(-2x=3\)
=> \(x=3:\left(-2\right)=-\frac{3}{2}\)
\(a,\frac{4}{3}x-1=\frac{x}{5}\)
\(\Rightarrow\frac{4}{3}x=\frac{x}{5}+1\)
\(\Rightarrow\frac{4x}{3}=\frac{x+5}{5}\)
\(\Rightarrow20x=3x+15\)
\(\Rightarrow17x=15\)
\(\Rightarrow x=\frac{15}{17}\)
\(b,x+50\%=\frac{4\left(x+1\right)}{3}-\frac{1}{3}\)
\(\Rightarrow x+\frac{1}{2}=\frac{4x+4-1}{3}\)
\(\Rightarrow\frac{2x+1}{2}=\frac{4x+3}{3}\)
\(\Rightarrow3\left(2x+1\right)=\left(4x+3\right).2\)
\(\Rightarrow6x+3=8x+6\)
\(\Rightarrow2x=-3\)
\(\Rightarrow x=-\frac{3}{2}\)
\(c,-200\%.x+\frac{4}{3}=\frac{7}{4}\left(x+1\right)\)
\(\Rightarrow-2x+\frac{4}{3}=\frac{7}{4}x+\frac{7}{4}\)
\(\Rightarrow\frac{-6x+4}{3}=\frac{7x+7}{4}\)
\(\Rightarrow4\left(-6x+4\right)=\left(7x+7\right)3\)
\(\Rightarrow-24x+16=21x+21\)
\(\Rightarrow45x=-5\)
\(\Rightarrow x=-\frac{1}{7}\)
a) \(3x-\frac{1}{5}=\frac{4+x}{2}\)
=> \(\frac{15x-1}{5}=\frac{4+x}{2}\)
=> \(\left(15x-1\right).2=\left(4+x\right).5\)
=> \(30x-2=20+5x\)
=> \(30x-5x=20+2\)
=> \(25x=22\)
=> \(x=\frac{22}{25}\)
b) \(\frac{4}{3}x-1=\frac{4\left(x+1\right)}{3}-\frac{1}{3}\)
=> \(\frac{1}{3}x=\frac{4x+4-1}{3}\)
=> \(\frac{1}{3}x=\frac{4x+3}{3}\)
=> \(3x=3\left(4x+3\right)\)
=> \(3x=12x+9\)
=> \(3x-12x=9\)
=> \(-9x=9\)
=> \(x=9:\left(-9\right)=-1\)
\(\frac{1}{3}x-0,5x=0,75\)
\(\Leftrightarrow-\frac{1}{6}x=0,75\)
\(\Leftrightarrow\)\(x=-\frac{9}{2}\)
1/3x -0.5x = 0.75
(1/3 - 0.5)x = 0.75
-1/6x =0.75
x =0.75 : -1/6
x =-9/2
tk mình nha .thank bạn nhiều:))