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\(a,45-\left(30+x\right)=x-\left(37-8\right)\)
\(\Leftrightarrow45-30-x=x-37+8\)
\(\Leftrightarrow-x-x=-37+8-45+30\)
\(\Leftrightarrow-2x=-44\)
\(\Leftrightarrow x=22\)
\(b,\left(x-12\right)-15=\left(30-8\right)-\left(40+x\right)\)
\(\Leftrightarrow x-12-15=30-8-40-x\)
\(\Leftrightarrow x+x=30-8-40+12+15\)
\(\Leftrightarrow2x=9\)
\(\Leftrightarrow x=4,5\)
a/ -x + 8 = -17-30
-x + 8 = -47
-x = -47 - 8
-x = -55
x = 55
Vậy x = 55
b/ 35 – x = 37
x = 35 - 37
x = -2
Vậy x = -2
c/ (-19 – x) + 23 = -20
-19 – x = -20 - 23
-19 – x = -43
x = -19 - (-43)
x = 24
Vậy x = 24
d/ (x – 45) : 2 = -17
x – 45 = -17 * 2
x – 45 = -34
x = -34 + 45
x = 11
Vậy x = 11
a/ -x + 8 = -17-30
-x + 8 = -47
-x =-47 - 8
-x = -55
x = 55
Vậy x = 55
Phần a mình bị lỗi nên sửa lại nha
a) -x +8=-17-30
-x+8+17+30=0
-x+55=0
-x=-55
x=55
b) 35-x=37
x=-2
c)(-19-x)+23=-20
-19-x+23+20=0
24-x=0
x=24
d) ( x-45):2=-17
x-45=-34
x=11
a) -x + 8 = -17 - 30
-x + 8 = -47
-x = -47 - 8
-x = -55
=> x = 55
Vậy x = 55
b) 35 - x = 37
x = 35 - 37
x = -2
Vậy x = -2
c)( -19 - x) + 23 = -20
(-19 - x) = -20 - 23
-19 - x = -43
x = -19 - (-43)
x = 24
Vậy x - 24
d)(x - 45) : 2 = -17
x - 45 = -17 . 2
x - 45 = -34
x = -34 + 45
x = 11
Vậy x = 11
Bài 1:
a) \(24 - (-15) - 2\)
\(=39-2\)
\(=37\)
b) \((-85) + 10 - (-85) - 50\)
\(=[(-85)-(-85)]+10-50\)
\(=0+10-50\)
\(=10-50\)
\(=-40\)
c) \(71 - (-30) - (+18) + (-30)\)
\(=[(-30)-(-30)]+71-(+18)\)
\(=0+71-18\)
\(=71-18\)
\(=53\)
d) \(-(30) - (+37) + (+37) + (-85)\)
\(=[-(+37)+(+37)]-(30)+(-85)\)
\(=0-(30)+(-85)\)
\(=(-30)+(-85)\)
\(=-115\)
e) \((35-815) - (795-65)\)
\(=(-780)-730\)
\(=-1510\)
g) \((2002-79+15) + (-79+15)\)
\(=1938+(-64)\)
\(=1874\)
Bài 2:
a) \(25 - (30+x) = x - (27-8)\)
\(25-30-x=x-27+8\)
\(x+x=25-30+27-8\)
\(2x=14\)
\(x=14\div2\)
\(x=7\)
b) \((x-12) - 15 = (20-17) - (18+x) \)
\(x-12-15=13-18-x\)
\(x-27=-5-x\)
\(x+x=-5+27\)
\(2x=22\)
\(x=22\div2\)
\(x=11\)
c) \(15 - x = 7 - (-2)\)
\(15-x=9\)
\(x=15-9\)
\(x=6\)
d) \(x - 35 = (-12) - 3\)
\(x-35=-15\)
\(x=-15+35\)
\(x=20\)
e) \(\left|5-x\right|-26=-15\)
\(\left|5-x\right|=-15+26\)
\(\left|5-x\right|=11\)
Từ đây ta có:
*Nếu \(5-x=11\)
\(x=5-11\)
\(x=-6\)
*Nếu \(5-x=-11\)
\(x=5-(-11)\)
\(x=16\)
Vậy \(x=-6;x=16\)
a ) x − 28 : − 12 = − 5 x − 28 = − 5 . − 12 x − 28 = 6 0 x = 6 0 + 28 x = 88
b ) x + 15 : − 28 = 8 x + 15 = 8 . − 28 x + 15 = − 224 x = − 224 – 15 x = − 239
c ) x + 3 0 : − 45 = − 4 x + 3 0 = − 4 . − 45 x + 3 0 = 18 0 x = 18 0 – 3 0 x = 15 0
a. x - (17 - 8) = 5 + (10 - 3x)
=> x - 9 = 5 + 10 - 3x
=> x + 3x = 15 + 9
=> 4x = 24
=> x = 6
b. 25 - (30 + x) = x - (27 - 8)
=> 25 - 30 - x = x - 19
=> -x -x = -19 + 30 - 25
=> -2x = -14
=> x = 7
c. (x - 12) - 15 = (20 - 7) - (18 + x)
=> x - 12 - 15 = 13 - 18 - x
=> x + x = 13 - 18 + 12 + 15
=> 2x = 22
=> x = 11
\(x\left(x-2\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x-2=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x=2\end{cases}}\)
a) 45 - (30 + x) = x - (37 - 8)
<-> 45 - 30 - x = x - 37 + 8
<-> -x - x = -37 + 8 + 30 - 45
<-> -2x = -44
<-> x = 22
b) (x - 12) - 15 = (30 - 8) - (40 - x)
<-> x - 12 - 15 = 22 - 40 + x
<-> x - x = 22 - 40 + 15 + 12
<-> 0x = 9
=> vô nghiệm
=> x thuộc rỗng