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câu 1:23+3x=5mu3=125-23=102:3=34.the la xong.minh lam tat
a,5^x=125
=>5^x=5^3
=>x=3
b,3^2x=81
=>3^2x=3^4
=>2x=4
=>x=4:2=2
c,5^2x-3-2*5^2=5^2+3
5^2x-3-50=75
5^2x-3=75+50=125
5^2x-3=5^3
=>2x-3=3
=>2x=3+3=6
=>6:2=3
k cho mk nhé
\(a,125=5\cdot5\cdot5=5^3\Leftrightarrow x=3\)
\(b,81=3\cdot3\cdot3\cdot3=3^4\Leftrightarrow2x=4\Leftrightarrow x=4:2\Leftrightarrow x=2\)
\(c,5^{2x-3}-2\cdot5^2=5^2\cdot3\)
\(\Leftrightarrow5^{2x-3}=2\cdot5^2+5^2\cdot3\)
\(\Leftrightarrow5^{2x-3}=5^2\cdot\left(2+3\right)\)
\(\Leftrightarrow5^{2x-3}=5^2\cdot5\Leftrightarrow5^{2x-3}=5^3\)
\(\Leftrightarrow2x-3=3\Leftrightarrow2x=3+3\Leftrightarrow2x=6\Leftrightarrow x=6:2\Leftrightarrow x=3\)
a)\(\frac{\frac{51}{2}}{\frac{13}{2}}\)=\(\frac{51}{13}\)
b)\(-\frac{5}{\frac{15}{32}}:\frac{\frac{23}{52}}{\frac{8}{3}}=-\frac{13312}{207}\)
a) \(\left(2x+1\right)^3=125\)
\(\Rightarrow2x+1=5\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=2\)
Vậy \(x=2\)
b) \(1999^{2x-6}=1\)
\(\Rightarrow1999^{2x-1}=1999^0\)
\(\Rightarrow2x-1=0\)
\(\Rightarrow2x=1\)
\(\Rightarrow x=\frac{1}{2}\)
Vậy \(x=\frac{1}{2}\)
c) \(x^{2002}=x\)
\(\Rightarrow x^{2002}-x=0\)
\(\Rightarrow x.\left(x^{2001}-1\right)=0\)
\(\Rightarrow x=0\) hoặc \(x^{2001}-1=0\)
+) \(x=0\)
+) \(x^{2001}-1=0\Rightarrow x^{2001}=1\Rightarrow x=1\)
Vậy \(x\in\left\{0;1\right\}\)
d) \(\left(x-1\right)^2=9\)
\(\Rightarrow x-1=\pm3\)
+) \(x-1=3\Rightarrow x=4\)
+) \(x-1=-3\Rightarrow x=-2\)
Vậy \(x\in\left\{4;-2\right\}\)
e) \(\left(2x-3\right)^2=81\)
\(\Rightarrow2x-3=\pm9\)
+) \(2x-3=9\Rightarrow2x=12\Rightarrow x=6\)
+) \(2x-3=-9\Rightarrow2x=-6\Rightarrow x=-3\)
Vậy \(x\in\left\{6;-3\right\}\)
Các phần khác làm tương tự
a) (3x - 1)2 = 100
(3x - 1)2 = 102
=>3x - 1 = 10
=> 3x = 10 + 1
3x = 11
x = 11/3
3x+3 = 81 : 1
3x + 3 = 81
3x + 3 = 34
=> x + 3 = 4
=> x = 4 - 3
=> x = 1
(2x - 5)3 = 8
(2x - 5)3 = 23
=> 2x - 5 = 2
=> 2x = 2 + 5
=> 2x = 7
=> x = 7/2
a) 3x+3 =81
=> 3x+3 = 34
=> x+3=4
=> x=1
b) (2x-5)3=8
=> (2x-5)3= (+8)3
\(\Rightarrow\orbr{\begin{cases}2x+5=8\\2x+5=-8\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{3}{2}\\x=\frac{-13}{2}\end{cases}}}\)