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Làm này mới đúng chứ:
(3x-5)(x+1) - (x-1)(x+2)= (2x-3)(x+2) + 1
=> (3x-5)(x+1) = (2x-3)(x+2) + (x-1)(x+2) + 1
=> (3x - 4 - 1)(x + 1) = (x+2) [(2x-3) + (x-1)] + 1
=> (3x-4)(x+1) - x - 1 = (x+2).(3x-4) + 1
=> (3x-4)(x+1) - (x+2).(3x-4) = x + 1 + 1
=> (3x-4).[(x+1) - (x+2)] = x + 2
=> (3x-4).(-1) = x + 2
=> - 3x + 4 = x + 2
=> 3x + x = 4 + 2
=> 4x = 6
=> x = 6 : 4
=> x = 3/2
a)\(\left(x+1\right)\left(x+3\right)-x\left(x-2\right)=7\)
\(x\left(x+3\right)+x+3-x^2+2x=7\)
\(x^2+3x+x+3-x^2+2x=7\)
\(6x+3=7\)
\(6x=4\)
\(x=\frac{4}{6}=\frac{2}{3}\)
Vậy \(x=\frac{2}{3}\)
b) \(2x\left(3x+5\right)-x\left(6x-1\right)=33\)
\(6x^2+10x-6x^2-x=33\)
\(9x=33\)
\(x=\frac{33}{9}\)
Vậy \(x=\frac{33}{9}\)
a) (x-1)*(x+2)-(x-3)*(-x+4)=19
\(\Leftrightarrow x^2+2x-x-2-\left(-x^2+4x+3-12\right)=19\)
\(\Leftrightarrow x^2+2x-x-2+x^2-4x-3+12=19\)
\(\Leftrightarrow2x^2-3x+7-19=0\)
\(\Leftrightarrow2x^2-3x-12=0\)
Đề sai??
b) (2x -1)*(3x+5)-(6x-1)*(6x+1)=(-17)
\(\Leftrightarrow6x^2+10x-3x-5-\left(36x^2+6x-6x-1\right)=-17\)
\(\Leftrightarrow6x^2+10x-3x-5-36x^2-6x+6x+1=-17\)
\(\Leftrightarrow-30x^2+7x-4+17=0\)
\(\Leftrightarrow-30x^2+7x+13=0\)
???
Với x = 0
\(\Rightarrow A=\left(0-3\right)\left(0+7\right)-\left(2.0-5\right)\left(0-1\right)\)
\(A=\left(-3\right).7-\left(-5\right)\left(-1\right)\)
\(A=-21+5=-16\)
Với x = 1
\(\Rightarrow A=\left(1-3\right)\left(1+7\right)-\left(2.1-5\right)\left(1-1\right)\)
\(\Rightarrow A=-2.8=-16\)
Với x = -1
\(\Rightarrow A=\left(-1-3\right)\left(-1+7\right)-\left(2.-1-1\right)\)
\(\Rightarrow A=-4.6+3\)
\(\Rightarrow A=-21\)
Với \(x=0\)
\(\Rightarrow A=\left(0-3\right)\left(0+7\right)-\left(2.0-5\right)\left(0-1\right)\)
\(A=\left(-3\right).7-\left(-5\right)\left(-1\right)\)
\(A=-21+5=-16\)
Với \(x=1\)
\(\Rightarrow A=\left(1-3\right)\left(1+7\right)-\left(2.1-5\right)\left(1-1\right)\)
\(\Rightarrow A=-2.8=-16\)
Với \(x=-1\)
\(\Rightarrow A=\left(-1-3\right)\left(-1+7\right)-\left(2.-1-1\right)\)
\(\Rightarrow A=-4.6+3\)
\(\Rightarrow A=-21\)
a) 3x2 + 10x + 8
= 3x2 + 6x + 4x + 8
= 3x.(x + 2) + 4.(x + 2)
= (x + 2).(3x + 4)
b) 2x2 + x - 6
= 2x2 + 4x - 3x - 6
= 2x.(x + 2) - 3.(x + 2)
= (x + 2).(2x - 3)
a) \(\left(3x+4\right)\left(x+2\right)\)
b) \(\left(2x-3\right)\left(x+2\right)\)
3(x + 2) - 2(2x + 7) = x - 5
<=> 3.x + 3.2 + (-2).2x + (-2).7 = x - 5
<=> 3x + 6 - 4x - 14 = x - 5
<=> -x - 8 = x - 5
<=> -x - 8 - x = -5
<=> -2x - 8 = -5
<=> -2x = -5 + 8
<=> -2x = 3
<=> x = 3 : (-2)
<=> x = -3/2
=> x = -3/2