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7 tháng 6 2016

\(2-\left(\frac{37}{7}+x-3\right)x\frac{49}{11}=0\)

\(\left(\frac{37}{7}+x-3\right)x\frac{49}{11}=2\)

\(\frac{37}{7}+x-3=\frac{22}{49}\)

\(x=-\frac{90}{49}\)

7 tháng 6 2016

\(2-\left(\frac{37}{7}+x-3\right)\cdot\frac{49}{11}=0\)

\(\left(\frac{37}{7}+x-3\right)\cdot\frac{49}{11}=0+2\)

\(\left(\frac{37}{7}+x-3\right)\cdot\frac{49}{11}=2\)

\(\frac{37}{7}+x-3=2:\frac{49}{11}\)

\(\frac{37}{7}+x-3=\frac{22}{49}\)

\(\frac{37}{7}+x=\frac{22}{49}+3\)

\(\frac{37}{7}+x=\frac{169}{49}\)

\(x=\frac{169}{49}-\frac{37}{7}\)

\(x=-\frac{90}{49}\)

30 tháng 5 2018

(9/2-2xX):11/7=77/20

9/2-2xX=121/20

2xX=-31/20

X=-31/40

k mk nha mk đung đó 

30 tháng 5 2018

\(\left(\frac{9}{2}-2\times x\right):1\frac{4}{7}=\frac{11}{4}\times\frac{7}{5}\)

\(\left(\frac{9}{2}-2\times x\right):\frac{11}{7}=\frac{77}{20}\)

\(\frac{9}{2}-2\times x=\frac{77}{20}\times\frac{11}{7}\)

\(\frac{9}{2}-2\times x=\frac{121}{20}\)

\(2\times x=\frac{9}{2}-\frac{121}{20}\)

\(2x=\frac{-31}{20}\)

\(x=\frac{-31}{20}:2\)

\(x=\frac{-31}{40}\)

giúp mk xem lại đề chút nha! vì lớp 5 chưa học số âm!

11 tháng 6 2017

\(\left[\left(35\frac{5}{7}+2\frac{3}{4}\right)-5\frac{5}{7}+\frac{1}{4}\right]:\left(11+x\right)=3\)

\(\left[\left(35\frac{5}{7}-5\frac{5}{7}\right)+2\frac{3}{4}+\frac{1}{4}\right]:\left(11+x\right)=3\)

\(\left[30+3\right]:\left(11+x\right)=3\)

\(33:\left(11+x\right)=3\)
\(11+x=11\)

\(x=0\)

11 tháng 6 2017

\(\left[\left(35\frac{5}{7}+2\frac{3}{4}\right)-5\frac{5}{7}+\frac{1}{4}\right]\div\left(11+x\right)=3\)

\(\left[\left(\frac{35\times7+5}{7}+\frac{2\times4+3}{4}\right)-\frac{5\times7+5}{7}+\frac{1}{4}\right]\div\left(11+x\right)=3\)

\(\left[\left(\frac{250}{7}+\frac{11}{4}\right)-\frac{40}{7}+\frac{1}{4}\right]\div\left(11+x\right)=3\)

\(\left[\frac{1077}{28}-\frac{167}{28}\right]\div\left(11+x\right)=3\)

\(32,5\div\left(11+x\right)=3\)

\(11+x=32,5\div3\)

\(11+x=\frac{65}{6}\)

\(x=\frac{65}{6}-11=-\frac{1}{6}\)

19 tháng 6 2016

1/5x8 + 1/8x11 + 1/11x14 + ... + 1/xx(x+3) = 101/1540

1/3 x (3/5x8 + 3/8x11 + 3/11x14 + ... + 3/xx(x+3) = 101/1540

1/3 x (1/5 - 1/8 + 1/8 - 1/11 + 1/11 - 1/14 + ... + 1/x - 1/x+3) = 101/1540

1/3 x (1/5 - 1/x+3) = 101/1540

1/5 - 1/x+3 = 101/1540 : 1/3

1/5 - 1/x+3 = 303/1540

1/x+3 = 1/5 - 303/1540

1/x+3 = 1/308

=> x+3=308

=> x=308-3=305

vậy x=305

19 tháng 6 2016

1/5x8 + 1/8x11 + 1/11x14 + ... + 1/xx(x+3) = 101/1540

1/3 x (3/5x8 + 3/8x11 + 3/11x14 + ... + 3/xx(x+3) = 101/1540

1/3 x (1/5 - 1/8 + 1/8 - 1/11 + 1/11 - 1/14 + ... + 1/x - 1/x+3) = 101/1540

1/3 x (1/5 - 1/x+3) = 101/1540

1/5 - 1/x+3 = 101/1540 : 1/3

1/5 - 1/x+3 = 303/1540

1/x+3 = 1/5 - 303/1540

1/x+3 = 1/308

=> x+3=308

=> x=308-3=305

vậy x=305

26 tháng 4 2015

\(A=\left(1-\frac{1}{4}\right)x\left(1-\frac{1}{9}\right)x\left(1-\frac{1}{16}\right)x...x\left(1-\frac{1}{576}\right)x\left(1-\frac{1}{625}\right)\)
     \(=\frac{3}{4}.x.\frac{8}{9}.x.\frac{15}{16}.x...x.\frac{575}{576}.x.\frac{624}{625}\)
     \(=\left(\frac{3}{4}.\frac{8}{9}.\frac{15}{16}....\frac{575}{576}.\frac{624}{625}\right)x\)
     \(=\left(\frac{1.3}{2.2}.\frac{2.4}{3.3}.\frac{3.5}{4.4}....\frac{23.25}{24.24}.\frac{24.26}{25.25}\right)x\)
     \(=\left(\frac{1.2.3.....23.24}{2.3.4.....24.25}.\frac{3.4.5.....25.26}{2.3.4.....24.25}\right)x\)
     \(=\left(\frac{1}{25}.\frac{26}{2}\right)x\)
     \(=\left(\frac{1}{25}.\frac{13}{1}\right)x\)
     \(=\frac{13}{25}.x\)
Thiếu kết quả đúng không

17 tháng 3 2016

mk thấy :

P/S cuối cùng là P/S :624/625

625=25x25       

=>mẫu số=25

tử số là :

624/24/2=13

Vậy kết quả là :\(\frac{13}{25}\)

14 tháng 7 2015

1/2 . 1/3 . 1/4 . 1/5 . 1/6 . ( x - 1,010 ) = 1/360 - 1/720

1/2 . 1/3 . 1/4 . 1/5 . 1/6 . ( x - 1,010) = 1/720

( x - 1,010 ) . 1/2 . 1/3 . 1/4 . 1/5 . 1/6 = 1/720

( x - 1,010 ) . 1/720 = 1/720

x - 1,010 = 1/720 : 1/720

x - 1,010 = 1

          x  = 1 + 1,010

          x  = 2,01

13 tháng 7 2018

a) (1,5 . 1,9 - x - 0,5) : 0,25 = 7,5 : 0,125

=> (2,85 - x - 0,5) : 0,25 = 60

=> (2,85 - 0,5) - x = 60 . 0,25

=> 2,35 - x = 15

=> x = 2,35 - 15

=> x = -12,65

Vậy x = -12,65

b) \(1-\left(5\frac{2}{9}+x-7\frac{7}{18}\right)\div2\frac{1}{6}=0\)

\(\Rightarrow\left(5\frac{2}{9}-7\frac{7}{18}+x\right)\div2\frac{1}{6}=1-0\)

\(\Rightarrow\left(\frac{47}{9}-\frac{133}{18}+x\right)\div2\frac{1}{6}=1\)

\(\Rightarrow\frac{-13}{6}+x=2\frac{1}{6}\)

\(\Rightarrow x=2\frac{1}{6}-\frac{-13}{6}\)

\(\Rightarrow x=\frac{13}{6}+\frac{13}{6}\)

\(\Rightarrow x=\frac{26}{6}\)

\(\Rightarrow x=\frac{13}{3}\)

Vậy \(x=\frac{13}{3}\)

c) \(35\left(2\frac{1}{5}-x\right)=32\)

\(\Rightarrow2\frac{1}{5}-x=32\div35\)

\(\Rightarrow\frac{11}{5}-x=\frac{32}{35}\)

\(\Rightarrow x=\frac{11}{5}-\frac{32}{35}\)

\(\Rightarrow x=\frac{9}{7}\)

Vậy \(x=\frac{9}{7}\)

d) \(\frac{4}{3}+\left(x\div2\frac{2}{3}-0,5\right).1\frac{35}{55}=0,6\)

\(\Rightarrow\left(x\div\frac{8}{3}-\frac{1}{2}\right).\frac{18}{11}=\frac{3}{5}-\frac{4}{3}\)

\(\Rightarrow\left(x\div\frac{8}{3}-\frac{1}{2}\right).\frac{18}{11}=\frac{-11}{15}\)

\(\Rightarrow x\div\frac{8}{3}-\frac{1}{2}=\frac{-11}{15}\div\frac{18}{11}\)

\(\Rightarrow x\div\frac{8}{3}-\frac{1}{2}=\frac{-121}{270}\)

\(\Rightarrow x\div\frac{8}{3}=\frac{-121}{270}+\frac{1}{2}\)

\(\Rightarrow x\div\frac{8}{3}=\frac{7}{135}\)

\(\Rightarrow x=\frac{7}{135}.\frac{8}{3}\)

\(\Rightarrow x=\frac{56}{405}\)

Vậy \(x=\frac{56}{405}\)

e) \(1\frac{1}{3}.2\frac{2}{4}\div\frac{5}{6}.1\frac{1}{11}=11-5\div x\)

\(\Rightarrow\frac{4}{3}.\frac{5}{2}\div\frac{5}{6}.\frac{12}{11}=11-5\div x\)

\(\Rightarrow\frac{10}{3}\div\frac{5}{6}.\frac{12}{11}=11-5\div x\)

\(\Rightarrow4.\frac{12}{11}=11-5\div x\)

\(\Rightarrow11-5\div x=\frac{48}{11}\)

\(\Rightarrow5\div x=11-\frac{48}{11}\)

\(\Rightarrow5\div x=\frac{73}{11}\)

\(\Rightarrow x=5\div\frac{73}{11}\)

\(\Rightarrow x=\frac{55}{73}\)

Vậy \(x=\frac{55}{73}\)

a) (1,5 * 1,9 - x - 0,5) : 0,25 = 7,5 : 0,125

(2,85 - x - 0,5) : 0,25 = 60

(2,85 - x - 0,5) = 60 x 0,25

(2,85 - x - 0,5) = 15

2,35 - x = 15

x = 2,35 - 15

x = -12,65