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a)X + 18,7= 50, 5 :2,5
X +\(\frac{187}{10}\)=\(\frac{505}{10}\):\(\frac{25}{10}\)
X + \(\frac{187}{10}\)=\(\frac{101}{2}:\frac{5}{2}\)
\(X+\frac{187}{10}=\frac{101}{2}\times\frac{2}{5}\)
\(X+\frac{187}{10}=\frac{101}{5}\)
\(X=\frac{101}{5}-\frac{187}{10}\)
\(X=\frac{202}{10}-\frac{187}{10}\)
\(X=\frac{15}{10}\)
\(X=\frac{3}{2}\)
4.(x - 2) + 3.(x - 1) = 2.x + 4
=> (4x - 8) + (3x - 3) =2x + 4
=> 4x - 8 + 3x - 3 = 2x + 4
=> 7x - 11 = 2x + 4
=> 7x - 2x = 4 + 11
=> 5x = 15
=> x = 15 : 5
=> x = 3
4.(x-2)+3.(x-1)=2.x+4
<=>4x-8+3x-1=2x+4
<=>4x+3x-2x=4+8+1
<=>5x=13
<=>x=\(\frac{13}{5}\)
vậy x=\(\frac{13}{5}\)
ủng hộ nha
Câu 6: Khôg có cau nào đúng
Câu 7: C
Câu 8: B
Câu 9: B
Câu 10: D
(x - 4)2 = (x - 4)4
<=> (x - 4)2 - (x - 4)4 = 0
<=> (x - 4)2 [ 1 - (x - 4)2 ] = 0
<=> \(\orbr{\begin{cases}\left(x-4\right)^2=0\\1-\left(x-4\right)^2=0\end{cases}\Leftrightarrow}\orbr{\begin{cases}x-4=0\\\left(x-4\right)^2=1\end{cases}\Leftrightarrow\orbr{\begin{cases}x-4=0\\\left(x-4\right)^2=1\end{cases}}}\)
Giải (x - 4)2 = 1
TH1: x - 4 = -1
<=> x = 3
TH2: x - 4 = 1
<=> x = 5
\(\left(x-4\right)^2=\left(x-4\right)^4\)
\(\Rightarrow\left(x-4\right)^2-\left(x-4\right)^4=0\)
\(\Rightarrow\left(x-4\right)^2-\left(x-4\right)^2.\left(x-4\right)^2=0\)
\(\Rightarrow\left(x-4\right)^2.\left[1-\left(x-4\right)^2\right]=0\)
TH 1 : \(\left(x-4\right)^2=0\Rightarrow x-4=0\Rightarrow x=4\)
TH 2 : \(1-\left(x-4\right)^2=0\Rightarrow\left(x-4\right)^2=1\Rightarrow\orbr{\begin{cases}x-4=1\\x-4=-1\end{cases}}\Rightarrow\orbr{\begin{cases}x=5\\x=3\end{cases}}\)
Vậy x = 3; x = 4 hoặc x = 5
\(2-\left(-x+4\right)=\left(-2\right)\left(-3\right)+4\)
\(2-\left(-x+4\right)=10\)
\(-x+4=2-10\)
\(-x+4=-8\)
\(-x=-8-4\)
\(-x=-12\)
\(=>x=12\)
\(x.4-x:4-24,7=190,48:2\)
\(x.4-x.\frac{1}{4}-24.7=95.24\)
\(x.\left(4-\frac{1}{4}\right)-24,7=95,24\)
\(x.\frac{15}{4}=95,24+24,7\)
\(x.\frac{15}{4}=119,94\)
\(x=119,94:\frac{15}{4}\)
\(x=31,984\)
Vậy \(x=31,984\)
Giải
X.4-X:4-24,7=190,48:2
X.4-X.1/4-24,7=95,24
X.(4-1/4)=95,24+24,7
X.15/4=119,94
X=119,94:15/4
X=31,984
Vậy X=31,984