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Ta có: \(\frac{73-x}{98-x}=\frac{1}{6}\)
\(\Rightarrow6\left(73-x\right)=98-x\)
\(\Rightarrow438-6x=98-x\)
\(\Rightarrow438-98=-x+6x\)
\(\Rightarrow340=5x\)
\(\Rightarrow x=340:5=68\)
\(\frac{73-x}{98-x}=\frac{1}{6}\)
=> \(6\left(73-x\right)=98-x\)
=> \(438-6x=98-x\)
\(\Leftrightarrow-6x+x=98-438\)
\(\Leftrightarrow-5x=-340\)
\(\Leftrightarrow x=68\)
Câu hỏi của Nguyễn Thị My Na - Toán lớp 6 - Học toán với OnlineMath bạn tham khảo tại đây nha
\(\frac{x}{6}-\frac{1}{y}=\frac{1}{2}\)
\(\Rightarrow\frac{x}{6}=\frac{1}{y}+\frac{1}{2}\)
\(\Rightarrow\frac{x}{6}=\frac{2+y}{2y}\)
\(6=2y\Rightarrow y=3\)
\(x=2+3\Rightarrow x=5\)
Giải:
Theo bài ra ta có:
\(\frac{-5}{6}+\frac{8}{3}+\frac{29}{-6}\le x\le\frac{-1}{2}+2+\frac{5}{12}\)
\(\Rightarrow-3\le x\le\frac{23}{12}\)
\(\Rightarrow x\varepsilon\left\{-2;-1;0;1\right\}\)
\(\frac{-5}{6}+\frac{16}{6}+-\frac{29}{6}\le x\le\frac{-6}{12}+\frac{24}{12}+\frac{5}{12}\)
=>-3\(\le\) x\(\le\) 23/12
=> x thuộc{-2-1;0;1}
a) \(\frac{x}{3}-\frac{10}{21}=-\frac{1}{7}\)
\(\Rightarrow\frac{x}{3}=-\frac{1}{7}+\frac{10}{21}\)
\(\Rightarrow\frac{x}{3}=\frac{7}{21}\)
\(\Rightarrow\frac{x}{3}=\frac{1}{3}\)
\(\Rightarrow x=1\)
\(x-25\%=\frac{1}{2}\)
\(\Rightarrow x-\frac{1}{4}=\frac{1}{2}\)
\(\Rightarrow x=\frac{1}{2}+\frac{1}{4}\)
\(\Rightarrow x=\frac{3}{4}\)
c) \(-\frac{5}{6}+\frac{8}{3}+-\frac{29}{6}\le x\le-\frac{1}{2}+2+\frac{5}{2}\)
\(\Rightarrow-3\le x\le4\)
\(\Rightarrow x\in\left\{-3;-2;-1;0;1;2;3;4\right\}\)
\(x-0,27=\frac{\frac{73}{77}+\frac{73}{165}+\frac{73}{285}}{25.\left(\frac{5}{84}+\frac{3}{180}+\frac{4}{285}\right)}\)
\(x-\frac{27}{100}=\frac{73.\left(\frac{1}{77}+\frac{1}{165}+\frac{1}{285}\right)}{25.4.\left(\frac{5}{4.84}+\frac{3}{4.180}+\frac{4}{4.285}\right)}\)
\(x-\frac{27}{100}=\frac{73.\left(\frac{2}{105}+\frac{1}{285}\right)}{100.\left(\frac{5}{336}+\frac{1}{240}+\frac{1}{285}\right)}\)
\(x-\frac{27}{100}=\frac{73.\left(\frac{2}{105}+\frac{1}{285}\right)}{100.\left(\frac{2}{105}+\frac{1}{285}\right)}\)
\(x-\frac{27}{100}=\frac{73}{100}\)
\(x=\frac{73}{100}+\frac{27}{100}\)
\(x=1\)
Vậy x=1
Ko viết lại đề bài nha
=> (73 - x) . 6 = (98 - x) . 1
438 - 6x = 98 - 1x
-6x + 1x = 98 - 438
-5x = - 340
x = 68
\(\frac{73-x}{98-x}=\frac{1}{6}\)
\(\Rightarrow\left(73-x\right).6=1.\left(98-x\right)\)
\(\Rightarrow\left(73-x\right).6=98-x\)
\(\Rightarrow73+x.6=98-x\)