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\(a)\frac{7}{3}-\frac{4}{3}\times x=\frac{5}{6}\)
\(-\frac{4}{3}\times x=\frac{3}{2}\)
\(x=\frac{-9}{8}\)
\(b)\frac{7}{4}-\frac{3}{4}\times x=\frac{5}{6}\)
\(-\frac{3}{4}\times x=\frac{11}{12}\)
\(x=-\frac{11}{9}\)
Bài 7:
a, \(x\) = \(\dfrac{1}{5}\) + \(\dfrac{2}{11}\)
\(x\) = \(\dfrac{11}{55}\) + \(\dfrac{10}{55}\)
\(x=\dfrac{21}{55}\)
b, \(\dfrac{x}{15}\) = \(\dfrac{3}{5}\) - \(\dfrac{2}{3}\)
\(\dfrac{x}{15}\) = \(\dfrac{9}{15}\) - \(\dfrac{10}{15}\)
\(\dfrac{x}{15}\) = \(\dfrac{1}{15}\)
\(x\) = 1
c, \(\dfrac{11}{8}\) + \(\dfrac{13}{6}\)= \(\dfrac{85}{x}\)
\(\dfrac{33}{24}\) + \(\dfrac{52}{24}\) = \(\dfrac{85}{x}\)
\(\dfrac{85}{24}\) = \(\dfrac{85}{x}\)
24 = \(x\)
Ta có :
a, ( 3 . x - 2^4 ) . 7^3 = 2 . 7^4 .
=> 3x - 16 = 2 . 7^4 : 7^3 .
=> 3x - 16 = 2 . 7 .
=> 3x = 2 . 7 + 16 .
=> 3x = 30 .
=> x = 30 : 3 .
=> x = 10 .
b, [ ( 6x - 72 ) : 2 - 84 ] . 28 = 5628 .
=> ( 6x -72 ) : 2 - 84 = 5628 : 28 .
=> ( 6x - 72 ) : 2 - 84 = 201 .
=> ( 6x - 72 ) : 2 = 201 + 84 .
=> ( 6x - 72 ) : 2 = 285 .
=> 6x - 72 = 285 . 2
=> 6x - 72 = 570 .
=> 6x = 570 + 72 .
=> 6x = 642 .
=> x = 642 : 6
=> x = 107 .
Vậy x = 107 .
Giải :
Ta có : \(\hept{\begin{cases}\frac{x-6}{y-7}=\frac{6}{7}\\x-y=-4\end{cases}}\)
Vì \(x-y=-4\)nên \(-4+y=x\)
\(\frac{x-6}{y-7}=\frac{6}{7}\)
\(\Leftrightarrow\frac{-4+y-6}{y-7}=\frac{6}{7}\)
\(\Leftrightarrow\frac{-10+y}{y-7}=\frac{6}{7}\)
\(\Leftrightarrow\left(-10+y\right).7=\left(y-7\right).6\)
\(\Rightarrow\left(-70\right)+7y=6y-42\)
\(\Rightarrow-6y+7y=70-42\)
\(\Rightarrow y=28\)
\(\Rightarrow x=28+\left(-4\right)=24\)
Vậy ...
\(\frac{x-6}{y-7}\)= \(\frac{6}{7}\)\(\Rightarrow7\left(x-6\right)=6\left(y-7\right)\)\(\Rightarrow7x-42=6y-42\)\(\Rightarrow7x-42-6y+42=0\)\(\Rightarrow7x-6y=0\)\(\Rightarrow7x=6y\)\(\Rightarrow\frac{x}{6}\)\(=\frac{y}{7}\)
áp dụng tính chất của dãy tỉ số bằng nhau ta có:
\(\frac{x}{6}\)= \(\frac{y}{7}\)= \(\frac{x-y}{6-7}\)= \(\frac{-4}{-1}\)\(=4\)
\(\Rightarrow\frac{x}{6}\)\(=4\)\(\Rightarrow x=24\)
\(\Rightarrow\frac{y}{7}\)\(=4\)\(\Rightarrow y=28\)
Chúc bạn học tốt!
a,\(\frac{1}{3}x=-2-\frac{2}{3}=\frac{-8}{3}\)
\(x=\frac{-8}{3}:\frac{1}{3}=\frac{-8}{3}.\frac{3}{1}=-8\)
\(b,\left[x+\frac{1}{1}\right]^2+\frac{5}{6}=\frac{7}{8}\)
\(\Rightarrow\left[x+1\right]^2=\frac{7}{8}-\frac{5}{6}\)
\(\Rightarrow\left[x+1\right]^2=\frac{7\cdot3}{24}-\frac{5\cdot4}{24}\)
\(\Rightarrow\left[x+1\right]^2=\frac{21}{24}-\frac{20}{24}\)
\(\Rightarrow\left[x+1\right]^2=\frac{1}{24}\)
\(\Rightarrow x\in\left\{\varnothing\right\}\)
4-(7-x)=x-(13-4)
4-(7-x)=x- 9
4-7+x = x-9
-3+x = x -9
không có số x nào thoả mãn đề bài
4-(7-x)=x-(13-4)
4-7+x=x-13+4
-3+x=x-9
x-x=-9+3
đề bài này sao sao á
7 . x - ( 6 . x + 5 ) = 17
7x - 6x - 5 = 17
x - 5 = 17
x = 22
hok tốt
..................
7x - (6x+5) = 17
7x - 6x - 5 = 17
x - 5 = 17
x = 22