Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(2\left(|x-1|+x-\frac{4}{5}\right)=2x-\frac{2}{5}\)
\(TH1:x\ge1\Rightarrow|x-1|=x-1\)
\(\Rightarrow2\left(x-1+x-\frac{4}{5}\right)=2x-\frac{2}{5}\)
\(\Rightarrow2\left(2x-\frac{9}{5}\right)=2x-\frac{2}{5}\Rightarrow4x-\frac{18}{5}=2x-\frac{2}{5}\)
\(\Rightarrow4x-2x=\frac{18}{5}-\frac{2}{5}\Rightarrow2x=\frac{16}{5}\Rightarrow x=\frac{16}{5}:2=\frac{16}{10}=\frac{8}{5}\)
\(TH2:x< 1\Rightarrow|x-1|=-x+1\)
\(\Rightarrow2\left(-x+1+x-\frac{4}{5}\right)=2x-\frac{2}{5}\)
\(\Rightarrow2\left(1-\frac{4}{5}\right)=2x-\frac{2}{5}\Rightarrow2\cdot\frac{1}{5}=2x-\frac{2}{5}\)
\(\Rightarrow2x-\frac{2}{5}=\frac{2}{5}\Rightarrow2x=\frac{2}{5}+\frac{2}{5}=\frac{4}{5}\Rightarrow x=\frac{4}{5}:2=\frac{4}{10}=\frac{2}{5}\)
TA CÓ \(\left(2X-3\right)^2-4.\left(X+1\right)^2=5\)
=>\(\left(2X-3\right)^2-\left(4X+4\right)^2=5\)
=>\(\left(2X-3\right)^2=5;\left(4X+4\right)^2=5\)
=>\(\orbr{\begin{cases}2X-3=5\\4X+4=5\end{cases}}\) =>\(\orbr{\begin{cases}2X=8\\4X=1\end{cases}}\) =>\(\orbr{\begin{cases}X=4\\X=\frac{1}{4}\end{cases}}\)
ta có 5^x+5^x*25=650 suy ra 5^x *26=650 ,5^x=25 suy ra x=2
Mk giúp phần đầu nhé!
Có 5x+5x+2=650
=> 5x.(1+52)=650
5x. 26=650
5x=650:26
5x=25
=> x=2
Ta có :
\(4-\left|x-\frac{1}{5}\right|=-\frac{1}{2}\)
\(\Leftrightarrow\)\(\left|x-\frac{1}{5}\right|=4-\left(-\frac{1}{2}\right)\)
\(\Leftrightarrow\)\(\left|x-\frac{1}{5}\right|=\frac{9}{2}\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x-\frac{1}{5}=\frac{9}{2}\\x-\frac{1}{5}=-\frac{9}{2}\end{cases}}\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x=\frac{9}{2}+\frac{1}{5}\\x=-\frac{9}{2}+\frac{1}{5}\end{cases}}\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x=\frac{43}{10}\\x=-\frac{43}{10}\end{cases}}\)
Vậy \(x=\frac{43}{10}\) hoặc \(x=-\frac{43}{10}\)
Ta có: \(4-\left|x-\frac{1}{5}\right|=\frac{-1}{2}\)
\(\Rightarrow\left|x-\frac{1}{5}\right|=4-\frac{-1}{2}\)
\(\Rightarrow\left|x-\frac{1}{5}\right|=\frac{9}{2}\)
\(\Rightarrow x-\frac{1}{5}=\pm\frac{9}{2}\)
Nếu \(x-\frac{1}{5}=\frac{9}{2}\Rightarrow x=\frac{9}{2}+\frac{1}{5}=\frac{47}{10}\)
Nếu \(x-\frac{1}{5}=\frac{-9}{2}\Rightarrow x=\frac{-9}{2}+\frac{1}{5}=\frac{-43}{10}\)
Vậy \(x=\left\{\frac{47}{10};\frac{-43}{10}\right\}\)
Chúc bạn năm mới vui vẻ!